Key generating program in Python












1












$begingroup$


I am about two months into programming with Python (no previous experience) and I tried to write a program which would generate a key and assign it to a student.



import random
import string


code_list =
students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
"Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
"Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
"Matic", "Marija", "Žiga T."]

#It generates the code and puts it in a list
size = 6
code = string.ascii_uppercase + string.digits
for i in range(24):
code_list.append(str(''.join(random.choice(code) for _ in range(size))))

#Combines the two lists (students and codes) into one
students_plus_codes = [x + str(" - " + y) for y in students for x in
code_list]

#It prints only every 25th element from the combined list
new = [x for i, x in enumerate(students_plus_codes) if i % 25 == 0]

for i in new:
print(i)`


My problem is that this code is not very elegant and just want to ask how I could write it more efficiently (especially the last part where I have to manually print out every 25th element of a list because every key gets assigned to every student).










share|improve this question









New contributor




urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$

















    1












    $begingroup$


    I am about two months into programming with Python (no previous experience) and I tried to write a program which would generate a key and assign it to a student.



    import random
    import string


    code_list =
    students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
    "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
    "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
    "Matic", "Marija", "Žiga T."]

    #It generates the code and puts it in a list
    size = 6
    code = string.ascii_uppercase + string.digits
    for i in range(24):
    code_list.append(str(''.join(random.choice(code) for _ in range(size))))

    #Combines the two lists (students and codes) into one
    students_plus_codes = [x + str(" - " + y) for y in students for x in
    code_list]

    #It prints only every 25th element from the combined list
    new = [x for i, x in enumerate(students_plus_codes) if i % 25 == 0]

    for i in new:
    print(i)`


    My problem is that this code is not very elegant and just want to ask how I could write it more efficiently (especially the last part where I have to manually print out every 25th element of a list because every key gets assigned to every student).










    share|improve this question









    New contributor




    urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1





      $begingroup$


      I am about two months into programming with Python (no previous experience) and I tried to write a program which would generate a key and assign it to a student.



      import random
      import string


      code_list =
      students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
      "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
      "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
      "Matic", "Marija", "Žiga T."]

      #It generates the code and puts it in a list
      size = 6
      code = string.ascii_uppercase + string.digits
      for i in range(24):
      code_list.append(str(''.join(random.choice(code) for _ in range(size))))

      #Combines the two lists (students and codes) into one
      students_plus_codes = [x + str(" - " + y) for y in students for x in
      code_list]

      #It prints only every 25th element from the combined list
      new = [x for i, x in enumerate(students_plus_codes) if i % 25 == 0]

      for i in new:
      print(i)`


      My problem is that this code is not very elegant and just want to ask how I could write it more efficiently (especially the last part where I have to manually print out every 25th element of a list because every key gets assigned to every student).










      share|improve this question









      New contributor




      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I am about two months into programming with Python (no previous experience) and I tried to write a program which would generate a key and assign it to a student.



      import random
      import string


      code_list =
      students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
      "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
      "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
      "Matic", "Marija", "Žiga T."]

      #It generates the code and puts it in a list
      size = 6
      code = string.ascii_uppercase + string.digits
      for i in range(24):
      code_list.append(str(''.join(random.choice(code) for _ in range(size))))

      #Combines the two lists (students and codes) into one
      students_plus_codes = [x + str(" - " + y) for y in students for x in
      code_list]

      #It prints only every 25th element from the combined list
      new = [x for i, x in enumerate(students_plus_codes) if i % 25 == 0]

      for i in new:
      print(i)`


      My problem is that this code is not very elegant and just want to ask how I could write it more efficiently (especially the last part where I have to manually print out every 25th element of a list because every key gets assigned to every student).







      python






      share|improve this question









      New contributor




      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 6 mins ago









      Jamal

      30.3k11116227




      30.3k11116227






      New contributor




      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 1 hour ago









      urban pečolerurban pečoler

      62




      62




      New contributor




      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      urban pečoler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes


















          0












          $begingroup$

          The reason that you are getting so many more entries is because this list comprehension:



           students_plus_codes = [x + str(" - " + y) for y in students for x in code_list]


          It's a nested for loop. If we expand it we can see what is happening:



          students_plus_codes = 
          for y in students: # students has 24 items
          for x in code_list: # code_list has 24 items
          students_plus_codes(x + str(" - " + y))


          So for every iteration of students you do 24 iterations of code_list.



          Fortunately, python has a builtin function called zip that will merge lists for us. So we can replace the nested list comprehension with this line:



          students_plus_codes = list(zip(students, code_list))


          Which results in a list of tuples:



          [('Aljoša', '256D2B'), ('Blažka', 'OEGJL9'), ('Nana', 'GB1PJL'), ('Kaja', 'F0P0F2'), 
          ('Alja', '62KU94'), ... ('Matic', 'E7CJIP'), ('Marija', '1D2UCL'), ('Žiga T.', '6X1DD5')]


          Generating the codes:



          First, I would replace for i in range(24): with for i in range(len(students)): as this allows you to change the number of students without having change other aspects of your code. In this instance 24 is a magic number that could cause issues down the line.



          You could even create a function that generates the the code, then you can use an easy to read list comprehension.



          # <=python3.5
          def generate_code(n, characters):
          return ''.join([random.choice(characters) for _ in range(n)])

          # >=python3.6
          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          Printing the codes:



          It isn't ideal to join the names and codes a single string as this makes it hard to use them separately later. For this reason, I used a list of tuples to match them as pairs. To print them the for loop has two variables, student and code that takes advantage of unpacking and then prints them using the format function.



          Instead of joining the students names with the codes for printing is not an ideal thing to do as it makes it harder to use the names and codes separately later.





          Altogether:



          import random
          import string


          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
          "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
          "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
          "Matic", "Marija", "Žiga T."]

          # It generates the code and puts it in a list
          size = 6
          chars = string.ascii_uppercase + string.digits
          code_list = [create_code(size, chars) for _ in range(len(students))]

          # Combines the two lists (students and codes) into a list of tuples
          students_plus_codes = list(zip(students, code_list))

          for student, code in students_plus_codes:
          print('{} - {}'.format(code, student))





          share|improve this answer








          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thank you, this was really helpful, I would never figure it out on my own :D
            $endgroup$
            – urban pečoler
            9 mins ago











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "196"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });






          urban pečoler is a new contributor. Be nice, and check out our Code of Conduct.










          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f212338%2fkey-generating-program-in-python%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          The reason that you are getting so many more entries is because this list comprehension:



           students_plus_codes = [x + str(" - " + y) for y in students for x in code_list]


          It's a nested for loop. If we expand it we can see what is happening:



          students_plus_codes = 
          for y in students: # students has 24 items
          for x in code_list: # code_list has 24 items
          students_plus_codes(x + str(" - " + y))


          So for every iteration of students you do 24 iterations of code_list.



          Fortunately, python has a builtin function called zip that will merge lists for us. So we can replace the nested list comprehension with this line:



          students_plus_codes = list(zip(students, code_list))


          Which results in a list of tuples:



          [('Aljoša', '256D2B'), ('Blažka', 'OEGJL9'), ('Nana', 'GB1PJL'), ('Kaja', 'F0P0F2'), 
          ('Alja', '62KU94'), ... ('Matic', 'E7CJIP'), ('Marija', '1D2UCL'), ('Žiga T.', '6X1DD5')]


          Generating the codes:



          First, I would replace for i in range(24): with for i in range(len(students)): as this allows you to change the number of students without having change other aspects of your code. In this instance 24 is a magic number that could cause issues down the line.



          You could even create a function that generates the the code, then you can use an easy to read list comprehension.



          # <=python3.5
          def generate_code(n, characters):
          return ''.join([random.choice(characters) for _ in range(n)])

          # >=python3.6
          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          Printing the codes:



          It isn't ideal to join the names and codes a single string as this makes it hard to use them separately later. For this reason, I used a list of tuples to match them as pairs. To print them the for loop has two variables, student and code that takes advantage of unpacking and then prints them using the format function.



          Instead of joining the students names with the codes for printing is not an ideal thing to do as it makes it harder to use the names and codes separately later.





          Altogether:



          import random
          import string


          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
          "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
          "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
          "Matic", "Marija", "Žiga T."]

          # It generates the code and puts it in a list
          size = 6
          chars = string.ascii_uppercase + string.digits
          code_list = [create_code(size, chars) for _ in range(len(students))]

          # Combines the two lists (students and codes) into a list of tuples
          students_plus_codes = list(zip(students, code_list))

          for student, code in students_plus_codes:
          print('{} - {}'.format(code, student))





          share|improve this answer








          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thank you, this was really helpful, I would never figure it out on my own :D
            $endgroup$
            – urban pečoler
            9 mins ago
















          0












          $begingroup$

          The reason that you are getting so many more entries is because this list comprehension:



           students_plus_codes = [x + str(" - " + y) for y in students for x in code_list]


          It's a nested for loop. If we expand it we can see what is happening:



          students_plus_codes = 
          for y in students: # students has 24 items
          for x in code_list: # code_list has 24 items
          students_plus_codes(x + str(" - " + y))


          So for every iteration of students you do 24 iterations of code_list.



          Fortunately, python has a builtin function called zip that will merge lists for us. So we can replace the nested list comprehension with this line:



          students_plus_codes = list(zip(students, code_list))


          Which results in a list of tuples:



          [('Aljoša', '256D2B'), ('Blažka', 'OEGJL9'), ('Nana', 'GB1PJL'), ('Kaja', 'F0P0F2'), 
          ('Alja', '62KU94'), ... ('Matic', 'E7CJIP'), ('Marija', '1D2UCL'), ('Žiga T.', '6X1DD5')]


          Generating the codes:



          First, I would replace for i in range(24): with for i in range(len(students)): as this allows you to change the number of students without having change other aspects of your code. In this instance 24 is a magic number that could cause issues down the line.



          You could even create a function that generates the the code, then you can use an easy to read list comprehension.



          # <=python3.5
          def generate_code(n, characters):
          return ''.join([random.choice(characters) for _ in range(n)])

          # >=python3.6
          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          Printing the codes:



          It isn't ideal to join the names and codes a single string as this makes it hard to use them separately later. For this reason, I used a list of tuples to match them as pairs. To print them the for loop has two variables, student and code that takes advantage of unpacking and then prints them using the format function.



          Instead of joining the students names with the codes for printing is not an ideal thing to do as it makes it harder to use the names and codes separately later.





          Altogether:



          import random
          import string


          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
          "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
          "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
          "Matic", "Marija", "Žiga T."]

          # It generates the code and puts it in a list
          size = 6
          chars = string.ascii_uppercase + string.digits
          code_list = [create_code(size, chars) for _ in range(len(students))]

          # Combines the two lists (students and codes) into a list of tuples
          students_plus_codes = list(zip(students, code_list))

          for student, code in students_plus_codes:
          print('{} - {}'.format(code, student))





          share|improve this answer








          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













          • $begingroup$
            Thank you, this was really helpful, I would never figure it out on my own :D
            $endgroup$
            – urban pečoler
            9 mins ago














          0












          0








          0





          $begingroup$

          The reason that you are getting so many more entries is because this list comprehension:



           students_plus_codes = [x + str(" - " + y) for y in students for x in code_list]


          It's a nested for loop. If we expand it we can see what is happening:



          students_plus_codes = 
          for y in students: # students has 24 items
          for x in code_list: # code_list has 24 items
          students_plus_codes(x + str(" - " + y))


          So for every iteration of students you do 24 iterations of code_list.



          Fortunately, python has a builtin function called zip that will merge lists for us. So we can replace the nested list comprehension with this line:



          students_plus_codes = list(zip(students, code_list))


          Which results in a list of tuples:



          [('Aljoša', '256D2B'), ('Blažka', 'OEGJL9'), ('Nana', 'GB1PJL'), ('Kaja', 'F0P0F2'), 
          ('Alja', '62KU94'), ... ('Matic', 'E7CJIP'), ('Marija', '1D2UCL'), ('Žiga T.', '6X1DD5')]


          Generating the codes:



          First, I would replace for i in range(24): with for i in range(len(students)): as this allows you to change the number of students without having change other aspects of your code. In this instance 24 is a magic number that could cause issues down the line.



          You could even create a function that generates the the code, then you can use an easy to read list comprehension.



          # <=python3.5
          def generate_code(n, characters):
          return ''.join([random.choice(characters) for _ in range(n)])

          # >=python3.6
          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          Printing the codes:



          It isn't ideal to join the names and codes a single string as this makes it hard to use them separately later. For this reason, I used a list of tuples to match them as pairs. To print them the for loop has two variables, student and code that takes advantage of unpacking and then prints them using the format function.



          Instead of joining the students names with the codes for printing is not an ideal thing to do as it makes it harder to use the names and codes separately later.





          Altogether:



          import random
          import string


          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
          "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
          "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
          "Matic", "Marija", "Žiga T."]

          # It generates the code and puts it in a list
          size = 6
          chars = string.ascii_uppercase + string.digits
          code_list = [create_code(size, chars) for _ in range(len(students))]

          # Combines the two lists (students and codes) into a list of tuples
          students_plus_codes = list(zip(students, code_list))

          for student, code in students_plus_codes:
          print('{} - {}'.format(code, student))





          share|improve this answer








          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$



          The reason that you are getting so many more entries is because this list comprehension:



           students_plus_codes = [x + str(" - " + y) for y in students for x in code_list]


          It's a nested for loop. If we expand it we can see what is happening:



          students_plus_codes = 
          for y in students: # students has 24 items
          for x in code_list: # code_list has 24 items
          students_plus_codes(x + str(" - " + y))


          So for every iteration of students you do 24 iterations of code_list.



          Fortunately, python has a builtin function called zip that will merge lists for us. So we can replace the nested list comprehension with this line:



          students_plus_codes = list(zip(students, code_list))


          Which results in a list of tuples:



          [('Aljoša', '256D2B'), ('Blažka', 'OEGJL9'), ('Nana', 'GB1PJL'), ('Kaja', 'F0P0F2'), 
          ('Alja', '62KU94'), ... ('Matic', 'E7CJIP'), ('Marija', '1D2UCL'), ('Žiga T.', '6X1DD5')]


          Generating the codes:



          First, I would replace for i in range(24): with for i in range(len(students)): as this allows you to change the number of students without having change other aspects of your code. In this instance 24 is a magic number that could cause issues down the line.



          You could even create a function that generates the the code, then you can use an easy to read list comprehension.



          # <=python3.5
          def generate_code(n, characters):
          return ''.join([random.choice(characters) for _ in range(n)])

          # >=python3.6
          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          Printing the codes:



          It isn't ideal to join the names and codes a single string as this makes it hard to use them separately later. For this reason, I used a list of tuples to match them as pairs. To print them the for loop has two variables, student and code that takes advantage of unpacking and then prints them using the format function.



          Instead of joining the students names with the codes for printing is not an ideal thing to do as it makes it harder to use the names and codes separately later.





          Altogether:



          import random
          import string


          def create_code(n, characters):
          return ''.join(random.choices(characters, k=n))


          students = ["Aljoša", "Blažka", "Nana", "Kaja", "Alja", "Tjaša", "Ana",
          "Gal", "Danijela", "Alma", "Neja", "Žiga K.", "Patricija", "Aja",
          "Kristjan", "Urban", "Janja", "Lea", "Žana", "Aljaž", "Tilen",
          "Matic", "Marija", "Žiga T."]

          # It generates the code and puts it in a list
          size = 6
          chars = string.ascii_uppercase + string.digits
          code_list = [create_code(size, chars) for _ in range(len(students))]

          # Combines the two lists (students and codes) into a list of tuples
          students_plus_codes = list(zip(students, code_list))

          for student, code in students_plus_codes:
          print('{} - {}'.format(code, student))






          share|improve this answer








          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|improve this answer



          share|improve this answer






          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          answered 22 mins ago









          AlexAlex

          1364




          1364




          New contributor




          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          New contributor





          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.












          • $begingroup$
            Thank you, this was really helpful, I would never figure it out on my own :D
            $endgroup$
            – urban pečoler
            9 mins ago


















          • $begingroup$
            Thank you, this was really helpful, I would never figure it out on my own :D
            $endgroup$
            – urban pečoler
            9 mins ago
















          $begingroup$
          Thank you, this was really helpful, I would never figure it out on my own :D
          $endgroup$
          – urban pečoler
          9 mins ago




          $begingroup$
          Thank you, this was really helpful, I would never figure it out on my own :D
          $endgroup$
          – urban pečoler
          9 mins ago










          urban pečoler is a new contributor. Be nice, and check out our Code of Conduct.










          draft saved

          draft discarded


















          urban pečoler is a new contributor. Be nice, and check out our Code of Conduct.













          urban pečoler is a new contributor. Be nice, and check out our Code of Conduct.












          urban pečoler is a new contributor. Be nice, and check out our Code of Conduct.
















          Thanks for contributing an answer to Code Review Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f212338%2fkey-generating-program-in-python%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          404 Error Contact Form 7 ajax form submitting

          How to know if a Active Directory user can login interactively

          TypeError: fit_transform() missing 1 required positional argument: 'X'