why does default value for char data type in java has 4 hex when it is a 16 bit datatype












-1















I am new to java, and this question may be silly to many.



When going through the basics, i learnt this:



char: The char data type is a single 16-bit Unicode character. It has a minimum value of 'u0000' (or 0) and a maximum value of 'uffff' (or 65,535 inclusive).



My question is why does the default, minimum and maximum have 4 hex when it can be only one?










share|improve this question


















  • 2





    Why do you think it can only be one?

    – Max Vollmer
    Nov 24 '18 at 0:27











  • @max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

    – Bohemian
    Nov 24 '18 at 0:29











  • Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

    – Bohemian
    Nov 24 '18 at 0:31











  • Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

    – user8506488
    Nov 24 '18 at 18:12
















-1















I am new to java, and this question may be silly to many.



When going through the basics, i learnt this:



char: The char data type is a single 16-bit Unicode character. It has a minimum value of 'u0000' (or 0) and a maximum value of 'uffff' (or 65,535 inclusive).



My question is why does the default, minimum and maximum have 4 hex when it can be only one?










share|improve this question


















  • 2





    Why do you think it can only be one?

    – Max Vollmer
    Nov 24 '18 at 0:27











  • @max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

    – Bohemian
    Nov 24 '18 at 0:29











  • Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

    – Bohemian
    Nov 24 '18 at 0:31











  • Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

    – user8506488
    Nov 24 '18 at 18:12














-1












-1








-1








I am new to java, and this question may be silly to many.



When going through the basics, i learnt this:



char: The char data type is a single 16-bit Unicode character. It has a minimum value of 'u0000' (or 0) and a maximum value of 'uffff' (or 65,535 inclusive).



My question is why does the default, minimum and maximum have 4 hex when it can be only one?










share|improve this question














I am new to java, and this question may be silly to many.



When going through the basics, i learnt this:



char: The char data type is a single 16-bit Unicode character. It has a minimum value of 'u0000' (or 0) and a maximum value of 'uffff' (or 65,535 inclusive).



My question is why does the default, minimum and maximum have 4 hex when it can be only one?







java






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 0:24









user8506488user8506488

301




301








  • 2





    Why do you think it can only be one?

    – Max Vollmer
    Nov 24 '18 at 0:27











  • @max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

    – Bohemian
    Nov 24 '18 at 0:29











  • Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

    – Bohemian
    Nov 24 '18 at 0:31











  • Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

    – user8506488
    Nov 24 '18 at 18:12














  • 2





    Why do you think it can only be one?

    – Max Vollmer
    Nov 24 '18 at 0:27











  • @max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

    – Bohemian
    Nov 24 '18 at 0:29











  • Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

    – Bohemian
    Nov 24 '18 at 0:31











  • Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

    – user8506488
    Nov 24 '18 at 18:12








2




2





Why do you think it can only be one?

– Max Vollmer
Nov 24 '18 at 0:27





Why do you think it can only be one?

– Max Vollmer
Nov 24 '18 at 0:27













@max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

– Bohemian
Nov 24 '18 at 0:29





@max I think OP means it can only have 1 value (at a time) but it seems to have 1 “u” and 4 “f” values.

– Bohemian
Nov 24 '18 at 0:29













Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

– Bohemian
Nov 24 '18 at 0:31





Exactly what do you mean by “one value” and “4 hex”? Do you now about hex literals?

– Bohemian
Nov 24 '18 at 0:31













Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

– user8506488
Nov 24 '18 at 18:12





Thanks @bohemian , I completely missed the point , that one F is binary 1111 ( and exactly fits 4 bits). Super silly me :) :)

– user8506488
Nov 24 '18 at 18:12












2 Answers
2






active

oldest

votes


















3














I think you need to read up on numeral systems.



Binary: Represents numbers using 2 digits, 0 and 1.



Decimal: Represents numbers using 10 digits, 0 - 9.



Hexadecimal: Represents numbers using 16 digits, 0 - F.



A char in Java is a type that can hold numbers with 16 bits, i.e. in the range 0 - 1111111111111111 in binary, 0 - 65535 in decimal or 0 - FFFF in hexadecimal.






share|improve this answer
























  • Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

    – user8506488
    Nov 24 '18 at 18:11



















2














Hex F is decimal 15 or binary 1111. It fits exactly in 4 bits. a 16-bit value can hold 4 times 4 bits, hence from 0x0000 to 0xFFFF (which is 2^16 = 65,536).



The u in your example is for Unicode, pretty much saying that you can store unicode characters that take up to 16 bits, from u0000 to uFFFF.






share|improve this answer
























  • Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

    – user8506488
    Nov 24 '18 at 18:07













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














I think you need to read up on numeral systems.



Binary: Represents numbers using 2 digits, 0 and 1.



Decimal: Represents numbers using 10 digits, 0 - 9.



Hexadecimal: Represents numbers using 16 digits, 0 - F.



A char in Java is a type that can hold numbers with 16 bits, i.e. in the range 0 - 1111111111111111 in binary, 0 - 65535 in decimal or 0 - FFFF in hexadecimal.






share|improve this answer
























  • Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

    – user8506488
    Nov 24 '18 at 18:11
















3














I think you need to read up on numeral systems.



Binary: Represents numbers using 2 digits, 0 and 1.



Decimal: Represents numbers using 10 digits, 0 - 9.



Hexadecimal: Represents numbers using 16 digits, 0 - F.



A char in Java is a type that can hold numbers with 16 bits, i.e. in the range 0 - 1111111111111111 in binary, 0 - 65535 in decimal or 0 - FFFF in hexadecimal.






share|improve this answer
























  • Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

    – user8506488
    Nov 24 '18 at 18:11














3












3








3







I think you need to read up on numeral systems.



Binary: Represents numbers using 2 digits, 0 and 1.



Decimal: Represents numbers using 10 digits, 0 - 9.



Hexadecimal: Represents numbers using 16 digits, 0 - F.



A char in Java is a type that can hold numbers with 16 bits, i.e. in the range 0 - 1111111111111111 in binary, 0 - 65535 in decimal or 0 - FFFF in hexadecimal.






share|improve this answer













I think you need to read up on numeral systems.



Binary: Represents numbers using 2 digits, 0 and 1.



Decimal: Represents numbers using 10 digits, 0 - 9.



Hexadecimal: Represents numbers using 16 digits, 0 - F.



A char in Java is a type that can hold numbers with 16 bits, i.e. in the range 0 - 1111111111111111 in binary, 0 - 65535 in decimal or 0 - FFFF in hexadecimal.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 24 '18 at 0:31









Max VollmerMax Vollmer

5,75651837




5,75651837













  • Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

    – user8506488
    Nov 24 '18 at 18:11



















  • Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

    – user8506488
    Nov 24 '18 at 18:11

















Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

– user8506488
Nov 24 '18 at 18:11





Thanks @max , I completely missed the point , that that one F is binary 1111 ( and exactly fits 4 bits)

– user8506488
Nov 24 '18 at 18:11













2














Hex F is decimal 15 or binary 1111. It fits exactly in 4 bits. a 16-bit value can hold 4 times 4 bits, hence from 0x0000 to 0xFFFF (which is 2^16 = 65,536).



The u in your example is for Unicode, pretty much saying that you can store unicode characters that take up to 16 bits, from u0000 to uFFFF.






share|improve this answer
























  • Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

    – user8506488
    Nov 24 '18 at 18:07


















2














Hex F is decimal 15 or binary 1111. It fits exactly in 4 bits. a 16-bit value can hold 4 times 4 bits, hence from 0x0000 to 0xFFFF (which is 2^16 = 65,536).



The u in your example is for Unicode, pretty much saying that you can store unicode characters that take up to 16 bits, from u0000 to uFFFF.






share|improve this answer
























  • Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

    – user8506488
    Nov 24 '18 at 18:07
















2












2








2







Hex F is decimal 15 or binary 1111. It fits exactly in 4 bits. a 16-bit value can hold 4 times 4 bits, hence from 0x0000 to 0xFFFF (which is 2^16 = 65,536).



The u in your example is for Unicode, pretty much saying that you can store unicode characters that take up to 16 bits, from u0000 to uFFFF.






share|improve this answer













Hex F is decimal 15 or binary 1111. It fits exactly in 4 bits. a 16-bit value can hold 4 times 4 bits, hence from 0x0000 to 0xFFFF (which is 2^16 = 65,536).



The u in your example is for Unicode, pretty much saying that you can store unicode characters that take up to 16 bits, from u0000 to uFFFF.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 24 '18 at 0:30









RobertRobert

2,15962536




2,15962536













  • Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

    – user8506488
    Nov 24 '18 at 18:07





















  • Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

    – user8506488
    Nov 24 '18 at 18:07



















Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

– user8506488
Nov 24 '18 at 18:07







Thanks @robert , now I get it perfectly, I had completely overlooked the fact that one F is binary 1111 (and fits exactly 4 bits) . The question was super silly to have been asked in a forum :) :). Thanks anyway

– user8506488
Nov 24 '18 at 18:07




















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