Python : pickle.load() only returns the first value of the file
0
I'm creating a very basic program that stores a dictionary of words translated from English to French, for example :
I'm storing all those values in a file that I append and read using the pickle function.
The problem is that when I use pickle.load to read the file and then print it, only the first value is returned.
I can't see where is my error, and I've been looking everywhere without getting any answer.
Thanks in advance.
import pickle
import os
clear=lambda:os.system("cls")
def pause():
input("Press ENTER to continue.")
def print_dictionary(dct):
print("Dictionary (English / French)")
for wordenglish, wordfrench in dct.items():
print("{} : {}".format(wordenglish, wordfrench))
dictionary={}
for loop in range(3):
wordEnglish=input("Enter the word in English : ")
wordFrench=input("Enter the word in French : ")
pause()
clear()
print("Saving ...")
dictionary[wordEnglish]=wordFrench
with open("data","ab") as file:
pickler=pickle.Pickler(file)
pickler.dump(dictionary)
print("Saved !")
pause()
with open("data","rb") as file:
unpickler=pickle.Unpickler(file)
dictionary_get=unpickler.load()
print_dictionary(dictionary_get)
pause()
For example, if I enter "Fire","Feu" / "Water","Eau" / "Mud","Boue", the only value I will get will be "Fire","Feu".
python pickle
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
|
show 3 more comments
0
I'm creating a very basic program that stores a dictionary of words translated from English to French, for example :
I'm storing all those values in a file that I append and read using the pickle function.
The problem is that when I use pickle.load to read the file and then print it, only the first value is returned.
I can't see where is my error, and I've been looking everywhere without getting any answer.
Thanks in advance.
import pickle
import os
clear=lambda:os.system("cls")
def pause():
input("Press ENTER to continue.")
def print_dictionary(dct):
print("Dictionary (English / French)")
for wordenglish, wordfrench in dct.items():
print("{} : {}".format(wordenglish, wordfrench))
dictionary={}
for loop in range(3):
wordEnglish=input("Enter the word in English : ")
wordFrench=input("Enter the word in French : ")
pause()
clear()
print("Saving ...")
dictionary[wordEnglish]=wordFrench
with open("data","ab") as file:
pickler=pickle.Pickler(file)
pickler.dump(dictionary)
print("Saved !")
pause()
with open("data","rb") as file:
unpickler=pickle.Unpickler(file)
dictionary_get=unpickler.load()
print_dictionary(dictionary_get)
pause()
For example, if I enter "Fire","Feu" / "Water","Eau" / "Mud","Boue", the only value I will get will be "Fire","Feu".
python pickle
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
@DanielRoseman no they are using 'ab' mode. The problem is that.loadwon't keep trying to load once it deserializes an object. You have to keep calling.load
– juanpa.arrivillaga
Nov 24 '18 at 21:52
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55
|
show 3 more comments
0
0
0
I'm creating a very basic program that stores a dictionary of words translated from English to French, for example :
I'm storing all those values in a file that I append and read using the pickle function.
The problem is that when I use pickle.load to read the file and then print it, only the first value is returned.
I can't see where is my error, and I've been looking everywhere without getting any answer.
Thanks in advance.
import pickle
import os
clear=lambda:os.system("cls")
def pause():
input("Press ENTER to continue.")
def print_dictionary(dct):
print("Dictionary (English / French)")
for wordenglish, wordfrench in dct.items():
print("{} : {}".format(wordenglish, wordfrench))
dictionary={}
for loop in range(3):
wordEnglish=input("Enter the word in English : ")
wordFrench=input("Enter the word in French : ")
pause()
clear()
print("Saving ...")
dictionary[wordEnglish]=wordFrench
with open("data","ab") as file:
pickler=pickle.Pickler(file)
pickler.dump(dictionary)
print("Saved !")
pause()
with open("data","rb") as file:
unpickler=pickle.Unpickler(file)
dictionary_get=unpickler.load()
print_dictionary(dictionary_get)
pause()
For example, if I enter "Fire","Feu" / "Water","Eau" / "Mud","Boue", the only value I will get will be "Fire","Feu".
python pickle
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
I'm creating a very basic program that stores a dictionary of words translated from English to French, for example :
I'm storing all those values in a file that I append and read using the pickle function.
The problem is that when I use pickle.load to read the file and then print it, only the first value is returned.
I can't see where is my error, and I've been looking everywhere without getting any answer.
Thanks in advance.
import pickle
import os
clear=lambda:os.system("cls")
def pause():
input("Press ENTER to continue.")
def print_dictionary(dct):
print("Dictionary (English / French)")
for wordenglish, wordfrench in dct.items():
print("{} : {}".format(wordenglish, wordfrench))
dictionary={}
for loop in range(3):
wordEnglish=input("Enter the word in English : ")
wordFrench=input("Enter the word in French : ")
pause()
clear()
print("Saving ...")
dictionary[wordEnglish]=wordFrench
with open("data","ab") as file:
pickler=pickle.Pickler(file)
pickler.dump(dictionary)
print("Saved !")
pause()
with open("data","rb") as file:
unpickler=pickle.Unpickler(file)
dictionary_get=unpickler.load()
print_dictionary(dictionary_get)
pause()
For example, if I enter "Fire","Feu" / "Water","Eau" / "Mud","Boue", the only value I will get will be "Fire","Feu".
python pickle
python pickle
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
asked Nov 24 '18 at 21:47
NitroxoneNitroxone
192
192
Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
@DanielRoseman no they are using 'ab' mode. The problem is that.loadwon't keep trying to load once it deserializes an object. You have to keep calling.load
– juanpa.arrivillaga
Nov 24 '18 at 21:52
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55
|
show 3 more comments
Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
@DanielRoseman no they are using 'ab' mode. The problem is that.loadwon't keep trying to load once it deserializes an object. You have to keep calling.load
– juanpa.arrivillaga
Nov 24 '18 at 21:52
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55
Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
@DanielRoseman no they are using 'ab' mode. The problem is that
.load won't keep trying to load once it deserializes an object. You have to keep calling .load– juanpa.arrivillaga
Nov 24 '18 at 21:52
@DanielRoseman no they are using 'ab' mode. The problem is that
.load won't keep trying to load once it deserializes an object. You have to keep calling .load– juanpa.arrivillaga
Nov 24 '18 at 21:52
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55
|
show 3 more comments
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Because you save each item separately inside the loop, overwriting the pickle file each time.
– Daniel Roseman
Nov 24 '18 at 21:51
@DanielRoseman no they are using 'ab' mode. The problem is that
.loadwon't keep trying to load once it deserializes an object. You have to keep calling.load– juanpa.arrivillaga
Nov 24 '18 at 21:52
However, why are you progressively dumping incremental versions of your dict?
– juanpa.arrivillaga
Nov 24 '18 at 21:53
@DanielRoseman No, because when I open the data file I can clearly see all the values are here.
– Nitroxone
Nov 24 '18 at 21:53
What do you mean by "keep calling .load" ? @juanpa.arrivillaga As for dumping incremental versions of my dict, it's just because I don't know any other way to do this ...
– Nitroxone
Nov 24 '18 at 21:55