using std::ios::sync_with_stdio(false) getting “WA”
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
There are exactly n inputs and in which each entry is getting entered twice
except once but n value may go to 10 000 000 000 spoj ololo
Note-> The xor of two same value is always zero
1^8=9 -> 9^1=8
we can take xor of values while input is getting entered finally we will have a single value that was entered exactly once and all other will be cancelled
But when I am using cin to take input I am getting as TLE but as mentioned in this post cin vs scanf
I changed my program as below
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
cin>>t;
std::ios::sync_with_stdio(false);
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
I am getting as "WA"
But when I am changing the position of std::ios::sync_with_stdio(false);
as
#include<bits/stdc++.h>
using namespace std;
int main(){
long long int t;
std::ios::sync_with_stdio(false);
cin>>t;
long long int ans=0;
while(t--){
long long int temp;
cin>>temp;
ans=ans^temp;
}
cout<<ans;
}
My answer is getting accepted can any tell me why this is happening ?
c++
c++
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 mins ago
ney123ney123
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 mins ago
ney123ney123
1
asked 8 mins ago
ney123ney123
1
1
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ney123 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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