Standard for “not found” when using size_t
Is there a standard what value to use when you do an array search and the value is not found.
With signed I would return -1. But what about size_t aka long unsigned.
int find(int a,int b, int n){
for(int i=0; i<n; i++){
if(a[i]==b)
return i;
}
return -1;
}
When using size_t just would come up with this. But it's not really perfect.
long long int find(int a,int b, size_t n){
for(size_t i=0; i<n; i++){
if(a[i]==b)
return (long long int)i;
}
return -1;
}
clang size-t
add a comment |
Is there a standard what value to use when you do an array search and the value is not found.
With signed I would return -1. But what about size_t aka long unsigned.
int find(int a,int b, int n){
for(int i=0; i<n; i++){
if(a[i]==b)
return i;
}
return -1;
}
When using size_t just would come up with this. But it's not really perfect.
long long int find(int a,int b, size_t n){
for(size_t i=0; i<n; i++){
if(a[i]==b)
return (long long int)i;
}
return -1;
}
clang size-t
add a comment |
Is there a standard what value to use when you do an array search and the value is not found.
With signed I would return -1. But what about size_t aka long unsigned.
int find(int a,int b, int n){
for(int i=0; i<n; i++){
if(a[i]==b)
return i;
}
return -1;
}
When using size_t just would come up with this. But it's not really perfect.
long long int find(int a,int b, size_t n){
for(size_t i=0; i<n; i++){
if(a[i]==b)
return (long long int)i;
}
return -1;
}
clang size-t
Is there a standard what value to use when you do an array search and the value is not found.
With signed I would return -1. But what about size_t aka long unsigned.
int find(int a,int b, int n){
for(int i=0; i<n; i++){
if(a[i]==b)
return i;
}
return -1;
}
When using size_t just would come up with this. But it's not really perfect.
long long int find(int a,int b, size_t n){
for(size_t i=0; i<n; i++){
if(a[i]==b)
return (long long int)i;
}
return -1;
}
clang size-t
clang size-t
asked Nov 22 '18 at 2:45
Felix Yah Batta ManFelix Yah Batta Man
12729
12729
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
To allow a size_t type to have a negative value, there is a ssize_t
type which is signed.
You can't rely on the equivalence of the size_t to unsigned long as its architecture specific.
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53423166%2fstandard-for-not-found-when-using-size-t%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
To allow a size_t type to have a negative value, there is a ssize_t
type which is signed.
You can't rely on the equivalence of the size_t to unsigned long as its architecture specific.
add a comment |
To allow a size_t type to have a negative value, there is a ssize_t
type which is signed.
You can't rely on the equivalence of the size_t to unsigned long as its architecture specific.
add a comment |
To allow a size_t type to have a negative value, there is a ssize_t
type which is signed.
You can't rely on the equivalence of the size_t to unsigned long as its architecture specific.
To allow a size_t type to have a negative value, there is a ssize_t
type which is signed.
You can't rely on the equivalence of the size_t to unsigned long as its architecture specific.
answered Nov 22 '18 at 2:50
danblackdanblack
1,5671214
1,5671214
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53423166%2fstandard-for-not-found-when-using-size-t%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown