Interweaving an array's values












0












$begingroup$


I've written a function to sort an array that interweaves an arrays values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);












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$endgroup$












  • $begingroup$
    I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
    $endgroup$
    – vnp
    35 mins ago










  • $begingroup$
    @vnp, updated the wording
    $endgroup$
    – totalnoob
    28 mins ago
















0












$begingroup$


I've written a function to sort an array that interweaves an arrays values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);












share|improve this question











$endgroup$












  • $begingroup$
    I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
    $endgroup$
    – vnp
    35 mins ago










  • $begingroup$
    @vnp, updated the wording
    $endgroup$
    – totalnoob
    28 mins ago














0












0








0





$begingroup$


I've written a function to sort an array that interweaves an arrays values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);












share|improve this question











$endgroup$




I've written a function to sort an array that interweaves an arrays values in the way of if you had two separate arrays [1,2,3,4,5] on one side and [6,7,8,9,0] on the other and it becomes [1, 6, 2, 7, 3, 8, 4, 9, 5, 0].



The code works, but I'm wondering how it can be cleaned up and be more performant without the need for three additional arrays and to see if it can be done on the cards array itself.






let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);








let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);





let data = [1,2,3,4,5,6,7,8,9,0];

const interweave = data => {
const _data = ;
const l = data.slice(0, data.length / 2);
const r = data.slice(data.length / 2, data.length);
if (l.length === r.length) {
for (let i = 0; i < l.length; i++) {
_data.push(l[i], r[i]);
}
}
return _data;
}

interweave(data);






javascript






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share|improve this question













share|improve this question




share|improve this question








edited 6 mins ago









Jamal

30.3k11117227




30.3k11117227










asked 1 hour ago









totalnoobtotalnoob

1435




1435












  • $begingroup$
    I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
    $endgroup$
    – vnp
    35 mins ago










  • $begingroup$
    @vnp, updated the wording
    $endgroup$
    – totalnoob
    28 mins ago


















  • $begingroup$
    I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
    $endgroup$
    – vnp
    35 mins ago










  • $begingroup$
    @vnp, updated the wording
    $endgroup$
    – totalnoob
    28 mins ago
















$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
35 mins ago




$begingroup$
I wouldn't call this deck shuffled. It all depends on your definition of shuffling.
$endgroup$
– vnp
35 mins ago












$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
28 mins ago




$begingroup$
@vnp, updated the wording
$endgroup$
– totalnoob
28 mins ago










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