Get those items which are ordered after they have been delivered
1
I have two tables, namely itemOrders and itemDelivered.
itemOrders
+-------+---------+--------+
| id | orderid | itemid |
+-------+---------+--------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 1 |
| 6 | 3 | 2 |
+-------+---------+--------+
And
itemDelivered
+-------+-------------+--------+
| id | orderId | itemid |
+-------+-------------+--------+
| 1 | 2 | 2 |
| 2 | 3 | 2 |
| 3 | 2 | 1 |
+-------+-------------+--------+
From the above scenario I want all those distinct items whose max orderId in the table itemDelivered is less than max orderId in the table itemOrders.
In the above example I should get itemid 1 as the result, as it's max orderid is 2 in table itemDelivered, which is less than its max orderid in table itemOrders which is 3.
I wrote the following query but it gives me both the items, 1 and 2 as item No. 2 doesn't have orderId 1 in itemDelivered table.
SELECT DISTINCT( itemid )
FROM itemorders
WHERE orderid NOT IN (SELECT orderid
FROM itemdelivered)
mysql
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
add a comment |
1
I have two tables, namely itemOrders and itemDelivered.
itemOrders
+-------+---------+--------+
| id | orderid | itemid |
+-------+---------+--------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 1 |
| 6 | 3 | 2 |
+-------+---------+--------+
And
itemDelivered
+-------+-------------+--------+
| id | orderId | itemid |
+-------+-------------+--------+
| 1 | 2 | 2 |
| 2 | 3 | 2 |
| 3 | 2 | 1 |
+-------+-------------+--------+
From the above scenario I want all those distinct items whose max orderId in the table itemDelivered is less than max orderId in the table itemOrders.
In the above example I should get itemid 1 as the result, as it's max orderid is 2 in table itemDelivered, which is less than its max orderid in table itemOrders which is 3.
I wrote the following query but it gives me both the items, 1 and 2 as item No. 2 doesn't have orderId 1 in itemDelivered table.
SELECT DISTINCT( itemid )
FROM itemorders
WHERE orderid NOT IN (SELECT orderid
FROM itemdelivered)
mysql
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
@P.Salmon,orderidcolumn and notitemidcolumn.
– abbas
Nov 22 '18 at 16:19
1
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46
add a comment |
1
1
1
I have two tables, namely itemOrders and itemDelivered.
itemOrders
+-------+---------+--------+
| id | orderid | itemid |
+-------+---------+--------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 1 |
| 6 | 3 | 2 |
+-------+---------+--------+
And
itemDelivered
+-------+-------------+--------+
| id | orderId | itemid |
+-------+-------------+--------+
| 1 | 2 | 2 |
| 2 | 3 | 2 |
| 3 | 2 | 1 |
+-------+-------------+--------+
From the above scenario I want all those distinct items whose max orderId in the table itemDelivered is less than max orderId in the table itemOrders.
In the above example I should get itemid 1 as the result, as it's max orderid is 2 in table itemDelivered, which is less than its max orderid in table itemOrders which is 3.
I wrote the following query but it gives me both the items, 1 and 2 as item No. 2 doesn't have orderId 1 in itemDelivered table.
SELECT DISTINCT( itemid )
FROM itemorders
WHERE orderid NOT IN (SELECT orderid
FROM itemdelivered)
mysql
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
I have two tables, namely itemOrders and itemDelivered.
itemOrders
+-------+---------+--------+
| id | orderid | itemid |
+-------+---------+--------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
| 5 | 3 | 1 |
| 6 | 3 | 2 |
+-------+---------+--------+
And
itemDelivered
+-------+-------------+--------+
| id | orderId | itemid |
+-------+-------------+--------+
| 1 | 2 | 2 |
| 2 | 3 | 2 |
| 3 | 2 | 1 |
+-------+-------------+--------+
From the above scenario I want all those distinct items whose max orderId in the table itemDelivered is less than max orderId in the table itemOrders.
In the above example I should get itemid 1 as the result, as it's max orderid is 2 in table itemDelivered, which is less than its max orderid in table itemOrders which is 3.
I wrote the following query but it gives me both the items, 1 and 2 as item No. 2 doesn't have orderId 1 in itemDelivered table.
SELECT DISTINCT( itemid )
FROM itemorders
WHERE orderid NOT IN (SELECT orderid
FROM itemdelivered)
mysql
mysql
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
edited Nov 22 '18 at 17:44
Strawberry
25.9k83149
25.9k83149
asked Nov 22 '18 at 16:05
abbasabbas
124110
asked Nov 22 '18 at 16:05
abbasabbas
124110
asked Nov 22 '18 at 16:05
abbasabbas
124110
124110
'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
@P.Salmon,orderidcolumn and notitemidcolumn.
– abbas
Nov 22 '18 at 16:19
1
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46
add a comment |
'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
@P.Salmon,orderidcolumn and notitemidcolumn.
– abbas
Nov 22 '18 at 16:19
1
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46
'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
@P.Salmon,
orderid column and not itemid column.– abbas
Nov 22 '18 at 16:19
@P.Salmon,
orderid column and not itemid column.– abbas
Nov 22 '18 at 16:19
1
1
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46
add a comment |
2 Answers
2
active
oldest
votes
1
You can LEFT JOIN between the two table using itemid, and GROUP BY on the itemid.
Eventually use HAVING clause to consider only those itemid values, where MAX(itemdelivered.orderid) < MAX(itemorders.orderid)
View on DB Fiddle
SELECT io.itemid
FROM itemorders AS io
LEFT JOIN itemdelivered AS id
ON id.itemid = io.itemid
GROUP BY io.itemid
HAVING MAX(id.orderid) < MAX(io.orderid)
OR MAX(id.orderid) IS NULL
Result
| itemid |
| ------ |
| 1 |
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
your query works if "itemid" 1 exists in "itemdelivered"table, if "itemid" 1 doesn't exist, then the result is blank.
– abbas
Nov 24 '18 at 9:24
@abbas you can simply changeJOINtoLEFT JOIN. your problem statement did not mention about this possible case.
– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2);If you have this query in DB Fiddle, then the output is empty.
– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
add a comment |
1
Ok, manage to write a query which gives the desired output.
SELECT io.itemid
FROM itemorders as io
LEFT JOIN itemdelivered AS id ON io.orderid = id.orderid AND io.itemid = id.itemid
WHERE id.itemid IS NULL
HAVING MAX(id.orderid) IS NULL
ORDER BY io.id
answered Nov 22 '18 at 17:18
abbasabbas
124110
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can LEFT JOIN between the two table using itemid, and GROUP BY on the itemid.
Eventually use HAVING clause to consider only those itemid values, where MAX(itemdelivered.orderid) < MAX(itemorders.orderid)
View on DB Fiddle
SELECT io.itemid
FROM itemorders AS io
LEFT JOIN itemdelivered AS id
ON id.itemid = io.itemid
GROUP BY io.itemid
HAVING MAX(id.orderid) < MAX(io.orderid)
OR MAX(id.orderid) IS NULL
Result
| itemid |
| ------ |
| 1 |
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
your query works if "itemid" 1 exists in "itemdelivered"table, if "itemid" 1 doesn't exist, then the result is blank.
– abbas
Nov 24 '18 at 9:24
@abbas you can simply changeJOINtoLEFT JOIN. your problem statement did not mention about this possible case.
– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2);If you have this query in DB Fiddle, then the output is empty.
– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
add a comment |
1
You can LEFT JOIN between the two table using itemid, and GROUP BY on the itemid.
Eventually use HAVING clause to consider only those itemid values, where MAX(itemdelivered.orderid) < MAX(itemorders.orderid)
View on DB Fiddle
SELECT io.itemid
FROM itemorders AS io
LEFT JOIN itemdelivered AS id
ON id.itemid = io.itemid
GROUP BY io.itemid
HAVING MAX(id.orderid) < MAX(io.orderid)
OR MAX(id.orderid) IS NULL
Result
| itemid |
| ------ |
| 1 |
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
your query works if "itemid" 1 exists in "itemdelivered"table, if "itemid" 1 doesn't exist, then the result is blank.
– abbas
Nov 24 '18 at 9:24
@abbas you can simply changeJOINtoLEFT JOIN. your problem statement did not mention about this possible case.
– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2);If you have this query in DB Fiddle, then the output is empty.
– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
add a comment |
1
1
1
You can LEFT JOIN between the two table using itemid, and GROUP BY on the itemid.
Eventually use HAVING clause to consider only those itemid values, where MAX(itemdelivered.orderid) < MAX(itemorders.orderid)
View on DB Fiddle
SELECT io.itemid
FROM itemorders AS io
LEFT JOIN itemdelivered AS id
ON id.itemid = io.itemid
GROUP BY io.itemid
HAVING MAX(id.orderid) < MAX(io.orderid)
OR MAX(id.orderid) IS NULL
Result
| itemid |
| ------ |
| 1 |
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
You can LEFT JOIN between the two table using itemid, and GROUP BY on the itemid.
Eventually use HAVING clause to consider only those itemid values, where MAX(itemdelivered.orderid) < MAX(itemorders.orderid)
View on DB Fiddle
SELECT io.itemid
FROM itemorders AS io
LEFT JOIN itemdelivered AS id
ON id.itemid = io.itemid
GROUP BY io.itemid
HAVING MAX(id.orderid) < MAX(io.orderid)
OR MAX(id.orderid) IS NULL
Result
| itemid |
| ------ |
| 1 |
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
edited Nov 24 '18 at 11:27
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
answered Nov 22 '18 at 17:21
Madhur BhaiyaMadhur Bhaiya
19.6k62236
19.6k62236
your query works if "itemid" 1 exists in "itemdelivered"table, if "itemid" 1 doesn't exist, then the result is blank.
– abbas
Nov 24 '18 at 9:24
@abbas you can simply changeJOINtoLEFT JOIN. your problem statement did not mention about this possible case.
– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2);If you have this query in DB Fiddle, then the output is empty.
– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
add a comment |
your query works if "itemid" 1 exists in "itemdelivered"table, if "itemid" 1 doesn't exist, then the result is blank.
– abbas
Nov 24 '18 at 9:24
@abbas you can simply changeJOINtoLEFT JOIN. your problem statement did not mention about this possible case.
– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2);If you have this query in DB Fiddle, then the output is empty.
– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
your query works if "itemid" 1 exists in "itemdelivered"
table, if "itemid" 1 doesn't exist, then the result is blank.– abbas
Nov 24 '18 at 9:24
your query works if "itemid" 1 exists in "itemdelivered"
table, if "itemid" 1 doesn't exist, then the result is blank.– abbas
Nov 24 '18 at 9:24
@abbas you can simply change
JOIN to LEFT JOIN. your problem statement did not mention about this possible case.– Madhur Bhaiya
Nov 24 '18 at 9:26
@abbas you can simply change
JOIN to LEFT JOIN. your problem statement did not mention about this possible case.– Madhur Bhaiya
Nov 24 '18 at 9:26
insert into itemdelivered(orderid, itemid) values (2,2),(3,2); If you have this query in DB Fiddle, then the output is empty.– abbas
Nov 24 '18 at 11:17
insert into itemdelivered(orderid, itemid) values (2,2),(3,2); If you have this query in DB Fiddle, then the output is empty.– abbas
Nov 24 '18 at 11:17
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
@abbas please check the edited answer.
– Madhur Bhaiya
Nov 24 '18 at 11:27
add a comment |
1
Ok, manage to write a query which gives the desired output.
SELECT io.itemid
FROM itemorders as io
LEFT JOIN itemdelivered AS id ON io.orderid = id.orderid AND io.itemid = id.itemid
WHERE id.itemid IS NULL
HAVING MAX(id.orderid) IS NULL
ORDER BY io.id
answered Nov 22 '18 at 17:18
abbasabbas
124110
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
add a comment |
1
Ok, manage to write a query which gives the desired output.
SELECT io.itemid
FROM itemorders as io
LEFT JOIN itemdelivered AS id ON io.orderid = id.orderid AND io.itemid = id.itemid
WHERE id.itemid IS NULL
HAVING MAX(id.orderid) IS NULL
ORDER BY io.id
answered Nov 22 '18 at 17:18
abbasabbas
124110
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
add a comment |
1
1
1
Ok, manage to write a query which gives the desired output.
SELECT io.itemid
FROM itemorders as io
LEFT JOIN itemdelivered AS id ON io.orderid = id.orderid AND io.itemid = id.itemid
WHERE id.itemid IS NULL
HAVING MAX(id.orderid) IS NULL
ORDER BY io.id
answered Nov 22 '18 at 17:18
abbasabbas
124110
Ok, manage to write a query which gives the desired output.
SELECT io.itemid
FROM itemorders as io
LEFT JOIN itemdelivered AS id ON io.orderid = id.orderid AND io.itemid = id.itemid
WHERE id.itemid IS NULL
HAVING MAX(id.orderid) IS NULL
ORDER BY io.id
answered Nov 22 '18 at 17:18
abbasabbas
124110
edited Nov 23 '18 at 3:11
answered Nov 22 '18 at 17:18
abbasabbas
124110
answered Nov 22 '18 at 17:18
abbasabbas
124110
answered Nov 22 '18 at 17:18
abbasabbas
124110
124110
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
add a comment |
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@MadhurBhaiya can you please elaborate your point.
– abbas
Nov 22 '18 at 17:21
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@Strawberry, I have edited my answer.
– abbas
Nov 23 '18 at 3:13
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya, I have commented on your answer.
– abbas
Nov 24 '18 at 9:24
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
@MadhurBhaiya; replied your answer.
– abbas
Nov 24 '18 at 11:23
add a comment |
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'less than its max orderid in table itemOrders which is 3.' - there is no itemid 3 in itemorders for orderid 1.
– P.Salmon
Nov 22 '18 at 16:11
@P.Salmon,
orderidcolumn and notitemidcolumn.– abbas
Nov 22 '18 at 16:19
1
Note that DISTINCT is not a function. It takes no arguments, so those parentheses are not doing anything.
– Strawberry
Nov 22 '18 at 17:46