What can I do in this code to prompt an error when a negative number is used?











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i was wondering what can I do to prompt an error when I input a negative number. I used a for loop for this program. What this program does, or at least its supposed to do, is to output the factor of any given number (if positive). But I am not sure how to make my code to prompt an error or at least keep asking for a number if the number that input is less or equal to 0.



I used the variable n as the number to input by the user.



I am really new to programming and I am eager to finish this program as soon as possible. Can you please assist?



  #include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;


int main()
{
double n;
cout << "Welcome to this program... Hope you like it" << flush << endl;
do
{
int i, fact = 1, n;
cout << "Please enter a value for the variable " "n: ";
cin >> n;

for (i = 1; i <= n; i++) {
fact = fact * i;
}
cout << "Factorial of " << n << " is: " << fact << endl;
cout << " Thanks for using this program... hope you liked it!" << endl;
} while (n >= 0);
return 0;
}









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  • 6




    Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
    – user4581301
    Nov 20 at 0:41










  • Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
    – user4581301
    Nov 20 at 0:46















up vote
3
down vote

favorite
1












i was wondering what can I do to prompt an error when I input a negative number. I used a for loop for this program. What this program does, or at least its supposed to do, is to output the factor of any given number (if positive). But I am not sure how to make my code to prompt an error or at least keep asking for a number if the number that input is less or equal to 0.



I used the variable n as the number to input by the user.



I am really new to programming and I am eager to finish this program as soon as possible. Can you please assist?



  #include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;


int main()
{
double n;
cout << "Welcome to this program... Hope you like it" << flush << endl;
do
{
int i, fact = 1, n;
cout << "Please enter a value for the variable " "n: ";
cin >> n;

for (i = 1; i <= n; i++) {
fact = fact * i;
}
cout << "Factorial of " << n << " is: " << fact << endl;
cout << " Thanks for using this program... hope you liked it!" << endl;
} while (n >= 0);
return 0;
}









share|improve this question


















  • 6




    Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
    – user4581301
    Nov 20 at 0:41










  • Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
    – user4581301
    Nov 20 at 0:46













up vote
3
down vote

favorite
1









up vote
3
down vote

favorite
1






1





i was wondering what can I do to prompt an error when I input a negative number. I used a for loop for this program. What this program does, or at least its supposed to do, is to output the factor of any given number (if positive). But I am not sure how to make my code to prompt an error or at least keep asking for a number if the number that input is less or equal to 0.



I used the variable n as the number to input by the user.



I am really new to programming and I am eager to finish this program as soon as possible. Can you please assist?



  #include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;


int main()
{
double n;
cout << "Welcome to this program... Hope you like it" << flush << endl;
do
{
int i, fact = 1, n;
cout << "Please enter a value for the variable " "n: ";
cin >> n;

for (i = 1; i <= n; i++) {
fact = fact * i;
}
cout << "Factorial of " << n << " is: " << fact << endl;
cout << " Thanks for using this program... hope you liked it!" << endl;
} while (n >= 0);
return 0;
}









share|improve this question













i was wondering what can I do to prompt an error when I input a negative number. I used a for loop for this program. What this program does, or at least its supposed to do, is to output the factor of any given number (if positive). But I am not sure how to make my code to prompt an error or at least keep asking for a number if the number that input is less or equal to 0.



I used the variable n as the number to input by the user.



I am really new to programming and I am eager to finish this program as soon as possible. Can you please assist?



  #include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;


int main()
{
double n;
cout << "Welcome to this program... Hope you like it" << flush << endl;
do
{
int i, fact = 1, n;
cout << "Please enter a value for the variable " "n: ";
cin >> n;

for (i = 1; i <= n; i++) {
fact = fact * i;
}
cout << "Factorial of " << n << " is: " << fact << endl;
cout << " Thanks for using this program... hope you liked it!" << endl;
} while (n >= 0);
return 0;
}






c++ visual-studio-2010 visual-c++






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asked Nov 20 at 0:35









Diego Montilla

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161








  • 6




    Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
    – user4581301
    Nov 20 at 0:41










  • Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
    – user4581301
    Nov 20 at 0:46














  • 6




    Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
    – user4581301
    Nov 20 at 0:41










  • Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
    – user4581301
    Nov 20 at 0:46








6




6




Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
– user4581301
Nov 20 at 0:41




Wait. You have 2 ns. Best not to do this. It's legal since they are in different scopes, but it's source of confusion.
– user4581301
Nov 20 at 0:41












Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
– user4581301
Nov 20 at 0:46




Consider drawing a picture of what you want the code to do. Then draw a picture of what the code does. Them move the code around until the picture of what the code does matches what the code should do.
– user4581301
Nov 20 at 0:46












1 Answer
1






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0
down vote













Commens in the code:



#include <iostream>

// it's best not to do using namespace std. It's a huge namespace

int main()
{
std::cout << "Welcome to this program... Hope you like itn";
do
{
int i, fact = 1, n;
std::cout << "Please enter a value for the variable " "n: ";
std::cin >> n;

// if std::cin is in a failed state then break out of the loop.
if (std::cin.fail()) break;

// added check if n<0. if n<0 ptint error on stderr
if (n<0) {
std::clog << "Error: you must supply a number equal to or greater than zeron";
} else { // if n>=0
for (i = 1; i <= n; i++) {
fact = fact * i;
}
std::cout << "Factorial of " << n << " is: " << fact << "n";
}
} while (true); // <- now always true

std::cout << "nThanks for using this program... hope you liked it!n";
return 0;
}





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    1 Answer
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    up vote
    0
    down vote













    Commens in the code:



    #include <iostream>

    // it's best not to do using namespace std. It's a huge namespace

    int main()
    {
    std::cout << "Welcome to this program... Hope you like itn";
    do
    {
    int i, fact = 1, n;
    std::cout << "Please enter a value for the variable " "n: ";
    std::cin >> n;

    // if std::cin is in a failed state then break out of the loop.
    if (std::cin.fail()) break;

    // added check if n<0. if n<0 ptint error on stderr
    if (n<0) {
    std::clog << "Error: you must supply a number equal to or greater than zeron";
    } else { // if n>=0
    for (i = 1; i <= n; i++) {
    fact = fact * i;
    }
    std::cout << "Factorial of " << n << " is: " << fact << "n";
    }
    } while (true); // <- now always true

    std::cout << "nThanks for using this program... hope you liked it!n";
    return 0;
    }





    share|improve this answer



























      up vote
      0
      down vote













      Commens in the code:



      #include <iostream>

      // it's best not to do using namespace std. It's a huge namespace

      int main()
      {
      std::cout << "Welcome to this program... Hope you like itn";
      do
      {
      int i, fact = 1, n;
      std::cout << "Please enter a value for the variable " "n: ";
      std::cin >> n;

      // if std::cin is in a failed state then break out of the loop.
      if (std::cin.fail()) break;

      // added check if n<0. if n<0 ptint error on stderr
      if (n<0) {
      std::clog << "Error: you must supply a number equal to or greater than zeron";
      } else { // if n>=0
      for (i = 1; i <= n; i++) {
      fact = fact * i;
      }
      std::cout << "Factorial of " << n << " is: " << fact << "n";
      }
      } while (true); // <- now always true

      std::cout << "nThanks for using this program... hope you liked it!n";
      return 0;
      }





      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        Commens in the code:



        #include <iostream>

        // it's best not to do using namespace std. It's a huge namespace

        int main()
        {
        std::cout << "Welcome to this program... Hope you like itn";
        do
        {
        int i, fact = 1, n;
        std::cout << "Please enter a value for the variable " "n: ";
        std::cin >> n;

        // if std::cin is in a failed state then break out of the loop.
        if (std::cin.fail()) break;

        // added check if n<0. if n<0 ptint error on stderr
        if (n<0) {
        std::clog << "Error: you must supply a number equal to or greater than zeron";
        } else { // if n>=0
        for (i = 1; i <= n; i++) {
        fact = fact * i;
        }
        std::cout << "Factorial of " << n << " is: " << fact << "n";
        }
        } while (true); // <- now always true

        std::cout << "nThanks for using this program... hope you liked it!n";
        return 0;
        }





        share|improve this answer














        Commens in the code:



        #include <iostream>

        // it's best not to do using namespace std. It's a huge namespace

        int main()
        {
        std::cout << "Welcome to this program... Hope you like itn";
        do
        {
        int i, fact = 1, n;
        std::cout << "Please enter a value for the variable " "n: ";
        std::cin >> n;

        // if std::cin is in a failed state then break out of the loop.
        if (std::cin.fail()) break;

        // added check if n<0. if n<0 ptint error on stderr
        if (n<0) {
        std::clog << "Error: you must supply a number equal to or greater than zeron";
        } else { // if n>=0
        for (i = 1; i <= n; i++) {
        fact = fact * i;
        }
        std::cout << "Factorial of " << n << " is: " << fact << "n";
        }
        } while (true); // <- now always true

        std::cout << "nThanks for using this program... hope you liked it!n";
        return 0;
        }






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        share|improve this answer








        edited Nov 20 at 6:30

























        answered Nov 20 at 0:53









        Ted Lyngmo

        1,368214




        1,368214






























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