Removing an Edge from a Mouse Click that is NOT on the edge











up vote
0
down vote

favorite












I have a GUI application demonstrating undirected Graph structure. The Gui is available in here. One of the features is delete an edge between two vertices. So to delete an edge from the graph (GUI) a user can have two options. A user can hover over the mouse on the edge and click on it to delete that edge. Below is the following code for that part -



// assume there are some defined vertices v1, v2, ...
// an edge has an instance variable of Line class
// also assume that all vertices and edges are unique

Edge edge = new Edge(v1, v2);
edge.getLine().setCursor(Cursor.CROSSHAIR);
edge.getLine().setOnMouseClicked(e ->
view.getCenter().getChildren().remove(edge.getLine()));
graph.addEdge(v1, v2, edge);
view.getCenter().getChildren().add(edge.getLine());


and the second option is a user can click on the closet edge he/she wants to delete instead of clicking on the edge. Assume he/she is not clicking on the intersection of a line. The picture shows the problem. enter image description here. Let's consider a user wants to delete the Orange edge and the red coordinates show where a user clicked. Is there a way to delete the closest edge based on the click?










share|improve this question




























    up vote
    0
    down vote

    favorite












    I have a GUI application demonstrating undirected Graph structure. The Gui is available in here. One of the features is delete an edge between two vertices. So to delete an edge from the graph (GUI) a user can have two options. A user can hover over the mouse on the edge and click on it to delete that edge. Below is the following code for that part -



    // assume there are some defined vertices v1, v2, ...
    // an edge has an instance variable of Line class
    // also assume that all vertices and edges are unique

    Edge edge = new Edge(v1, v2);
    edge.getLine().setCursor(Cursor.CROSSHAIR);
    edge.getLine().setOnMouseClicked(e ->
    view.getCenter().getChildren().remove(edge.getLine()));
    graph.addEdge(v1, v2, edge);
    view.getCenter().getChildren().add(edge.getLine());


    and the second option is a user can click on the closet edge he/she wants to delete instead of clicking on the edge. Assume he/she is not clicking on the intersection of a line. The picture shows the problem. enter image description here. Let's consider a user wants to delete the Orange edge and the red coordinates show where a user clicked. Is there a way to delete the closest edge based on the click?










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a GUI application demonstrating undirected Graph structure. The Gui is available in here. One of the features is delete an edge between two vertices. So to delete an edge from the graph (GUI) a user can have two options. A user can hover over the mouse on the edge and click on it to delete that edge. Below is the following code for that part -



      // assume there are some defined vertices v1, v2, ...
      // an edge has an instance variable of Line class
      // also assume that all vertices and edges are unique

      Edge edge = new Edge(v1, v2);
      edge.getLine().setCursor(Cursor.CROSSHAIR);
      edge.getLine().setOnMouseClicked(e ->
      view.getCenter().getChildren().remove(edge.getLine()));
      graph.addEdge(v1, v2, edge);
      view.getCenter().getChildren().add(edge.getLine());


      and the second option is a user can click on the closet edge he/she wants to delete instead of clicking on the edge. Assume he/she is not clicking on the intersection of a line. The picture shows the problem. enter image description here. Let's consider a user wants to delete the Orange edge and the red coordinates show where a user clicked. Is there a way to delete the closest edge based on the click?










      share|improve this question















      I have a GUI application demonstrating undirected Graph structure. The Gui is available in here. One of the features is delete an edge between two vertices. So to delete an edge from the graph (GUI) a user can have two options. A user can hover over the mouse on the edge and click on it to delete that edge. Below is the following code for that part -



      // assume there are some defined vertices v1, v2, ...
      // an edge has an instance variable of Line class
      // also assume that all vertices and edges are unique

      Edge edge = new Edge(v1, v2);
      edge.getLine().setCursor(Cursor.CROSSHAIR);
      edge.getLine().setOnMouseClicked(e ->
      view.getCenter().getChildren().remove(edge.getLine()));
      graph.addEdge(v1, v2, edge);
      view.getCenter().getChildren().add(edge.getLine());


      and the second option is a user can click on the closet edge he/she wants to delete instead of clicking on the edge. Assume he/she is not clicking on the intersection of a line. The picture shows the problem. enter image description here. Let's consider a user wants to delete the Orange edge and the red coordinates show where a user clicked. Is there a way to delete the closest edge based on the click?







      java object-oriented graph javafx






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 5 mins ago

























      asked 1 hour ago









      Hamidur Rahman

      436




      436



























          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "196"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














           

          draft saved


          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208494%2fremoving-an-edge-from-a-mouse-click-that-is-not-on-the-edge%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















           

          draft saved


          draft discarded



















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208494%2fremoving-an-edge-from-a-mouse-click-that-is-not-on-the-edge%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          404 Error Contact Form 7 ajax form submitting

          How to know if a Active Directory user can login interactively

          TypeError: fit_transform() missing 1 required positional argument: 'X'