Access the column using column header from variable [closed]

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0
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dist <- array(5, dim = c(61,61), dimnames = list(c(1:61),c(1:61)))



dist <- dist[-23,-29]



y <- 61

now I want to access the column with header = y, i.e. in this case dist$'61'
However, I want to do it in terms of y.

I have tried dist$y, dist$y and dist$'get("y")' but all of these returned NULL.

Can someone please help me with this syntax?

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

closed as off-topic by Cath, Jaap, Sotos, phiver, wp78de Nov 19 at 18:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Cath, Jaap, Sotos, phiver, wp78de

If this question can be reworded to fit the rules in the help center, please edit the question.

2

$ is not suitable for arrays (it is quite surprising that it returns NULL and not an error). You can access the column "61" with dist[, as.character(y)] (or directly defining y as y <- "61").
– Cath
Nov 19 at 15:27

2

Or dist[,colnames(dist) %in% y]
– Sotos
Nov 19 at 15:30

add a comment |

up vote
0
down vote

favorite

dist <- array(5, dim = c(61,61), dimnames = list(c(1:61),c(1:61)))



dist <- dist[-23,-29]



y <- 61

now I want to access the column with header = y, i.e. in this case dist$'61'
However, I want to do it in terms of y.

I have tried dist$y, dist$y and dist$'get("y")' but all of these returned NULL.

Can someone please help me with this syntax?

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

closed as off-topic by Cath, Jaap, Sotos, phiver, wp78de Nov 19 at 18:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Cath, Jaap, Sotos, phiver, wp78de

If this question can be reworded to fit the rules in the help center, please edit the question.

2

$ is not suitable for arrays (it is quite surprising that it returns NULL and not an error). You can access the column "61" with dist[, as.character(y)] (or directly defining y as y <- "61").
– Cath
Nov 19 at 15:27

2

Or dist[,colnames(dist) %in% y]
– Sotos
Nov 19 at 15:30

add a comment |

up vote
0
down vote

favorite

dist <- array(5, dim = c(61,61), dimnames = list(c(1:61),c(1:61)))



dist <- dist[-23,-29]



y <- 61

now I want to access the column with header = y, i.e. in this case dist$'61'
However, I want to do it in terms of y.

I have tried dist$y, dist$y and dist$'get("y")' but all of these returned NULL.

Can someone please help me with this syntax?

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

dist <- array(5, dim = c(61,61), dimnames = list(c(1:61),c(1:61)))



dist <- dist[-23,-29]



y <- 61

now I want to access the column with header = y, i.e. in this case dist$'61'
However, I want to do it in terms of y.

I have tried dist$y, dist$y and dist$'get("y")' but all of these returned NULL.

Can someone please help me with this syntax?

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

edited Nov 19 at 15:22

Sotos

27k51540

edited Nov 19 at 15:22

Sotos

27k51540

edited Nov 19 at 15:22

Sotos

27k51540

asked Nov 19 at 15:19

Saumya Pendyala

asked Nov 19 at 15:19

Saumya Pendyala

asked Nov 19 at 15:19

Saumya Pendyala

closed as off-topic by Cath, Jaap, Sotos, phiver, wp78de Nov 19 at 18:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Cath, Jaap, Sotos, phiver, wp78de

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by Cath, Jaap, Sotos, phiver, wp78de Nov 19 at 18:09

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – Cath, Jaap, Sotos, phiver, wp78de

If this question can be reworded to fit the rules in the help center, please edit the question.

2

$ is not suitable for arrays (it is quite surprising that it returns NULL and not an error). You can access the column "61" with dist[, as.character(y)] (or directly defining y as y <- "61").
– Cath
Nov 19 at 15:27

2

Or dist[,colnames(dist) %in% y]
– Sotos
Nov 19 at 15:30

add a comment |

2

$ is not suitable for arrays (it is quite surprising that it returns NULL and not an error). You can access the column "61" with dist[, as.character(y)] (or directly defining y as y <- "61").
– Cath
Nov 19 at 15:27

2

Or dist[,colnames(dist) %in% y]
– Sotos
Nov 19 at 15:30

$ is not suitable for arrays (it is quite surprising that it returns NULL and not an error). You can access the column "61" with dist[, as.character(y)] (or directly defining y as y <- "61").
– Cath
Nov 19 at 15:27

Or dist[,colnames(dist) %in% y]
– Sotos
Nov 19 at 15:30

add a comment |

2 Answers
2

active

oldest

votes

up vote
0
down vote

By doing dist <- dist[-23,-29] you removed a line and a column, meaning that dist[, y] with y equal to 61 is now out of bounds. But you know that already.

Indeed what you need to do is to select the name 61, and therefore
dist[, as.character(y)] should give you what you want.

answered Nov 19 at 15:26

fzenoni

1114

add a comment |

up vote
0
down vote

dist$y expects y to be the actual name of the column.

If y is a variable containing the name of the column, you want to use the following syntax:
dist[, y]

Make sure that y is a character!

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

1

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

add a comment |

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

By doing dist <- dist[-23,-29] you removed a line and a column, meaning that dist[, y] with y equal to 61 is now out of bounds. But you know that already.

Indeed what you need to do is to select the name 61, and therefore
dist[, as.character(y)] should give you what you want.

answered Nov 19 at 15:26

fzenoni

1114

add a comment |

up vote
0
down vote

By doing dist <- dist[-23,-29] you removed a line and a column, meaning that dist[, y] with y equal to 61 is now out of bounds. But you know that already.

Indeed what you need to do is to select the name 61, and therefore
dist[, as.character(y)] should give you what you want.

answered Nov 19 at 15:26

fzenoni

1114

add a comment |

up vote
0
down vote

By doing dist <- dist[-23,-29] you removed a line and a column, meaning that dist[, y] with y equal to 61 is now out of bounds. But you know that already.

Indeed what you need to do is to select the name 61, and therefore
dist[, as.character(y)] should give you what you want.

answered Nov 19 at 15:26

fzenoni

1114

By doing dist <- dist[-23,-29] you removed a line and a column, meaning that dist[, y] with y equal to 61 is now out of bounds. But you know that already.

Indeed what you need to do is to select the name 61, and therefore
dist[, as.character(y)] should give you what you want.

answered Nov 19 at 15:26

fzenoni

1114

answered Nov 19 at 15:26

fzenoni

1114

answered Nov 19 at 15:26

fzenoni

1114

answered Nov 19 at 15:26

fzenoni

1114

add a comment |

up vote
0
down vote

dist$y expects y to be the actual name of the column.

If y is a variable containing the name of the column, you want to use the following syntax:
dist[, y]

Make sure that y is a character!

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

1

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

add a comment |

up vote
0
down vote

dist$y expects y to be the actual name of the column.

If y is a variable containing the name of the column, you want to use the following syntax:
dist[, y]

Make sure that y is a character!

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

1

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

add a comment |

up vote
0
down vote

dist$y expects y to be the actual name of the column.

If y is a variable containing the name of the column, you want to use the following syntax:
dist[, y]

Make sure that y is a character!

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

dist$y expects y to be the actual name of the column.

If y is a variable containing the name of the column, you want to use the following syntax:
dist[, y]

Make sure that y is a character!

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

edited Nov 19 at 18:24

answered Nov 19 at 15:22

12b345b6b78

685115

answered Nov 19 at 15:22

12b345b6b78

685115

answered Nov 19 at 15:22

12b345b6b78

685115

1

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

add a comment |

1

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

Did you try that?
– Sotos
Nov 19 at 15:32

I have...but with wrong inputs. My bad!
– 12b345b6b78
Nov 19 at 15:38

add a comment |

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