ggrepel: using position_dodge in combination with geom_label_repel
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I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
asked Nov 19 at 14:58
Ravi
363
add a comment |
up vote
3
down vote
favorite
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
asked Nov 19 at 14:58
Ravi
363
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 at 22:35
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
asked Nov 19 at 14:58
Ravi
363
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
r ggplot2 ggrepel
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
asked Nov 19 at 14:58
Ravi
363
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
asked Nov 19 at 14:58
Ravi
363
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
edited Nov 19 at 15:02
Rui Barradas
14.8k31730
14.8k31730
asked Nov 19 at 14:58
Ravi
363
asked Nov 19 at 14:58
Ravi
363
asked Nov 19 at 14:58
Ravi
363
363
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 at 22:35
add a comment |
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 at 22:35
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 at 22:35
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 at 22:35
add a comment |
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I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 at 22:35