dart JSON String convert to List String
up vote
0
down vote
favorite
I have an API that calls the json String array as follows:
[
"006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"
]
I intend to convert the json to the List in the dart. I tried the script below :
json.decode(response.body).cast<List<String>();
but it didn't work, how should the script be correct?
dart 
flutter edited Nov 20 at 7:10
lrn
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
add a comment |
up vote
0
down vote
favorite
I have an API that calls the json String array as follows:
[
"006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"
]
I intend to convert the json to the List in the dart. I tried the script below :
json.decode(response.body).cast<List<String>();
but it didn't work, how should the script be correct?
dart flutter edited Nov 20 at 7:10
lrn
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have an API that calls the json String array as follows:
[
"006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"
]
I intend to convert the json to the List in the dart. I tried the script below :
json.decode(response.body).cast<List<String>();
but it didn't work, how should the script be correct?
dart flutter edited Nov 20 at 7:10
lrn
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
I have an API that calls the json String array as follows:
[
"006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"
]
I intend to convert the json to the List in the dart. I tried the script below :
json.decode(response.body).cast<List<String>();
but it didn't work, how should the script be correct?
dart flutter dart flutter edited Nov 20 at 7:10
lrn
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
edited Nov 20 at 7:10
lrn
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
edited Nov 20 at 7:10
lrn
9,3741217
edited Nov 20 at 7:10
lrn
9,3741217
edited Nov 20 at 7:10
lrn
9,3741217
9,3741217
asked Nov 19 at 14:15
Denis Ramdan
436
asked Nov 19 at 14:15
Denis Ramdan
436
asked Nov 19 at 14:15
Denis Ramdan
436
436
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Try this one. Hope it helps.
import 'dart:convert';
void main() {
String jsonResponse = '''
["006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"]
''';
dynamic jsonParsed = json.decode(jsonResponse);
// print(jsonParsed);
print(jsonParsed[5]);
}
answered Nov 19 at 14:26
Sagar Tamang
349113
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
add a comment |
up vote
1
down vote
The result of parsing a JSON list is a List<dynamic>. The return type of jsonDecode is just dynamic.
You can cast such a list to a `List as
List<String> stringList = (jsonDecode(input) as List<dynamic>).cast<String>();
You can also just use it as a List<dynamic> and then assign each value to String:
List<dynamic> rellyAStringList = jsonDecode(input);
for (String string in reallyAStringList) { ... }
The effect is approximately the same - each element is checked for being a string when it is taken out of the list.
answered Nov 20 at 7:14
lrn
9,3741217
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Try this one. Hope it helps.
import 'dart:convert';
void main() {
String jsonResponse = '''
["006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"]
''';
dynamic jsonParsed = json.decode(jsonResponse);
// print(jsonParsed);
print(jsonParsed[5]);
}
answered Nov 19 at 14:26
Sagar Tamang
349113
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
add a comment |
up vote
1
down vote
accepted
Try this one. Hope it helps.
import 'dart:convert';
void main() {
String jsonResponse = '''
["006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"]
''';
dynamic jsonParsed = json.decode(jsonResponse);
// print(jsonParsed);
print(jsonParsed[5]);
}
answered Nov 19 at 14:26
Sagar Tamang
349113
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Try this one. Hope it helps.
import 'dart:convert';
void main() {
String jsonResponse = '''
["006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"]
''';
dynamic jsonParsed = json.decode(jsonResponse);
// print(jsonParsed);
print(jsonParsed[5]);
}
answered Nov 19 at 14:26
Sagar Tamang
349113
Try this one. Hope it helps.
import 'dart:convert';
void main() {
String jsonResponse = '''
["006.01.01",
"006.01.01 1090",
"006.01.01 1090 1090.950",
"006.01.01 1090 1090.950 052",
"006.01.01 1090 1090.950 052 A",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 A 521219",
"006.01.01 1090 1090.950 052 B",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.950 052 B 521211",
"006.01.01 1090 1090.994",
"006.01.01 1090 1090.994 001",
"006.01.01 1090 1090.994 001 A",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111",
"006.01.01 1090 1090.994 001 A 511111"]
''';
dynamic jsonParsed = json.decode(jsonResponse);
// print(jsonParsed);
print(jsonParsed[5]);
}
answered Nov 19 at 14:26
Sagar Tamang
349113
answered Nov 19 at 14:26
Sagar Tamang
349113
answered Nov 19 at 14:26
Sagar Tamang
349113
answered Nov 19 at 14:26
Sagar Tamang
349113
349113
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
add a comment |
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
that's greate, thank you..
– Denis Ramdan
Nov 19 at 19:01
add a comment |
up vote
1
down vote
The result of parsing a JSON list is a List<dynamic>. The return type of jsonDecode is just dynamic.
You can cast such a list to a `List as
List<String> stringList = (jsonDecode(input) as List<dynamic>).cast<String>();
You can also just use it as a List<dynamic> and then assign each value to String:
List<dynamic> rellyAStringList = jsonDecode(input);
for (String string in reallyAStringList) { ... }
The effect is approximately the same - each element is checked for being a string when it is taken out of the list.
answered Nov 20 at 7:14
lrn
9,3741217
add a comment |
up vote
1
down vote
The result of parsing a JSON list is a List<dynamic>. The return type of jsonDecode is just dynamic.
You can cast such a list to a `List as
List<String> stringList = (jsonDecode(input) as List<dynamic>).cast<String>();
You can also just use it as a List<dynamic> and then assign each value to String:
List<dynamic> rellyAStringList = jsonDecode(input);
for (String string in reallyAStringList) { ... }
The effect is approximately the same - each element is checked for being a string when it is taken out of the list.
answered Nov 20 at 7:14
lrn
9,3741217
add a comment |
up vote
1
down vote
up vote
1
down vote
The result of parsing a JSON list is a List<dynamic>. The return type of jsonDecode is just dynamic.
You can cast such a list to a `List as
List<String> stringList = (jsonDecode(input) as List<dynamic>).cast<String>();
You can also just use it as a List<dynamic> and then assign each value to String:
List<dynamic> rellyAStringList = jsonDecode(input);
for (String string in reallyAStringList) { ... }
The effect is approximately the same - each element is checked for being a string when it is taken out of the list.
answered Nov 20 at 7:14
lrn
9,3741217
The result of parsing a JSON list is a List<dynamic>. The return type of jsonDecode is just dynamic.
You can cast such a list to a `List as
List<String> stringList = (jsonDecode(input) as List<dynamic>).cast<String>();
You can also just use it as a List<dynamic> and then assign each value to String:
List<dynamic> rellyAStringList = jsonDecode(input);
for (String string in reallyAStringList) { ... }
The effect is approximately the same - each element is checked for being a string when it is taken out of the list.
answered Nov 20 at 7:14
lrn
9,3741217
edited Nov 21 at 19:51
answered Nov 20 at 7:14
lrn
9,3741217
answered Nov 20 at 7:14
lrn
9,3741217
answered Nov 20 at 7:14
lrn
9,3741217
9,3741217
add a comment |
add a comment |
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