Search files into a directory / compatible Unix / Windows











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i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".



Based on what I found so far, here is my code :



def import_files_list(path, key_word):
files =
for i in os.listdir(path):
if os.path.isfile(os.path.join(path,i)) and key_word in i:
file_plus_path = path+i
pprint(file_plus_path)
files.append(file_plus_path)
return files

actual_dir = os.path.dirname(os.path.realpath(__file__))
wanted_dir = os.path.split(actual_dir)[0]
files_list = import_files_list(wanted_dir, 'example')
pprint(files_list)


The thing is that, instead of getting for instance :



'C:\Users\User\folder\example1.csv'


I'm getting :



'C:\Users\User\folderexample1.csv'


So this is not correct.



I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.



Could you help me and tell me here I am wrong ?










share|improve this question







New contributor




SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    up vote
    0
    down vote

    favorite












    i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".



    Based on what I found so far, here is my code :



    def import_files_list(path, key_word):
    files =
    for i in os.listdir(path):
    if os.path.isfile(os.path.join(path,i)) and key_word in i:
    file_plus_path = path+i
    pprint(file_plus_path)
    files.append(file_plus_path)
    return files

    actual_dir = os.path.dirname(os.path.realpath(__file__))
    wanted_dir = os.path.split(actual_dir)[0]
    files_list = import_files_list(wanted_dir, 'example')
    pprint(files_list)


    The thing is that, instead of getting for instance :



    'C:\Users\User\folder\example1.csv'


    I'm getting :



    'C:\Users\User\folderexample1.csv'


    So this is not correct.



    I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.



    Could you help me and tell me here I am wrong ?










    share|improve this question







    New contributor




    SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".



      Based on what I found so far, here is my code :



      def import_files_list(path, key_word):
      files =
      for i in os.listdir(path):
      if os.path.isfile(os.path.join(path,i)) and key_word in i:
      file_plus_path = path+i
      pprint(file_plus_path)
      files.append(file_plus_path)
      return files

      actual_dir = os.path.dirname(os.path.realpath(__file__))
      wanted_dir = os.path.split(actual_dir)[0]
      files_list = import_files_list(wanted_dir, 'example')
      pprint(files_list)


      The thing is that, instead of getting for instance :



      'C:\Users\User\folder\example1.csv'


      I'm getting :



      'C:\Users\User\folderexample1.csv'


      So this is not correct.



      I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.



      Could you help me and tell me here I am wrong ?










      share|improve this question







      New contributor




      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      i'm a beginner in Python, and try to use the os module to find and aggregate all files in a given folder, given a key word such as "example".



      Based on what I found so far, here is my code :



      def import_files_list(path, key_word):
      files =
      for i in os.listdir(path):
      if os.path.isfile(os.path.join(path,i)) and key_word in i:
      file_plus_path = path+i
      pprint(file_plus_path)
      files.append(file_plus_path)
      return files

      actual_dir = os.path.dirname(os.path.realpath(__file__))
      wanted_dir = os.path.split(actual_dir)[0]
      files_list = import_files_list(wanted_dir, 'example')
      pprint(files_list)


      The thing is that, instead of getting for instance :



      'C:\Users\User\folder\example1.csv'


      I'm getting :



      'C:\Users\User\folderexample1.csv'


      So this is not correct.



      I don't want to hardcode anything such as "" to solve the problem, and I'm pretty sure I could also simplify the above code.



      Could you help me and tell me here I am wrong ?







      python






      share|improve this question







      New contributor




      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked Nov 19 at 14:14









      SidGabriel

      123




      123




      New contributor




      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      SidGabriel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          Your problem is this line:



              file_plus_path = path+i


          Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).



          So here's a way to correct that:



          file_plus_path = os.path.join(path,i)
          if os.path.isfile(file_plus_path) and key_word in i:
          pprint(file_plus_path)
          files.append(file_plus_path)





          share|improve this answer





















          • You're right ! It solved my mistake :) Thank you !
            – SidGabriel
            Nov 19 at 14:27











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          1 Answer
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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          Your problem is this line:



              file_plus_path = path+i


          Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).



          So here's a way to correct that:



          file_plus_path = os.path.join(path,i)
          if os.path.isfile(file_plus_path) and key_word in i:
          pprint(file_plus_path)
          files.append(file_plus_path)





          share|improve this answer





















          • You're right ! It solved my mistake :) Thank you !
            – SidGabriel
            Nov 19 at 14:27















          up vote
          0
          down vote



          accepted










          Your problem is this line:



              file_plus_path = path+i


          Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).



          So here's a way to correct that:



          file_plus_path = os.path.join(path,i)
          if os.path.isfile(file_plus_path) and key_word in i:
          pprint(file_plus_path)
          files.append(file_plus_path)





          share|improve this answer





















          • You're right ! It solved my mistake :) Thank you !
            – SidGabriel
            Nov 19 at 14:27













          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          Your problem is this line:



              file_plus_path = path+i


          Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).



          So here's a way to correct that:



          file_plus_path = os.path.join(path,i)
          if os.path.isfile(file_plus_path) and key_word in i:
          pprint(file_plus_path)
          files.append(file_plus_path)





          share|improve this answer












          Your problem is this line:



              file_plus_path = path+i


          Here you append one string to another, but without any delimiter between them. On the previous line you did it correctly: os.path.join(path,i).



          So here's a way to correct that:



          file_plus_path = os.path.join(path,i)
          if os.path.isfile(file_plus_path) and key_word in i:
          pprint(file_plus_path)
          files.append(file_plus_path)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 19 at 14:20









          dsh

          10.1k22141




          10.1k22141












          • You're right ! It solved my mistake :) Thank you !
            – SidGabriel
            Nov 19 at 14:27


















          • You're right ! It solved my mistake :) Thank you !
            – SidGabriel
            Nov 19 at 14:27
















          You're right ! It solved my mistake :) Thank you !
          – SidGabriel
          Nov 19 at 14:27




          You're right ! It solved my mistake :) Thank you !
          – SidGabriel
          Nov 19 at 14:27










          SidGabriel is a new contributor. Be nice, and check out our Code of Conduct.










           

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