Will printf still has a cost even I redirect output to /dev/null?












8















We have a daemon contains a lot of print message. Since we working on a embedded device with a weak CPU and other constraint hardware, we want to minimize any kinds of costs(IO, CPU,etc..) of printf message in our final version. (Users don't have a console)



My teammates and I have a disagreement. He think we can just redirect everything to /dev/null. It won't cost any IO so affections will be minimal. But I think it will still cost CPU and we better define a macro for printf so we can rewrite "printf"(maybe just return).



So I need some opinions about who is right. Will Linux smart enough to optimize printf? I really doubt it.










share|improve this question


















  • 2





    Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

    – pmg
    3 hours ago








  • 1





    Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

    – msrd0
    3 hours ago
















8















We have a daemon contains a lot of print message. Since we working on a embedded device with a weak CPU and other constraint hardware, we want to minimize any kinds of costs(IO, CPU,etc..) of printf message in our final version. (Users don't have a console)



My teammates and I have a disagreement. He think we can just redirect everything to /dev/null. It won't cost any IO so affections will be minimal. But I think it will still cost CPU and we better define a macro for printf so we can rewrite "printf"(maybe just return).



So I need some opinions about who is right. Will Linux smart enough to optimize printf? I really doubt it.










share|improve this question


















  • 2





    Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

    – pmg
    3 hours ago








  • 1





    Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

    – msrd0
    3 hours ago














8












8








8








We have a daemon contains a lot of print message. Since we working on a embedded device with a weak CPU and other constraint hardware, we want to minimize any kinds of costs(IO, CPU,etc..) of printf message in our final version. (Users don't have a console)



My teammates and I have a disagreement. He think we can just redirect everything to /dev/null. It won't cost any IO so affections will be minimal. But I think it will still cost CPU and we better define a macro for printf so we can rewrite "printf"(maybe just return).



So I need some opinions about who is right. Will Linux smart enough to optimize printf? I really doubt it.










share|improve this question














We have a daemon contains a lot of print message. Since we working on a embedded device with a weak CPU and other constraint hardware, we want to minimize any kinds of costs(IO, CPU,etc..) of printf message in our final version. (Users don't have a console)



My teammates and I have a disagreement. He think we can just redirect everything to /dev/null. It won't cost any IO so affections will be minimal. But I think it will still cost CPU and we better define a macro for printf so we can rewrite "printf"(maybe just return).



So I need some opinions about who is right. Will Linux smart enough to optimize printf? I really doubt it.







c linux






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 3 hours ago









Michael PengMichael Peng

1189




1189








  • 2





    Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

    – pmg
    3 hours ago








  • 1





    Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

    – msrd0
    3 hours ago














  • 2





    Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

    – pmg
    3 hours ago








  • 1





    Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

    – msrd0
    3 hours ago








2




2





Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

– pmg
3 hours ago







Beware side effects: printf("%d", x=a+b); If you redirect to /dev/null side effects will happen; if you rewrite as a do nothing macro, side effects will be lost

– pmg
3 hours ago






1




1





Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

– msrd0
3 hours ago





Providing a myprintf(...) { return; } is probably what you want. You can then have a macro for printf forwarding to that method, preserving side effects yet not formatting any string or calling write

– msrd0
3 hours ago












4 Answers
4






active

oldest

votes


















13














Pretty much.



Although in theory, the program could detect /dev/null and perform some optimizations within the restrictions of standards they comply to, based on general understanding of common implementations, they practically don't (i.e. I am unaware of any Unix or Linux system doing so). You can read Damon's answer for details about POSIX standard requirements.



When you redirect the stdout of the program to /dev/null, any call to printf(3) will still evaluate all the arguments (beware side effects like a++), and the string formatting will still take place before calling write(2), which writes the full formatted string to the standard output of the process. It's at the kernel level that the data isn't written to disk, but discarded by the handler associated with the special device /dev/null. Therefore I see little improvement in terms of performance, unless your disk or terminal is considerably slow. Disk and RAM capacity (for terminals) may be another concern, though.



Be aware that if you replace printf completely, some side effects may go wrong, for example printf("%d%n", a++, &b).






share|improve this answer





















  • 4





    Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

    – Eric Postpischil
    1 hour ago






  • 1





    @EricPostpischil Thanks for that! Very valuable information.

    – iBug
    1 hour ago



















6














The printf function writes to stdout. If the file descriptor connected to stdout is redirected to /dev/null then no output will be written anywhere (but it will still be written), but the call to printf itself and the formatting it does will still happen.






share|improve this answer





















  • 1





    @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

    – glglgl
    3 hours ago






  • 1





    Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

    – Eric Postpischil
    1 hour ago



















1














Generally speaking, an implementation is permitted to perform such optimisations if they do not affect the observable (functional) outputs of the program. In the case of printf(), that would mean that if the program doesn't use the return value, and if there are no %n conversions, then the implementation would be allowed to do nothing.



In practice, I'm not aware of any implementation on Linux that currently (early 2019) performs such an optimisation - the compilers and libraries I'm familiar with will format the output and write the result to the null device, relying on the kernel' to ignore it.



You may want to write a forwarding function of your own if you really need to save the cost of formatting when the output is not used - you'll want to it to return void, and you should check the format string for %n. (You could use snprintf with a NULL and 0 buffer if you need those side-effects, but the savings are unlikely to repay the effort invested).






share|improve this answer































    1














    The printf function will write to stdout. It is not conforming to optimize for /dev/null.
    Therefore, you will have the overhead of parsing the format string and evaluating any necessary arguments, and you will have at least one syscall, plus you will copy a buffer to kernel address space (which, compared to the cost of the syscall is neglegible).



    This answer is based on the specific documentation of POSIX.




    System Interfaces

    dprintf, fprintf, printf, snprintf, sprintf - print formatted output



    The fprintf() function shall place output on the named output stream. The printf() function shall place output on the standard output stream stdout. The sprintf() function shall place output followed by the null byte, '', in consecutive bytes starting at *s; it is the user's responsibility to ensure that enough space is available.



    Base Definitions

    shall

    For an implementation that conforms to POSIX.1-2017, describes a feature or behavior that is mandatory. An application can rely on the existence of the feature or behavior.






    share























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      13














      Pretty much.



      Although in theory, the program could detect /dev/null and perform some optimizations within the restrictions of standards they comply to, based on general understanding of common implementations, they practically don't (i.e. I am unaware of any Unix or Linux system doing so). You can read Damon's answer for details about POSIX standard requirements.



      When you redirect the stdout of the program to /dev/null, any call to printf(3) will still evaluate all the arguments (beware side effects like a++), and the string formatting will still take place before calling write(2), which writes the full formatted string to the standard output of the process. It's at the kernel level that the data isn't written to disk, but discarded by the handler associated with the special device /dev/null. Therefore I see little improvement in terms of performance, unless your disk or terminal is considerably slow. Disk and RAM capacity (for terminals) may be another concern, though.



      Be aware that if you replace printf completely, some side effects may go wrong, for example printf("%d%n", a++, &b).






      share|improve this answer





















      • 4





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago






      • 1





        @EricPostpischil Thanks for that! Very valuable information.

        – iBug
        1 hour ago
















      13














      Pretty much.



      Although in theory, the program could detect /dev/null and perform some optimizations within the restrictions of standards they comply to, based on general understanding of common implementations, they practically don't (i.e. I am unaware of any Unix or Linux system doing so). You can read Damon's answer for details about POSIX standard requirements.



      When you redirect the stdout of the program to /dev/null, any call to printf(3) will still evaluate all the arguments (beware side effects like a++), and the string formatting will still take place before calling write(2), which writes the full formatted string to the standard output of the process. It's at the kernel level that the data isn't written to disk, but discarded by the handler associated with the special device /dev/null. Therefore I see little improvement in terms of performance, unless your disk or terminal is considerably slow. Disk and RAM capacity (for terminals) may be another concern, though.



      Be aware that if you replace printf completely, some side effects may go wrong, for example printf("%d%n", a++, &b).






      share|improve this answer





















      • 4





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago






      • 1





        @EricPostpischil Thanks for that! Very valuable information.

        – iBug
        1 hour ago














      13












      13








      13







      Pretty much.



      Although in theory, the program could detect /dev/null and perform some optimizations within the restrictions of standards they comply to, based on general understanding of common implementations, they practically don't (i.e. I am unaware of any Unix or Linux system doing so). You can read Damon's answer for details about POSIX standard requirements.



      When you redirect the stdout of the program to /dev/null, any call to printf(3) will still evaluate all the arguments (beware side effects like a++), and the string formatting will still take place before calling write(2), which writes the full formatted string to the standard output of the process. It's at the kernel level that the data isn't written to disk, but discarded by the handler associated with the special device /dev/null. Therefore I see little improvement in terms of performance, unless your disk or terminal is considerably slow. Disk and RAM capacity (for terminals) may be another concern, though.



      Be aware that if you replace printf completely, some side effects may go wrong, for example printf("%d%n", a++, &b).






      share|improve this answer















      Pretty much.



      Although in theory, the program could detect /dev/null and perform some optimizations within the restrictions of standards they comply to, based on general understanding of common implementations, they practically don't (i.e. I am unaware of any Unix or Linux system doing so). You can read Damon's answer for details about POSIX standard requirements.



      When you redirect the stdout of the program to /dev/null, any call to printf(3) will still evaluate all the arguments (beware side effects like a++), and the string formatting will still take place before calling write(2), which writes the full formatted string to the standard output of the process. It's at the kernel level that the data isn't written to disk, but discarded by the handler associated with the special device /dev/null. Therefore I see little improvement in terms of performance, unless your disk or terminal is considerably slow. Disk and RAM capacity (for terminals) may be another concern, though.



      Be aware that if you replace printf completely, some side effects may go wrong, for example printf("%d%n", a++, &b).







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 1 min ago

























      answered 3 hours ago









      iBugiBug

      19.4k53363




      19.4k53363








      • 4





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago






      • 1





        @EricPostpischil Thanks for that! Very valuable information.

        – iBug
        1 hour ago














      • 4





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago






      • 1





        @EricPostpischil Thanks for that! Very valuable information.

        – iBug
        1 hour ago








      4




      4





      Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

      – Eric Postpischil
      1 hour ago





      Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

      – Eric Postpischil
      1 hour ago




      1




      1





      @EricPostpischil Thanks for that! Very valuable information.

      – iBug
      1 hour ago





      @EricPostpischil Thanks for that! Very valuable information.

      – iBug
      1 hour ago













      6














      The printf function writes to stdout. If the file descriptor connected to stdout is redirected to /dev/null then no output will be written anywhere (but it will still be written), but the call to printf itself and the formatting it does will still happen.






      share|improve this answer





















      • 1





        @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

        – glglgl
        3 hours ago






      • 1





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago
















      6














      The printf function writes to stdout. If the file descriptor connected to stdout is redirected to /dev/null then no output will be written anywhere (but it will still be written), but the call to printf itself and the formatting it does will still happen.






      share|improve this answer





















      • 1





        @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

        – glglgl
        3 hours ago






      • 1





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago














      6












      6








      6







      The printf function writes to stdout. If the file descriptor connected to stdout is redirected to /dev/null then no output will be written anywhere (but it will still be written), but the call to printf itself and the formatting it does will still happen.






      share|improve this answer















      The printf function writes to stdout. If the file descriptor connected to stdout is redirected to /dev/null then no output will be written anywhere (but it will still be written), but the call to printf itself and the formatting it does will still happen.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 3 hours ago

























      answered 3 hours ago









      Some programmer dudeSome programmer dude

      296k24250411




      296k24250411








      • 1





        @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

        – glglgl
        3 hours ago






      • 1





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago














      • 1





        @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

        – glglgl
        3 hours ago






      • 1





        Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

        – Eric Postpischil
        1 hour ago








      1




      1





      @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

      – glglgl
      3 hours ago





      @OP: Addition: You can further reduce the cost of printf() by creating a new driver which provides a new FILE * (depending on if your platform supports that). In this case, you can create a data sink which discards the data. The cost for formatting etc. still remains, but the OS call for writing to /dev/null goes away.

      – glglgl
      3 hours ago




      1




      1





      Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

      – Eric Postpischil
      1 hour ago





      Answers like this should state they are based on general understanding of common implementations and not upon specific documentation. In theory, there is no reason a C implementation might not inspect stdout, learn it is /dev/null, and suppress printf calls that do not contain %n and whose return value is not used. We cannot really assert nobody has done this, and students ought to learn the provenance of information since an important part of engineering is knowing how you know something (is it specified in a standard, is it just assumed, is it provable, and so on).

      – Eric Postpischil
      1 hour ago











      1














      Generally speaking, an implementation is permitted to perform such optimisations if they do not affect the observable (functional) outputs of the program. In the case of printf(), that would mean that if the program doesn't use the return value, and if there are no %n conversions, then the implementation would be allowed to do nothing.



      In practice, I'm not aware of any implementation on Linux that currently (early 2019) performs such an optimisation - the compilers and libraries I'm familiar with will format the output and write the result to the null device, relying on the kernel' to ignore it.



      You may want to write a forwarding function of your own if you really need to save the cost of formatting when the output is not used - you'll want to it to return void, and you should check the format string for %n. (You could use snprintf with a NULL and 0 buffer if you need those side-effects, but the savings are unlikely to repay the effort invested).






      share|improve this answer




























        1














        Generally speaking, an implementation is permitted to perform such optimisations if they do not affect the observable (functional) outputs of the program. In the case of printf(), that would mean that if the program doesn't use the return value, and if there are no %n conversions, then the implementation would be allowed to do nothing.



        In practice, I'm not aware of any implementation on Linux that currently (early 2019) performs such an optimisation - the compilers and libraries I'm familiar with will format the output and write the result to the null device, relying on the kernel' to ignore it.



        You may want to write a forwarding function of your own if you really need to save the cost of formatting when the output is not used - you'll want to it to return void, and you should check the format string for %n. (You could use snprintf with a NULL and 0 buffer if you need those side-effects, but the savings are unlikely to repay the effort invested).






        share|improve this answer


























          1












          1








          1







          Generally speaking, an implementation is permitted to perform such optimisations if they do not affect the observable (functional) outputs of the program. In the case of printf(), that would mean that if the program doesn't use the return value, and if there are no %n conversions, then the implementation would be allowed to do nothing.



          In practice, I'm not aware of any implementation on Linux that currently (early 2019) performs such an optimisation - the compilers and libraries I'm familiar with will format the output and write the result to the null device, relying on the kernel' to ignore it.



          You may want to write a forwarding function of your own if you really need to save the cost of formatting when the output is not used - you'll want to it to return void, and you should check the format string for %n. (You could use snprintf with a NULL and 0 buffer if you need those side-effects, but the savings are unlikely to repay the effort invested).






          share|improve this answer













          Generally speaking, an implementation is permitted to perform such optimisations if they do not affect the observable (functional) outputs of the program. In the case of printf(), that would mean that if the program doesn't use the return value, and if there are no %n conversions, then the implementation would be allowed to do nothing.



          In practice, I'm not aware of any implementation on Linux that currently (early 2019) performs such an optimisation - the compilers and libraries I'm familiar with will format the output and write the result to the null device, relying on the kernel' to ignore it.



          You may want to write a forwarding function of your own if you really need to save the cost of formatting when the output is not used - you'll want to it to return void, and you should check the format string for %n. (You could use snprintf with a NULL and 0 buffer if you need those side-effects, but the savings are unlikely to repay the effort invested).







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          answered 10 mins ago









          Toby SpeightToby Speight

          16.4k133965




          16.4k133965























              1














              The printf function will write to stdout. It is not conforming to optimize for /dev/null.
              Therefore, you will have the overhead of parsing the format string and evaluating any necessary arguments, and you will have at least one syscall, plus you will copy a buffer to kernel address space (which, compared to the cost of the syscall is neglegible).



              This answer is based on the specific documentation of POSIX.




              System Interfaces

              dprintf, fprintf, printf, snprintf, sprintf - print formatted output



              The fprintf() function shall place output on the named output stream. The printf() function shall place output on the standard output stream stdout. The sprintf() function shall place output followed by the null byte, '', in consecutive bytes starting at *s; it is the user's responsibility to ensure that enough space is available.



              Base Definitions

              shall

              For an implementation that conforms to POSIX.1-2017, describes a feature or behavior that is mandatory. An application can rely on the existence of the feature or behavior.






              share




























                1














                The printf function will write to stdout. It is not conforming to optimize for /dev/null.
                Therefore, you will have the overhead of parsing the format string and evaluating any necessary arguments, and you will have at least one syscall, plus you will copy a buffer to kernel address space (which, compared to the cost of the syscall is neglegible).



                This answer is based on the specific documentation of POSIX.




                System Interfaces

                dprintf, fprintf, printf, snprintf, sprintf - print formatted output



                The fprintf() function shall place output on the named output stream. The printf() function shall place output on the standard output stream stdout. The sprintf() function shall place output followed by the null byte, '', in consecutive bytes starting at *s; it is the user's responsibility to ensure that enough space is available.



                Base Definitions

                shall

                For an implementation that conforms to POSIX.1-2017, describes a feature or behavior that is mandatory. An application can rely on the existence of the feature or behavior.






                share


























                  1












                  1








                  1







                  The printf function will write to stdout. It is not conforming to optimize for /dev/null.
                  Therefore, you will have the overhead of parsing the format string and evaluating any necessary arguments, and you will have at least one syscall, plus you will copy a buffer to kernel address space (which, compared to the cost of the syscall is neglegible).



                  This answer is based on the specific documentation of POSIX.




                  System Interfaces

                  dprintf, fprintf, printf, snprintf, sprintf - print formatted output



                  The fprintf() function shall place output on the named output stream. The printf() function shall place output on the standard output stream stdout. The sprintf() function shall place output followed by the null byte, '', in consecutive bytes starting at *s; it is the user's responsibility to ensure that enough space is available.



                  Base Definitions

                  shall

                  For an implementation that conforms to POSIX.1-2017, describes a feature or behavior that is mandatory. An application can rely on the existence of the feature or behavior.






                  share













                  The printf function will write to stdout. It is not conforming to optimize for /dev/null.
                  Therefore, you will have the overhead of parsing the format string and evaluating any necessary arguments, and you will have at least one syscall, plus you will copy a buffer to kernel address space (which, compared to the cost of the syscall is neglegible).



                  This answer is based on the specific documentation of POSIX.




                  System Interfaces

                  dprintf, fprintf, printf, snprintf, sprintf - print formatted output



                  The fprintf() function shall place output on the named output stream. The printf() function shall place output on the standard output stream stdout. The sprintf() function shall place output followed by the null byte, '', in consecutive bytes starting at *s; it is the user's responsibility to ensure that enough space is available.



                  Base Definitions

                  shall

                  For an implementation that conforms to POSIX.1-2017, describes a feature or behavior that is mandatory. An application can rely on the existence of the feature or behavior.







                  share











                  share


                  share










                  answered 8 mins ago









                  DamonDamon

                  50.8k1599153




                  50.8k1599153






























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