Given a word, how do I find other words in an array with same length and same characters
0
$begingroup$
I tried solving the problem in the following manner; I am just a beginner and wanted to know my mistakes and a more efficient way with better time complexity (if any).
public class Exercise {
public static void main(String args){
String Search="loop";
String letters = Search.split("") ;
int counter;
String words={"loop","pool","lopo","book","kobo"};
for(int i=0;i<words.length;i++)
{
counter=0;
for(int j=0;j<words[i].length();j++)
{
String ssplit = words[i].split("");
if(letters.length==ssplit.length)
{
for(int k=0;k<letters.length;k++)
{
if(letters[j].equals(ssplit[k]))
{
counter++;
break;
}
}
if (counter == 4)
{
System.out.println(words[i]);
}
}
}
}
}
}
java
asked 50 mins ago
AdityaAditya
1
New contributor
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$endgroup$
add a comment |
0
$begingroup$
I tried solving the problem in the following manner; I am just a beginner and wanted to know my mistakes and a more efficient way with better time complexity (if any).
public class Exercise {
public static void main(String args){
String Search="loop";
String letters = Search.split("") ;
int counter;
String words={"loop","pool","lopo","book","kobo"};
for(int i=0;i<words.length;i++)
{
counter=0;
for(int j=0;j<words[i].length();j++)
{
String ssplit = words[i].split("");
if(letters.length==ssplit.length)
{
for(int k=0;k<letters.length;k++)
{
if(letters[j].equals(ssplit[k]))
{
counter++;
break;
}
}
if (counter == 4)
{
System.out.println(words[i]);
}
}
}
}
}
}
java
asked 50 mins ago
AdityaAditya
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
1
$begingroup$
I tried solving the problem in the following manner; I am just a beginner and wanted to know my mistakes and a more efficient way with better time complexity (if any).
public class Exercise {
public static void main(String args){
String Search="loop";
String letters = Search.split("") ;
int counter;
String words={"loop","pool","lopo","book","kobo"};
for(int i=0;i<words.length;i++)
{
counter=0;
for(int j=0;j<words[i].length();j++)
{
String ssplit = words[i].split("");
if(letters.length==ssplit.length)
{
for(int k=0;k<letters.length;k++)
{
if(letters[j].equals(ssplit[k]))
{
counter++;
break;
}
}
if (counter == 4)
{
System.out.println(words[i]);
}
}
}
}
}
}
java
asked 50 mins ago
AdityaAditya
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I tried solving the problem in the following manner; I am just a beginner and wanted to know my mistakes and a more efficient way with better time complexity (if any).
public class Exercise {
public static void main(String args){
String Search="loop";
String letters = Search.split("") ;
int counter;
String words={"loop","pool","lopo","book","kobo"};
for(int i=0;i<words.length;i++)
{
counter=0;
for(int j=0;j<words[i].length();j++)
{
String ssplit = words[i].split("");
if(letters.length==ssplit.length)
{
for(int k=0;k<letters.length;k++)
{
if(letters[j].equals(ssplit[k]))
{
counter++;
break;
}
}
if (counter == 4)
{
System.out.println(words[i]);
}
}
}
}
}
}
java
java
asked 50 mins ago
AdityaAditya
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 50 mins ago
AdityaAditya
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 50 mins ago
AdityaAditya
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 50 mins ago
AdityaAditya
1
asked 50 mins ago
AdityaAditya
1
1
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Aditya is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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