How to find all interactive commands in a shell script using java?
I want to write a java function, that will scan a bash file and find if there are any commands that require user input. I know that there is a command read, designed to capture user input and I think that it is the only one.
I wrote a Validator class that takes a script (simple class that just loads a content of a script to a String variable using Files.readAllBytes(Paths.get(path))).
Here is my Validator class:
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;
public class Validator {
Script script;
String interactiveCommands = {"read"};
public Validator(Script script) {
this.script = script;
}
public void validateInteractiveCommands() {
for (String string : interactiveCommands) {
streamService(string);
}
}
private void streamService(String string) {
try (Stream<String> stream = Files.lines(Paths.get(script.getPath()))) {
stream.filter(lines -> lines.startsWith(string))
.forEach(this::printFound);
} catch (IOException e) {
e.printStackTrace();
}
}
private void printFound(String string) {
System.out.println("Found an interactive command: " + string);
}
}
But in this case I only capture read when it is at the beggining of a line.
And in this case:
if true ; then
read a
fi
it fails to capture read because of 4 spaces.
Is there any simple way that I can handle it using stream or lambdas? Or should I switch to regexp?
java string bash lambda find
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
add a comment |
I want to write a java function, that will scan a bash file and find if there are any commands that require user input. I know that there is a command read, designed to capture user input and I think that it is the only one.
I wrote a Validator class that takes a script (simple class that just loads a content of a script to a String variable using Files.readAllBytes(Paths.get(path))).
Here is my Validator class:
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;
public class Validator {
Script script;
String interactiveCommands = {"read"};
public Validator(Script script) {
this.script = script;
}
public void validateInteractiveCommands() {
for (String string : interactiveCommands) {
streamService(string);
}
}
private void streamService(String string) {
try (Stream<String> stream = Files.lines(Paths.get(script.getPath()))) {
stream.filter(lines -> lines.startsWith(string))
.forEach(this::printFound);
} catch (IOException e) {
e.printStackTrace();
}
}
private void printFound(String string) {
System.out.println("Found an interactive command: " + string);
}
}
But in this case I only capture read when it is at the beggining of a line.
And in this case:
if true ; then
read a
fi
it fails to capture read because of 4 spaces.
Is there any simple way that I can handle it using stream or lambdas? Or should I switch to regexp?
java string bash lambda find
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
add a comment |
I want to write a java function, that will scan a bash file and find if there are any commands that require user input. I know that there is a command read, designed to capture user input and I think that it is the only one.
I wrote a Validator class that takes a script (simple class that just loads a content of a script to a String variable using Files.readAllBytes(Paths.get(path))).
Here is my Validator class:
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;
public class Validator {
Script script;
String interactiveCommands = {"read"};
public Validator(Script script) {
this.script = script;
}
public void validateInteractiveCommands() {
for (String string : interactiveCommands) {
streamService(string);
}
}
private void streamService(String string) {
try (Stream<String> stream = Files.lines(Paths.get(script.getPath()))) {
stream.filter(lines -> lines.startsWith(string))
.forEach(this::printFound);
} catch (IOException e) {
e.printStackTrace();
}
}
private void printFound(String string) {
System.out.println("Found an interactive command: " + string);
}
}
But in this case I only capture read when it is at the beggining of a line.
And in this case:
if true ; then
read a
fi
it fails to capture read because of 4 spaces.
Is there any simple way that I can handle it using stream or lambdas? Or should I switch to regexp?
java string bash lambda find
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
I want to write a java function, that will scan a bash file and find if there are any commands that require user input. I know that there is a command read, designed to capture user input and I think that it is the only one.
I wrote a Validator class that takes a script (simple class that just loads a content of a script to a String variable using Files.readAllBytes(Paths.get(path))).
Here is my Validator class:
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;
public class Validator {
Script script;
String interactiveCommands = {"read"};
public Validator(Script script) {
this.script = script;
}
public void validateInteractiveCommands() {
for (String string : interactiveCommands) {
streamService(string);
}
}
private void streamService(String string) {
try (Stream<String> stream = Files.lines(Paths.get(script.getPath()))) {
stream.filter(lines -> lines.startsWith(string))
.forEach(this::printFound);
} catch (IOException e) {
e.printStackTrace();
}
}
private void printFound(String string) {
System.out.println("Found an interactive command: " + string);
}
}
But in this case I only capture read when it is at the beggining of a line.
And in this case:
if true ; then
read a
fi
it fails to capture read because of 4 spaces.
Is there any simple way that I can handle it using stream or lambdas? Or should I switch to regexp?
java string bash lambda find
java string bash lambda find
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
asked Nov 22 '18 at 7:28
CrystalzordCrystalzord
559
559
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
"I know that there is a command read, designed to capture user input and I think that it is the only one."
In fact, it is impossible to tell if a command in a shell script is going to capture user input. Here are some examples:
rm -i *
cat > file
Indeed, it is (in general) impossible to tell which commands might be executed by a shell script. For example:
#!/bin/sh
echo running "$@"
"$@"
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
"I know that there is a command read, designed to capture user input and I think that it is the only one."
In fact, it is impossible to tell if a command in a shell script is going to capture user input. Here are some examples:
rm -i *
cat > file
Indeed, it is (in general) impossible to tell which commands might be executed by a shell script. For example:
#!/bin/sh
echo running "$@"
"$@"
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
add a comment |
"I know that there is a command read, designed to capture user input and I think that it is the only one."
In fact, it is impossible to tell if a command in a shell script is going to capture user input. Here are some examples:
rm -i *
cat > file
Indeed, it is (in general) impossible to tell which commands might be executed by a shell script. For example:
#!/bin/sh
echo running "$@"
"$@"
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
add a comment |
"I know that there is a command read, designed to capture user input and I think that it is the only one."
In fact, it is impossible to tell if a command in a shell script is going to capture user input. Here are some examples:
rm -i *
cat > file
Indeed, it is (in general) impossible to tell which commands might be executed by a shell script. For example:
#!/bin/sh
echo running "$@"
"$@"
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
"I know that there is a command read, designed to capture user input and I think that it is the only one."
In fact, it is impossible to tell if a command in a shell script is going to capture user input. Here are some examples:
rm -i *
cat > file
Indeed, it is (in general) impossible to tell which commands might be executed by a shell script. For example:
#!/bin/sh
echo running "$@"
"$@"
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
answered Nov 22 '18 at 7:45
Stephen CStephen C
515k69563920
515k69563920
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
add a comment |
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
Indeed You are right. I did not think about it earlier. So it seems that the only way to assume that the script will run in a non-interactive mode is closing the stdin right?
– Crystalzord
Nov 22 '18 at 8:09
1
1
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
Even that is not sufficient. A program can (attempt to) open "/dev/tty" and read from there.
– Stephen C
Nov 22 '18 at 9:07
add a comment |
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