SHA 256 Algorithm
$begingroup$
I'm really confused about the computation about SHA 256.
The $W_t$ variable: What's the value of $W_t$? How do I get that value?
I'm still confused because the explanation using english languange. I'm a beginner guys, any help from you will be a plus point for me about hashing.
hash sha-256
New contributor
$endgroup$
add a comment |
$begingroup$
I'm really confused about the computation about SHA 256.
The $W_t$ variable: What's the value of $W_t$? How do I get that value?
I'm still confused because the explanation using english languange. I'm a beginner guys, any help from you will be a plus point for me about hashing.
hash sha-256
New contributor
$endgroup$
add a comment |
$begingroup$
I'm really confused about the computation about SHA 256.
The $W_t$ variable: What's the value of $W_t$? How do I get that value?
I'm still confused because the explanation using english languange. I'm a beginner guys, any help from you will be a plus point for me about hashing.
hash sha-256
New contributor
$endgroup$
I'm really confused about the computation about SHA 256.
The $W_t$ variable: What's the value of $W_t$? How do I get that value?
I'm still confused because the explanation using english languange. I'm a beginner guys, any help from you will be a plus point for me about hashing.
hash sha-256
hash sha-256
New contributor
New contributor
edited 45 mins ago
AleksanderRas
2,6371834
2,6371834
New contributor
asked 54 mins ago
Onta SsOnta Ss
112
112
New contributor
New contributor
add a comment |
add a comment |
1 Answer
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$begingroup$
It is in SHA-256 message schedule (NIST-FIPS 180-4);
The message is first padded, then parsed into 512-bit as $M^{1},ldots,M^{N}$.
The $M_t^{(i)}$ is the $t$-th 32 bit in the $i$-th value there for $0 leq t leq 15$
The $W_t$ is defined as your equation.
$endgroup$
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
add a comment |
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1 Answer
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1 Answer
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active
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votes
$begingroup$
It is in SHA-256 message schedule (NIST-FIPS 180-4);
The message is first padded, then parsed into 512-bit as $M^{1},ldots,M^{N}$.
The $M_t^{(i)}$ is the $t$-th 32 bit in the $i$-th value there for $0 leq t leq 15$
The $W_t$ is defined as your equation.
$endgroup$
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
add a comment |
$begingroup$
It is in SHA-256 message schedule (NIST-FIPS 180-4);
The message is first padded, then parsed into 512-bit as $M^{1},ldots,M^{N}$.
The $M_t^{(i)}$ is the $t$-th 32 bit in the $i$-th value there for $0 leq t leq 15$
The $W_t$ is defined as your equation.
$endgroup$
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
add a comment |
$begingroup$
It is in SHA-256 message schedule (NIST-FIPS 180-4);
The message is first padded, then parsed into 512-bit as $M^{1},ldots,M^{N}$.
The $M_t^{(i)}$ is the $t$-th 32 bit in the $i$-th value there for $0 leq t leq 15$
The $W_t$ is defined as your equation.
$endgroup$
It is in SHA-256 message schedule (NIST-FIPS 180-4);
The message is first padded, then parsed into 512-bit as $M^{1},ldots,M^{N}$.
The $M_t^{(i)}$ is the $t$-th 32 bit in the $i$-th value there for $0 leq t leq 15$
The $W_t$ is defined as your equation.
edited 36 mins ago
answered 43 mins ago
kelalakakelalaka
8,24322351
8,24322351
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
add a comment |
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
$begingroup$
so you mean Wt = M16.....Mn ?
$endgroup$
– Onta Ss
10 mins ago
add a comment |
Onta Ss is a new contributor. Be nice, and check out our Code of Conduct.
Onta Ss is a new contributor. Be nice, and check out our Code of Conduct.
Onta Ss is a new contributor. Be nice, and check out our Code of Conduct.
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