passing Variable from PHP to Python












0















i have problem , i want to passing variable from php to python .
why if my word contains space , in python cannt receive this words .
Example Code :



<?php 
$variable = "Test Variable Contains Space";

echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py $variable ");

?>


in my python code :



import sys

variable = str(sys.argv[1])

print variable


the result i have from this code jut this words "Test" .










share|improve this question























  • escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

    – mario
    Nov 26 '18 at 2:51
















0















i have problem , i want to passing variable from php to python .
why if my word contains space , in python cannt receive this words .
Example Code :



<?php 
$variable = "Test Variable Contains Space";

echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py $variable ");

?>


in my python code :



import sys

variable = str(sys.argv[1])

print variable


the result i have from this code jut this words "Test" .










share|improve this question























  • escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

    – mario
    Nov 26 '18 at 2:51














0












0








0








i have problem , i want to passing variable from php to python .
why if my word contains space , in python cannt receive this words .
Example Code :



<?php 
$variable = "Test Variable Contains Space";

echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py $variable ");

?>


in my python code :



import sys

variable = str(sys.argv[1])

print variable


the result i have from this code jut this words "Test" .










share|improve this question














i have problem , i want to passing variable from php to python .
why if my word contains space , in python cannt receive this words .
Example Code :



<?php 
$variable = "Test Variable Contains Space";

echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py $variable ");

?>


in my python code :



import sys

variable = str(sys.argv[1])

print variable


the result i have from this code jut this words "Test" .







php python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 26 '18 at 2:39









ZaboyZaboy

63




63













  • escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

    – mario
    Nov 26 '18 at 2:51



















  • escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

    – mario
    Nov 26 '18 at 2:51

















escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

– mario
Nov 26 '18 at 2:51





escapeshellarg is usually the best option. Albeit cmd might mess with it, Python usually employs a standard shell argument tokenizer.

– mario
Nov 26 '18 at 2:51












2 Answers
2






active

oldest

votes


















1














Bash commands interpret arguments as separated by spaces, therefore, Test Variable Contains Space seems like 4 different arguments. To fix this, you need to surround it with double quotes:



... "$variable" ");


Full code:



<?php 
$variable = "Test Variable Contains Space";

echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py "$variable" ");

?>





share|improve this answer































    0














    Please add "." after url part is completed.



    echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py". $variable);





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Bash commands interpret arguments as separated by spaces, therefore, Test Variable Contains Space seems like 4 different arguments. To fix this, you need to surround it with double quotes:



      ... "$variable" ");


      Full code:



      <?php 
      $variable = "Test Variable Contains Space";

      echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py "$variable" ");

      ?>





      share|improve this answer




























        1














        Bash commands interpret arguments as separated by spaces, therefore, Test Variable Contains Space seems like 4 different arguments. To fix this, you need to surround it with double quotes:



        ... "$variable" ");


        Full code:



        <?php 
        $variable = "Test Variable Contains Space";

        echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py "$variable" ");

        ?>





        share|improve this answer


























          1












          1








          1







          Bash commands interpret arguments as separated by spaces, therefore, Test Variable Contains Space seems like 4 different arguments. To fix this, you need to surround it with double quotes:



          ... "$variable" ");


          Full code:



          <?php 
          $variable = "Test Variable Contains Space";

          echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py "$variable" ");

          ?>





          share|improve this answer













          Bash commands interpret arguments as separated by spaces, therefore, Test Variable Contains Space seems like 4 different arguments. To fix this, you need to surround it with double quotes:



          ... "$variable" ");


          Full code:



          <?php 
          $variable = "Test Variable Contains Space";

          echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py "$variable" ");

          ?>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 26 '18 at 2:44









          DavіdDavіd

          3,66841735




          3,66841735

























              0














              Please add "." after url part is completed.



              echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py". $variable);





              share|improve this answer




























                0














                Please add "." after url part is completed.



                echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py". $variable);





                share|improve this answer


























                  0












                  0








                  0







                  Please add "." after url part is completed.



                  echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py". $variable);





                  share|improve this answer













                  Please add "." after url part is completed.



                  echo shell_exec("C:UsersHPAppDataLocalProgramsPythonPython37-32python.exe C:UsersHPAppDataLocalProgramsPythonPython37-32hasil.py". $variable);






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 26 '18 at 4:25









                  Madhuri PatelMadhuri Patel

                  863521




                  863521






























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