Tukukkk

I am trying to extract only the number part including the thousands separator and the decimal value , but always getting the error input string not in correct format .

My input string will be in the following formats

USD1200 1,200.12 USD

I need the output as below respectively

1200 1,200.12

If I use the below the first occurrence of , is considered as delimiter

string prodValue = Regex.Match(prodAmount, @"d+").Value;

If I use this one , I am getting error

string prodValue = Regex.Match(prodAmount, @"^[0-9]+(,[0-9])+(.[0-9])?$").Value;

How can I can extract the output I needed?

For capturing multiple matches, you need Regex.Matches instead of Regex.Match . Also in your regex, you need to make comma group as zero or more occurence and dot group as optional as it may or may not exist in the number you intend to capture.

You can use this regex,

d+(?:,d+)*(?:.d+)?

Explanation:

• 
  d+ --> Matches one or more digits


• 
  (?:,d+)* --> Matches a comma followed by one or more digits zero or more times


• 
  (?:.d+)? --> Optionally matches a literal dot followed by one or more digits

Demo

Here is a sample C# code,

MatchCollection matches = Regex.Matches("USD1200 1,200.12 1,211,234,332.12 12,333 USD", @"d+(?:,d+)*(?:.d+)?");

for (int i = 0; i < matches.Count;i++) {

    Console.WriteLine("Match: " + matches[i]);

}

This gives following output like you expect,

Match: 1200

Match: 1,200.12

Match: 1,211,234,332.12

Match: 12,333

I think you places the second "+" wrong and missed a third one.

@"^[0-9]+,[0-9]+.[0-9]+?$")

You Regex match string is incorrect.

Try: ^[0-9]+((,[0-9]+)+)?(.[0-9]+)?$

See example here

In your regex you use anchors ^ to assert the start and the end $ of the string where USD is not taken into consideration and would not match. If you want mulitple matches, you should use Regex.Matches instead.

To match a number without a dot or a comma, the middle part should match 0+ times as the last part is already optional and the digits in the character class need an quantifier to match 1+ times like (,[0-9]+)*. Note that you don't have to escape the comma.

If the USD is part of the match, you could use an alternation to match either USD1200 or 1,200.12 USD instead of matching all the digits.

You could use named capturing group to reference the group by name.

bUSD(?<n1>d+)|(?<n2>d{1,3}(?:,d{3})*(?:.d+)?) USDb

That would match

• 
  bUSD Match word boundary and USD


• 
  (?<n1>d+) Named capturing group n1 which will match 1+ digits


• 
  | or


• 
  (?<n2> Start named capturing group n2
  
  
  
  
  • 
    d{1,3} Match 1-3 digits
  
  
  • 
    (?:,d{3})* Match a comma, 3 digits and repeat 0+ times
  
  
  • 
    (?:.d+)? Match a dot and 1+ digits and make that optional
  
  
  
  


• 
  ) Close namedd capturing group


• 
  USDb Match space, USD and a word boundary

Regex demo | C# demo