Symfony 4, provide simple example for a findby custom method in ManyToMany relation context
I have two simple entities A and B : (entity 'AB' automatically created by symfony 4)
With theses examples datas :
In entry, I have only the names of one entitie B (by example 'foo') and the name of one entity A ( by example 'A_b')
From a Repository class ( A repository class or B Repository class ? ), how can I get the entity B depending of only the strings 'foo' and 'A_b' entries ?
I must obtains in result the entity B with the id 1
I'm not a very strong doctrine DQL user.. And I'm looking for a proper way
symfony doctrine many-to-many symfony4
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
add a comment |
I have two simple entities A and B : (entity 'AB' automatically created by symfony 4)
With theses examples datas :
In entry, I have only the names of one entitie B (by example 'foo') and the name of one entity A ( by example 'A_b')
From a Repository class ( A repository class or B Repository class ? ), how can I get the entity B depending of only the strings 'foo' and 'A_b' entries ?
I must obtains in result the entity B with the id 1
I'm not a very strong doctrine DQL user.. And I'm looking for a proper way
symfony doctrine many-to-many symfony4
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
add a comment |
I have two simple entities A and B : (entity 'AB' automatically created by symfony 4)
With theses examples datas :
In entry, I have only the names of one entitie B (by example 'foo') and the name of one entity A ( by example 'A_b')
From a Repository class ( A repository class or B Repository class ? ), how can I get the entity B depending of only the strings 'foo' and 'A_b' entries ?
I must obtains in result the entity B with the id 1
I'm not a very strong doctrine DQL user.. And I'm looking for a proper way
symfony doctrine many-to-many symfony4
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
I have two simple entities A and B : (entity 'AB' automatically created by symfony 4)
With theses examples datas :
In entry, I have only the names of one entitie B (by example 'foo') and the name of one entity A ( by example 'A_b')
From a Repository class ( A repository class or B Repository class ? ), how can I get the entity B depending of only the strings 'foo' and 'A_b' entries ?
I must obtains in result the entity B with the id 1
I'm not a very strong doctrine DQL user.. And I'm looking for a proper way
symfony doctrine many-to-many symfony4
symfony doctrine many-to-many symfony4
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
asked Nov 22 '18 at 10:24
user2137454user2137454
184632
184632
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can try this code:
public function getBByName($name)
{
$qb = $this->createQueryBuilder('A');
$qb->leftJoin('A.b', 'B');
$qb->where('B.name= :name');
$qb->setParameter('name', $name);
$query = $qb->getQuery();
$result = $query->getResult();
return $result;
}
answered Nov 22 '18 at 10:46
ThemerThemer
31026
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428783%2fsymfony-4-provide-simple-example-for-a-findby-custom-method-in-manytomany-relat%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can try this code:
public function getBByName($name)
{
$qb = $this->createQueryBuilder('A');
$qb->leftJoin('A.b', 'B');
$qb->where('B.name= :name');
$qb->setParameter('name', $name);
$query = $qb->getQuery();
$result = $query->getResult();
return $result;
}
answered Nov 22 '18 at 10:46
ThemerThemer
31026
add a comment |
You can try this code:
public function getBByName($name)
{
$qb = $this->createQueryBuilder('A');
$qb->leftJoin('A.b', 'B');
$qb->where('B.name= :name');
$qb->setParameter('name', $name);
$query = $qb->getQuery();
$result = $query->getResult();
return $result;
}
answered Nov 22 '18 at 10:46
ThemerThemer
31026
add a comment |
You can try this code:
public function getBByName($name)
{
$qb = $this->createQueryBuilder('A');
$qb->leftJoin('A.b', 'B');
$qb->where('B.name= :name');
$qb->setParameter('name', $name);
$query = $qb->getQuery();
$result = $query->getResult();
return $result;
}
answered Nov 22 '18 at 10:46
ThemerThemer
31026
You can try this code:
public function getBByName($name)
{
$qb = $this->createQueryBuilder('A');
$qb->leftJoin('A.b', 'B');
$qb->where('B.name= :name');
$qb->setParameter('name', $name);
$query = $qb->getQuery();
$result = $query->getResult();
return $result;
}
answered Nov 22 '18 at 10:46
ThemerThemer
31026
answered Nov 22 '18 at 10:46
ThemerThemer
31026
answered Nov 22 '18 at 10:46
ThemerThemer
31026
answered Nov 22 '18 at 10:46
ThemerThemer
31026
31026
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53428783%2fsymfony-4-provide-simple-example-for-a-findby-custom-method-in-manytomany-relat%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
