change value by reference when using an extension method












0















I want to create an error message string. It should contain multiple hints to fix the errors.



First I created something like this



string errorMessage = string.Empty;

if (1 == 1)
errorMessage += "- hint 1n";

if (2 == 2)
errorMessage += "- hint 2n";

if (3 == 3)
errorMessage += "- hint 3";

// do something with errorMessage


And I thought about cleaning it up. I created an extension method



public static void AppendIf(this string s, bool condition, string txtToAppend)
{
if (condition)
s += txtToAppend;
}


And call it within my class



string errorMessage = string.Empty;

errorMessage.AppendIf(1 == 1, "- hint 1n");
errorMessage.AppendIf(2 == 2, "- hint 2n");
errorMessage.AppendIf(3 == 3, "- hint 3");

// do something with errorMessage


But errorMessage stays empty. I thought this acts like the ref keyword so what is wrong with my extension method?










share|improve this question




















  • 4





    Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

    – Jeroen Mostert
    Nov 22 '18 at 10:35






  • 1





    if (1 == 1)? What's the point?

    – SeM
    Nov 22 '18 at 10:35








  • 1





    you probably want to return a new string from your extension method

    – Rahul
    Nov 22 '18 at 10:36











  • @JeroenMostert thanks, I will have a look.

    – MHComputech
    Nov 22 '18 at 10:38











  • @SeM just an example

    – MHComputech
    Nov 22 '18 at 10:38
















0















I want to create an error message string. It should contain multiple hints to fix the errors.



First I created something like this



string errorMessage = string.Empty;

if (1 == 1)
errorMessage += "- hint 1n";

if (2 == 2)
errorMessage += "- hint 2n";

if (3 == 3)
errorMessage += "- hint 3";

// do something with errorMessage


And I thought about cleaning it up. I created an extension method



public static void AppendIf(this string s, bool condition, string txtToAppend)
{
if (condition)
s += txtToAppend;
}


And call it within my class



string errorMessage = string.Empty;

errorMessage.AppendIf(1 == 1, "- hint 1n");
errorMessage.AppendIf(2 == 2, "- hint 2n");
errorMessage.AppendIf(3 == 3, "- hint 3");

// do something with errorMessage


But errorMessage stays empty. I thought this acts like the ref keyword so what is wrong with my extension method?










share|improve this question




















  • 4





    Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

    – Jeroen Mostert
    Nov 22 '18 at 10:35






  • 1





    if (1 == 1)? What's the point?

    – SeM
    Nov 22 '18 at 10:35








  • 1





    you probably want to return a new string from your extension method

    – Rahul
    Nov 22 '18 at 10:36











  • @JeroenMostert thanks, I will have a look.

    – MHComputech
    Nov 22 '18 at 10:38











  • @SeM just an example

    – MHComputech
    Nov 22 '18 at 10:38














0












0








0








I want to create an error message string. It should contain multiple hints to fix the errors.



First I created something like this



string errorMessage = string.Empty;

if (1 == 1)
errorMessage += "- hint 1n";

if (2 == 2)
errorMessage += "- hint 2n";

if (3 == 3)
errorMessage += "- hint 3";

// do something with errorMessage


And I thought about cleaning it up. I created an extension method



public static void AppendIf(this string s, bool condition, string txtToAppend)
{
if (condition)
s += txtToAppend;
}


And call it within my class



string errorMessage = string.Empty;

errorMessage.AppendIf(1 == 1, "- hint 1n");
errorMessage.AppendIf(2 == 2, "- hint 2n");
errorMessage.AppendIf(3 == 3, "- hint 3");

// do something with errorMessage


But errorMessage stays empty. I thought this acts like the ref keyword so what is wrong with my extension method?










share|improve this question
















I want to create an error message string. It should contain multiple hints to fix the errors.



First I created something like this



string errorMessage = string.Empty;

if (1 == 1)
errorMessage += "- hint 1n";

if (2 == 2)
errorMessage += "- hint 2n";

if (3 == 3)
errorMessage += "- hint 3";

// do something with errorMessage


And I thought about cleaning it up. I created an extension method



public static void AppendIf(this string s, bool condition, string txtToAppend)
{
if (condition)
s += txtToAppend;
}


And call it within my class



string errorMessage = string.Empty;

errorMessage.AppendIf(1 == 1, "- hint 1n");
errorMessage.AppendIf(2 == 2, "- hint 2n");
errorMessage.AppendIf(3 == 3, "- hint 3");

// do something with errorMessage


But errorMessage stays empty. I thought this acts like the ref keyword so what is wrong with my extension method?







c#






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 10:39









S.Akbari

30.3k93673




30.3k93673










asked Nov 22 '18 at 10:32









MHComputechMHComputech

25913




25913








  • 4





    Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

    – Jeroen Mostert
    Nov 22 '18 at 10:35






  • 1





    if (1 == 1)? What's the point?

    – SeM
    Nov 22 '18 at 10:35








  • 1





    you probably want to return a new string from your extension method

    – Rahul
    Nov 22 '18 at 10:36











  • @JeroenMostert thanks, I will have a look.

    – MHComputech
    Nov 22 '18 at 10:38











  • @SeM just an example

    – MHComputech
    Nov 22 '18 at 10:38














  • 4





    Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

    – Jeroen Mostert
    Nov 22 '18 at 10:35






  • 1





    if (1 == 1)? What's the point?

    – SeM
    Nov 22 '18 at 10:35








  • 1





    you probably want to return a new string from your extension method

    – Rahul
    Nov 22 '18 at 10:36











  • @JeroenMostert thanks, I will have a look.

    – MHComputech
    Nov 22 '18 at 10:38











  • @SeM just an example

    – MHComputech
    Nov 22 '18 at 10:38








4




4





Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

– Jeroen Mostert
Nov 22 '18 at 10:35





Well, this does not act like the ref keyword... that's basically all there is to it. string is an immutable object; slapping on an extension method does not make it mutable. You want a StringBuilder.

– Jeroen Mostert
Nov 22 '18 at 10:35




1




1





if (1 == 1)? What's the point?

– SeM
Nov 22 '18 at 10:35







if (1 == 1)? What's the point?

– SeM
Nov 22 '18 at 10:35






1




1





you probably want to return a new string from your extension method

– Rahul
Nov 22 '18 at 10:36





you probably want to return a new string from your extension method

– Rahul
Nov 22 '18 at 10:36













@JeroenMostert thanks, I will have a look.

– MHComputech
Nov 22 '18 at 10:38





@JeroenMostert thanks, I will have a look.

– MHComputech
Nov 22 '18 at 10:38













@SeM just an example

– MHComputech
Nov 22 '18 at 10:38





@SeM just an example

– MHComputech
Nov 22 '18 at 10:38












2 Answers
2






active

oldest

votes


















2














You could not use this ref modifier, please check compiler feature request.



However you can get the same result by using the StringBuilder type:



public static void AppendIf(this StringBuilder s, bool condition, string txtToAppend)
{
if (condition)
s.Append(txtToAppend);
}


So, your code will be:



string errorMessage = new StringBuilder();

errorMessage.AppendIf(1 == 1, "- hint 1n");
errorMessage.AppendIf(2 == 2, "- hint 2n");
errorMessage.AppendIf(3 == 3, "- hint 3");


NB: please avoid executing code like str += anotherStr; inside the loop, because this method has O(N^2) complexity, where N is count of chars. Please check details in this question.






share|improve this answer































    4














    string is immutable, which means that it creates a new string every time you append to it, so it is impossible.



    However, you can use StringBuilder to achieve it:



    public static class StringBuilderExtensions
    {
    public static StringBuilder AppendLineIf(this StringBuilder builder, bool condition, string line)
    {
    // validate arguments
    if (condition)
    builder.AppendLine(line);
    return builder;
    }

    public static StringBuilder AppendIf(this StringBuilder builder, bool condition, string line)
    {
    // validate arguments
    if (condition)
    builder.Append(line);
    return builder;
    }
    }

    StringBuilder builder = new StringBuilder();
    builder.AppendLineIf(1 == 1, "- hint 1");
    builder.AppendLineIf(2 == 2, "- hint 2");
    builder.AppendLineIf(3 == 3, "- hint 3");

    string result = builder.ToString();
    // do something with result


    You can also chain these calls, if it looks better for you:



    string result = new StringBuilder()
    .AppendLineIf(1 == 1, "- hint 1")
    .AppendLineIf(2 == 2, "- hint 2")
    .AppendLineIf(3 == 3, "- hint 3")
    .ToString();





    share|improve this answer
























    • Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

      – Stefan Illner
      Nov 22 '18 at 11:05











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    You could not use this ref modifier, please check compiler feature request.



    However you can get the same result by using the StringBuilder type:



    public static void AppendIf(this StringBuilder s, bool condition, string txtToAppend)
    {
    if (condition)
    s.Append(txtToAppend);
    }


    So, your code will be:



    string errorMessage = new StringBuilder();

    errorMessage.AppendIf(1 == 1, "- hint 1n");
    errorMessage.AppendIf(2 == 2, "- hint 2n");
    errorMessage.AppendIf(3 == 3, "- hint 3");


    NB: please avoid executing code like str += anotherStr; inside the loop, because this method has O(N^2) complexity, where N is count of chars. Please check details in this question.






    share|improve this answer




























      2














      You could not use this ref modifier, please check compiler feature request.



      However you can get the same result by using the StringBuilder type:



      public static void AppendIf(this StringBuilder s, bool condition, string txtToAppend)
      {
      if (condition)
      s.Append(txtToAppend);
      }


      So, your code will be:



      string errorMessage = new StringBuilder();

      errorMessage.AppendIf(1 == 1, "- hint 1n");
      errorMessage.AppendIf(2 == 2, "- hint 2n");
      errorMessage.AppendIf(3 == 3, "- hint 3");


      NB: please avoid executing code like str += anotherStr; inside the loop, because this method has O(N^2) complexity, where N is count of chars. Please check details in this question.






      share|improve this answer


























        2












        2








        2







        You could not use this ref modifier, please check compiler feature request.



        However you can get the same result by using the StringBuilder type:



        public static void AppendIf(this StringBuilder s, bool condition, string txtToAppend)
        {
        if (condition)
        s.Append(txtToAppend);
        }


        So, your code will be:



        string errorMessage = new StringBuilder();

        errorMessage.AppendIf(1 == 1, "- hint 1n");
        errorMessage.AppendIf(2 == 2, "- hint 2n");
        errorMessage.AppendIf(3 == 3, "- hint 3");


        NB: please avoid executing code like str += anotherStr; inside the loop, because this method has O(N^2) complexity, where N is count of chars. Please check details in this question.






        share|improve this answer













        You could not use this ref modifier, please check compiler feature request.



        However you can get the same result by using the StringBuilder type:



        public static void AppendIf(this StringBuilder s, bool condition, string txtToAppend)
        {
        if (condition)
        s.Append(txtToAppend);
        }


        So, your code will be:



        string errorMessage = new StringBuilder();

        errorMessage.AppendIf(1 == 1, "- hint 1n");
        errorMessage.AppendIf(2 == 2, "- hint 2n");
        errorMessage.AppendIf(3 == 3, "- hint 3");


        NB: please avoid executing code like str += anotherStr; inside the loop, because this method has O(N^2) complexity, where N is count of chars. Please check details in this question.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 '18 at 10:47









        Manushin IgorManushin Igor

        1,060818




        1,060818

























            4














            string is immutable, which means that it creates a new string every time you append to it, so it is impossible.



            However, you can use StringBuilder to achieve it:



            public static class StringBuilderExtensions
            {
            public static StringBuilder AppendLineIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.AppendLine(line);
            return builder;
            }

            public static StringBuilder AppendIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.Append(line);
            return builder;
            }
            }

            StringBuilder builder = new StringBuilder();
            builder.AppendLineIf(1 == 1, "- hint 1");
            builder.AppendLineIf(2 == 2, "- hint 2");
            builder.AppendLineIf(3 == 3, "- hint 3");

            string result = builder.ToString();
            // do something with result


            You can also chain these calls, if it looks better for you:



            string result = new StringBuilder()
            .AppendLineIf(1 == 1, "- hint 1")
            .AppendLineIf(2 == 2, "- hint 2")
            .AppendLineIf(3 == 3, "- hint 3")
            .ToString();





            share|improve this answer
























            • Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

              – Stefan Illner
              Nov 22 '18 at 11:05
















            4














            string is immutable, which means that it creates a new string every time you append to it, so it is impossible.



            However, you can use StringBuilder to achieve it:



            public static class StringBuilderExtensions
            {
            public static StringBuilder AppendLineIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.AppendLine(line);
            return builder;
            }

            public static StringBuilder AppendIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.Append(line);
            return builder;
            }
            }

            StringBuilder builder = new StringBuilder();
            builder.AppendLineIf(1 == 1, "- hint 1");
            builder.AppendLineIf(2 == 2, "- hint 2");
            builder.AppendLineIf(3 == 3, "- hint 3");

            string result = builder.ToString();
            // do something with result


            You can also chain these calls, if it looks better for you:



            string result = new StringBuilder()
            .AppendLineIf(1 == 1, "- hint 1")
            .AppendLineIf(2 == 2, "- hint 2")
            .AppendLineIf(3 == 3, "- hint 3")
            .ToString();





            share|improve this answer
























            • Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

              – Stefan Illner
              Nov 22 '18 at 11:05














            4












            4








            4







            string is immutable, which means that it creates a new string every time you append to it, so it is impossible.



            However, you can use StringBuilder to achieve it:



            public static class StringBuilderExtensions
            {
            public static StringBuilder AppendLineIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.AppendLine(line);
            return builder;
            }

            public static StringBuilder AppendIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.Append(line);
            return builder;
            }
            }

            StringBuilder builder = new StringBuilder();
            builder.AppendLineIf(1 == 1, "- hint 1");
            builder.AppendLineIf(2 == 2, "- hint 2");
            builder.AppendLineIf(3 == 3, "- hint 3");

            string result = builder.ToString();
            // do something with result


            You can also chain these calls, if it looks better for you:



            string result = new StringBuilder()
            .AppendLineIf(1 == 1, "- hint 1")
            .AppendLineIf(2 == 2, "- hint 2")
            .AppendLineIf(3 == 3, "- hint 3")
            .ToString();





            share|improve this answer













            string is immutable, which means that it creates a new string every time you append to it, so it is impossible.



            However, you can use StringBuilder to achieve it:



            public static class StringBuilderExtensions
            {
            public static StringBuilder AppendLineIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.AppendLine(line);
            return builder;
            }

            public static StringBuilder AppendIf(this StringBuilder builder, bool condition, string line)
            {
            // validate arguments
            if (condition)
            builder.Append(line);
            return builder;
            }
            }

            StringBuilder builder = new StringBuilder();
            builder.AppendLineIf(1 == 1, "- hint 1");
            builder.AppendLineIf(2 == 2, "- hint 2");
            builder.AppendLineIf(3 == 3, "- hint 3");

            string result = builder.ToString();
            // do something with result


            You can also chain these calls, if it looks better for you:



            string result = new StringBuilder()
            .AppendLineIf(1 == 1, "- hint 1")
            .AppendLineIf(2 == 2, "- hint 2")
            .AppendLineIf(3 == 3, "- hint 3")
            .ToString();






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 22 '18 at 10:46









            Yeldar KurmangaliyevYeldar Kurmangaliyev

            24.5k93666




            24.5k93666













            • Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

              – Stefan Illner
              Nov 22 '18 at 11:05



















            • Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

              – Stefan Illner
              Nov 22 '18 at 11:05

















            Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

            – Stefan Illner
            Nov 22 '18 at 11:05





            Like this solution more than the other one because of returning StringBuilder instead of void from your extension methods.

            – Stefan Illner
            Nov 22 '18 at 11:05


















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