Overloading functions like Mean for distributions
I'd like to understand how functions like Mean are overloaded to provide the right behavior for the distributions in Mathematica (like NormalDistribution or PoissonDistribution).
I originally assumed it was through the use of UpValues, but now I'm not so sure...
So, if I wanted to implement a function or distribution and define a behavior for it when another function like Mean is applied to it, how would I go about it? I know it's not the following:
f[x_]:=2+x
f /: Mean[f[x_]] := 3 x
Desired behavior:
f[3]
Mean[f[3]]
(*
==> 5
==> 9
*)
upvalues
asked 5 hours ago
tgray
30527
add a comment |
I'd like to understand how functions like Mean are overloaded to provide the right behavior for the distributions in Mathematica (like NormalDistribution or PoissonDistribution).
I originally assumed it was through the use of UpValues, but now I'm not so sure...
So, if I wanted to implement a function or distribution and define a behavior for it when another function like Mean is applied to it, how would I go about it? I know it's not the following:
f[x_]:=2+x
f /: Mean[f[x_]] := 3 x
Desired behavior:
f[3]
Mean[f[3]]
(*
==> 5
==> 9
*)
upvalues
asked 5 hours ago
tgray
30527
add a comment |
I'd like to understand how functions like Mean are overloaded to provide the right behavior for the distributions in Mathematica (like NormalDistribution or PoissonDistribution).
I originally assumed it was through the use of UpValues, but now I'm not so sure...
So, if I wanted to implement a function or distribution and define a behavior for it when another function like Mean is applied to it, how would I go about it? I know it's not the following:
f[x_]:=2+x
f /: Mean[f[x_]] := 3 x
Desired behavior:
f[3]
Mean[f[3]]
(*
==> 5
==> 9
*)
upvalues
asked 5 hours ago
tgray
30527
I'd like to understand how functions like Mean are overloaded to provide the right behavior for the distributions in Mathematica (like NormalDistribution or PoissonDistribution).
I originally assumed it was through the use of UpValues, but now I'm not so sure...
So, if I wanted to implement a function or distribution and define a behavior for it when another function like Mean is applied to it, how would I go about it? I know it's not the following:
f[x_]:=2+x
f /: Mean[f[x_]] := 3 x
Desired behavior:
f[3]
Mean[f[3]]
(*
==> 5
==> 9
*)
upvalues
upvalues
asked 5 hours ago
tgray
30527
asked 5 hours ago
tgray
30527
asked 5 hours ago
tgray
30527
asked 5 hours ago
tgray
30527
asked 5 hours ago
tgray
30527
30527
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
This works:
Unprotect[Mean];
SetAttributes[Mean, HoldFirst];
Protect[Mean];
f[x_] := 2 + x
f /: Mean[f[x_]] := 3 x
Since using Unprotect is not reccomended here's another way.
mean[x_] := Mean[x]
SetAttributes[mean, HoldFirst]
f[x_] := 2 + x
f /: mean[f[x_]] := 3 x
answered 2 hours ago
Andrew
1,7161014
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This works:
Unprotect[Mean];
SetAttributes[Mean, HoldFirst];
Protect[Mean];
f[x_] := 2 + x
f /: Mean[f[x_]] := 3 x
Since using Unprotect is not reccomended here's another way.
mean[x_] := Mean[x]
SetAttributes[mean, HoldFirst]
f[x_] := 2 + x
f /: mean[f[x_]] := 3 x
answered 2 hours ago
Andrew
1,7161014
add a comment |
This works:
Unprotect[Mean];
SetAttributes[Mean, HoldFirst];
Protect[Mean];
f[x_] := 2 + x
f /: Mean[f[x_]] := 3 x
Since using Unprotect is not reccomended here's another way.
mean[x_] := Mean[x]
SetAttributes[mean, HoldFirst]
f[x_] := 2 + x
f /: mean[f[x_]] := 3 x
answered 2 hours ago
Andrew
1,7161014
add a comment |
This works:
Unprotect[Mean];
SetAttributes[Mean, HoldFirst];
Protect[Mean];
f[x_] := 2 + x
f /: Mean[f[x_]] := 3 x
Since using Unprotect is not reccomended here's another way.
mean[x_] := Mean[x]
SetAttributes[mean, HoldFirst]
f[x_] := 2 + x
f /: mean[f[x_]] := 3 x
answered 2 hours ago
Andrew
1,7161014
This works:
Unprotect[Mean];
SetAttributes[Mean, HoldFirst];
Protect[Mean];
f[x_] := 2 + x
f /: Mean[f[x_]] := 3 x
Since using Unprotect is not reccomended here's another way.
mean[x_] := Mean[x]
SetAttributes[mean, HoldFirst]
f[x_] := 2 + x
f /: mean[f[x_]] := 3 x
answered 2 hours ago
Andrew
1,7161014
answered 2 hours ago
Andrew
1,7161014
answered 2 hours ago
Andrew
1,7161014
answered 2 hours ago
Andrew
1,7161014
1,7161014
add a comment |
add a comment |
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