Filled up $_FILES doesn't return file extension












2















I wrote this short script to upload multiple files, based on an old topic from Stackoverflow : How do you loop through $_FILES array?
(I didn't reply into it as it's 7 years old... Let me know if I did wrong)



if(!empty($_FILES)) {
$i = 0;
foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule).'-' . time() . $i . '.'.strtolower(substr(strrchr($tmpName, '.'),1));
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}
}
echo $gallery;


So basically, I'm sending multiple files in $_FILES['images'] and I create unique names before upload (using time() + $i). I never get the file extension as $_FILES['images']['name'] seems to be empty. It's not though as Var_dump returns a complete array with everything I need :



array(1) {
["images"]=> array(5) {
["name"]=> array(5) {
[0]=> string(13) "my-file-1.jpg"
[1]=> string(13) "my-file-2.jpg"
[2]=> string(13) "my-file-3.jpg"
[3]=> string(13) "my-file-4.jpg"
[4]=> string(13) "my-file-5.jpg"
}
["type"]=> array(5) {
[0]=> string(10) "image/jpeg"
[1]=> string(10) "image/jpeg"
[2]=> string(10) "image/jpeg"
[3]=> string(10) "image/jpeg"
[4]=> string(10) "image/jpeg"
}
["tmp_name"]=> array(5) {
[0]=> string(14) "/tmp/php1Nrgb4"
[1]=> string(14) "/tmp/phpnIJHZa"
[2]=> string(14) "/tmp/phpcAEf1c"
[3]=> string(14) "/tmp/phpbHgrVj"
[4]=> string(14) "/tmp/phpGu0FIp"
}
["error"]=> array(5) {
[0]=> int(0)
[1]=> int(0)
[2]=> int(0)
[3]=> int(0)
[4]=> int(0)
}
["size"]=> array(5) {
[0]=> int(262684)
[1]=> int(15644)
[2]=> int(32638)
[3]=> int(11897)
[4]=> int(103303)
}
}
}


I'd also need ['type'] to test the files but same thing : I Can't get to return the array's content.



Do you see something wrong in this script ?










share|improve this question

























  • "$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

    – Phil
    Nov 22 '18 at 0:12











  • That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

    – Greg
    Nov 22 '18 at 0:18
















2















I wrote this short script to upload multiple files, based on an old topic from Stackoverflow : How do you loop through $_FILES array?
(I didn't reply into it as it's 7 years old... Let me know if I did wrong)



if(!empty($_FILES)) {
$i = 0;
foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule).'-' . time() . $i . '.'.strtolower(substr(strrchr($tmpName, '.'),1));
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}
}
echo $gallery;


So basically, I'm sending multiple files in $_FILES['images'] and I create unique names before upload (using time() + $i). I never get the file extension as $_FILES['images']['name'] seems to be empty. It's not though as Var_dump returns a complete array with everything I need :



array(1) {
["images"]=> array(5) {
["name"]=> array(5) {
[0]=> string(13) "my-file-1.jpg"
[1]=> string(13) "my-file-2.jpg"
[2]=> string(13) "my-file-3.jpg"
[3]=> string(13) "my-file-4.jpg"
[4]=> string(13) "my-file-5.jpg"
}
["type"]=> array(5) {
[0]=> string(10) "image/jpeg"
[1]=> string(10) "image/jpeg"
[2]=> string(10) "image/jpeg"
[3]=> string(10) "image/jpeg"
[4]=> string(10) "image/jpeg"
}
["tmp_name"]=> array(5) {
[0]=> string(14) "/tmp/php1Nrgb4"
[1]=> string(14) "/tmp/phpnIJHZa"
[2]=> string(14) "/tmp/phpcAEf1c"
[3]=> string(14) "/tmp/phpbHgrVj"
[4]=> string(14) "/tmp/phpGu0FIp"
}
["error"]=> array(5) {
[0]=> int(0)
[1]=> int(0)
[2]=> int(0)
[3]=> int(0)
[4]=> int(0)
}
["size"]=> array(5) {
[0]=> int(262684)
[1]=> int(15644)
[2]=> int(32638)
[3]=> int(11897)
[4]=> int(103303)
}
}
}


I'd also need ['type'] to test the files but same thing : I Can't get to return the array's content.



Do you see something wrong in this script ?










share|improve this question

























  • "$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

    – Phil
    Nov 22 '18 at 0:12











  • That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

    – Greg
    Nov 22 '18 at 0:18














2












2








2








I wrote this short script to upload multiple files, based on an old topic from Stackoverflow : How do you loop through $_FILES array?
(I didn't reply into it as it's 7 years old... Let me know if I did wrong)



if(!empty($_FILES)) {
$i = 0;
foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule).'-' . time() . $i . '.'.strtolower(substr(strrchr($tmpName, '.'),1));
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}
}
echo $gallery;


So basically, I'm sending multiple files in $_FILES['images'] and I create unique names before upload (using time() + $i). I never get the file extension as $_FILES['images']['name'] seems to be empty. It's not though as Var_dump returns a complete array with everything I need :



array(1) {
["images"]=> array(5) {
["name"]=> array(5) {
[0]=> string(13) "my-file-1.jpg"
[1]=> string(13) "my-file-2.jpg"
[2]=> string(13) "my-file-3.jpg"
[3]=> string(13) "my-file-4.jpg"
[4]=> string(13) "my-file-5.jpg"
}
["type"]=> array(5) {
[0]=> string(10) "image/jpeg"
[1]=> string(10) "image/jpeg"
[2]=> string(10) "image/jpeg"
[3]=> string(10) "image/jpeg"
[4]=> string(10) "image/jpeg"
}
["tmp_name"]=> array(5) {
[0]=> string(14) "/tmp/php1Nrgb4"
[1]=> string(14) "/tmp/phpnIJHZa"
[2]=> string(14) "/tmp/phpcAEf1c"
[3]=> string(14) "/tmp/phpbHgrVj"
[4]=> string(14) "/tmp/phpGu0FIp"
}
["error"]=> array(5) {
[0]=> int(0)
[1]=> int(0)
[2]=> int(0)
[3]=> int(0)
[4]=> int(0)
}
["size"]=> array(5) {
[0]=> int(262684)
[1]=> int(15644)
[2]=> int(32638)
[3]=> int(11897)
[4]=> int(103303)
}
}
}


I'd also need ['type'] to test the files but same thing : I Can't get to return the array's content.



Do you see something wrong in this script ?










share|improve this question
















I wrote this short script to upload multiple files, based on an old topic from Stackoverflow : How do you loop through $_FILES array?
(I didn't reply into it as it's 7 years old... Let me know if I did wrong)



if(!empty($_FILES)) {
$i = 0;
foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule).'-' . time() . $i . '.'.strtolower(substr(strrchr($tmpName, '.'),1));
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}
}
echo $gallery;


So basically, I'm sending multiple files in $_FILES['images'] and I create unique names before upload (using time() + $i). I never get the file extension as $_FILES['images']['name'] seems to be empty. It's not though as Var_dump returns a complete array with everything I need :



array(1) {
["images"]=> array(5) {
["name"]=> array(5) {
[0]=> string(13) "my-file-1.jpg"
[1]=> string(13) "my-file-2.jpg"
[2]=> string(13) "my-file-3.jpg"
[3]=> string(13) "my-file-4.jpg"
[4]=> string(13) "my-file-5.jpg"
}
["type"]=> array(5) {
[0]=> string(10) "image/jpeg"
[1]=> string(10) "image/jpeg"
[2]=> string(10) "image/jpeg"
[3]=> string(10) "image/jpeg"
[4]=> string(10) "image/jpeg"
}
["tmp_name"]=> array(5) {
[0]=> string(14) "/tmp/php1Nrgb4"
[1]=> string(14) "/tmp/phpnIJHZa"
[2]=> string(14) "/tmp/phpcAEf1c"
[3]=> string(14) "/tmp/phpbHgrVj"
[4]=> string(14) "/tmp/phpGu0FIp"
}
["error"]=> array(5) {
[0]=> int(0)
[1]=> int(0)
[2]=> int(0)
[3]=> int(0)
[4]=> int(0)
}
["size"]=> array(5) {
[0]=> int(262684)
[1]=> int(15644)
[2]=> int(32638)
[3]=> int(11897)
[4]=> int(103303)
}
}
}


I'd also need ['type'] to test the files but same thing : I Can't get to return the array's content.



Do you see something wrong in this script ?







php arrays file loops






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 0:15









Phil

96.2k11136157




96.2k11136157










asked Nov 22 '18 at 0:00









GregGreg

217




217













  • "$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

    – Phil
    Nov 22 '18 at 0:12











  • That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

    – Greg
    Nov 22 '18 at 0:18



















  • "$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

    – Phil
    Nov 22 '18 at 0:12











  • That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

    – Greg
    Nov 22 '18 at 0:18

















"$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

– Phil
Nov 22 '18 at 0:12





"$_FILES['images']['name'] seems to be empty." 👈 it's pretty clear from your var_dump() that it is far from empty

– Phil
Nov 22 '18 at 0:12













That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

– Greg
Nov 22 '18 at 0:18





That's why I'm asking for help. I tried a Foreach on $_FILES['images']['name'] instead of 'tmp_name' and nothing appear.

– Greg
Nov 22 '18 at 0:18












1 Answer
1






active

oldest

votes


















3














$_FILES['images']['tmp_name'] does not contain an extension, that is the temp file PHP made of the uploaded file.



If you want the filename with extension of the file that was uploaded from the users PC, you need to look in $_FILES['images']['name']



So



foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. strtolower(substr(strrchr($_FILES['images']['name'][$index], '.'),1));
// changed here -----------------------------^^^^^^^^^^^^^^^^
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}


Also you can simplify that bunch of functions that get the extension to



        $img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. pathinfo($_FILES['images']['name'][$index], PATHINFO_EXTENSION);

$gallery = $gallery . '|' . $img_url;





share|improve this answer


























  • Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

    – Greg
    Nov 22 '18 at 0:22











  • Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

    – RiggsFolly
    Nov 22 '18 at 0:23











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














$_FILES['images']['tmp_name'] does not contain an extension, that is the temp file PHP made of the uploaded file.



If you want the filename with extension of the file that was uploaded from the users PC, you need to look in $_FILES['images']['name']



So



foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. strtolower(substr(strrchr($_FILES['images']['name'][$index], '.'),1));
// changed here -----------------------------^^^^^^^^^^^^^^^^
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}


Also you can simplify that bunch of functions that get the extension to



        $img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. pathinfo($_FILES['images']['name'][$index], PATHINFO_EXTENSION);

$gallery = $gallery . '|' . $img_url;





share|improve this answer


























  • Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

    – Greg
    Nov 22 '18 at 0:22











  • Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

    – RiggsFolly
    Nov 22 '18 at 0:23
















3














$_FILES['images']['tmp_name'] does not contain an extension, that is the temp file PHP made of the uploaded file.



If you want the filename with extension of the file that was uploaded from the users PC, you need to look in $_FILES['images']['name']



So



foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. strtolower(substr(strrchr($_FILES['images']['name'][$index], '.'),1));
// changed here -----------------------------^^^^^^^^^^^^^^^^
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}


Also you can simplify that bunch of functions that get the extension to



        $img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. pathinfo($_FILES['images']['name'][$index], PATHINFO_EXTENSION);

$gallery = $gallery . '|' . $img_url;





share|improve this answer


























  • Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

    – Greg
    Nov 22 '18 at 0:22











  • Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

    – RiggsFolly
    Nov 22 '18 at 0:23














3












3








3







$_FILES['images']['tmp_name'] does not contain an extension, that is the temp file PHP made of the uploaded file.



If you want the filename with extension of the file that was uploaded from the users PC, you need to look in $_FILES['images']['name']



So



foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. strtolower(substr(strrchr($_FILES['images']['name'][$index], '.'),1));
// changed here -----------------------------^^^^^^^^^^^^^^^^
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}


Also you can simplify that bunch of functions that get the extension to



        $img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. pathinfo($_FILES['images']['name'][$index], PATHINFO_EXTENSION);

$gallery = $gallery . '|' . $img_url;





share|improve this answer















$_FILES['images']['tmp_name'] does not contain an extension, that is the temp file PHP made of the uploaded file.



If you want the filename with extension of the file that was uploaded from the users PC, you need to look in $_FILES['images']['name']



So



foreach($_FILES['images']['tmp_name'] as $index => $tmpName) {
if(!empty($tmpName) && is_uploaded_file($tmpName)) {
$img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. strtolower(substr(strrchr($_FILES['images']['name'][$index], '.'),1));
// changed here -----------------------------^^^^^^^^^^^^^^^^
$gallery = $gallery . '|' . $img_url;
move_uploaded_file( $tmpName, $dir_upload . '/' . $img_url);
}
$i++;
}


Also you can simplify that bunch of functions that get the extension to



        $img_url = url_rewrite($intitule)
.'-'
. time()
. $i
. '.'
. pathinfo($_FILES['images']['name'][$index], PATHINFO_EXTENSION);

$gallery = $gallery . '|' . $img_url;






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 '18 at 0:19

























answered Nov 22 '18 at 0:11









RiggsFollyRiggsFolly

70.1k1864109




70.1k1864109













  • Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

    – Greg
    Nov 22 '18 at 0:22











  • Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

    – RiggsFolly
    Nov 22 '18 at 0:23



















  • Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

    – Greg
    Nov 22 '18 at 0:22











  • Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

    – RiggsFolly
    Nov 22 '18 at 0:23

















Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

– Greg
Nov 22 '18 at 0:22





Thanks you @RiggsFolly, it's working that way. i guess I forgot the [$index]. But why can't I use foreach($_FILES['images']['name'] as $index => $tmpName) instead ? (I'm keeping your suggestion, but I'm being curious about it)

– Greg
Nov 22 '18 at 0:22













Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

– RiggsFolly
Nov 22 '18 at 0:23





Because you need that, to be the location and name of the TMP file so that move_upload_file() will move the tmp file.

– RiggsFolly
Nov 22 '18 at 0:23


















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