Data frames as the third dimension in a 3D matrix in R
0
How can I create a 3D array with multiple data frames (or, I can convert them to arrays if that makes more sense) as the third dimension? So, I have multiple data frames that have rows and columns (are 2D), and I want them in one 3D array. The columns are the same across all data frames, but the number of rows is variable.
a <- c(1, 2)
b <- c(2, 1)
df <- data.frame(a, b)
c <- c(3, 4)
d <- c(4, 3)
df2 <- data.frame(c, d)
I need df and df2 to be the third dimension in an array
r
asked Nov 22 '18 at 0:15
LisaLisa
3741218
|
show 7 more comments
0
How can I create a 3D array with multiple data frames (or, I can convert them to arrays if that makes more sense) as the third dimension? So, I have multiple data frames that have rows and columns (are 2D), and I want them in one 3D array. The columns are the same across all data frames, but the number of rows is variable.
a <- c(1, 2)
b <- c(2, 1)
df <- data.frame(a, b)
c <- c(3, 4)
d <- c(4, 3)
df2 <- data.frame(c, d)
I need df and df2 to be the third dimension in an array
r
asked Nov 22 '18 at 0:15
LisaLisa
3741218
1
Do you just mean alist?list(df1, df2, df3)? If so, that was the exact output I suggested in my answer to your previous question.
– thelatemail
Nov 22 '18 at 0:34
1
Something like this - stackoverflow.com/a/36440267/496803 - in particularsimplify2array(list(x1, x2, x3))wherex1/2/3are matrices all of the same size.
– thelatemail
Nov 22 '18 at 0:53
1
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
1
As per the previous answer at the linked question -simplify2array(lapply(list(df,df2),as.matrix))works.
– thelatemail
Nov 22 '18 at 1:04
1
Using exactly what you have above in the question and your code to create and subsettest, I get1- the first column of the first row in the first strata. Maybe try with a fresh R session.
– thelatemail
Nov 22 '18 at 1:10
|
show 7 more comments
0
0
0
How can I create a 3D array with multiple data frames (or, I can convert them to arrays if that makes more sense) as the third dimension? So, I have multiple data frames that have rows and columns (are 2D), and I want them in one 3D array. The columns are the same across all data frames, but the number of rows is variable.
a <- c(1, 2)
b <- c(2, 1)
df <- data.frame(a, b)
c <- c(3, 4)
d <- c(4, 3)
df2 <- data.frame(c, d)
I need df and df2 to be the third dimension in an array
r
asked Nov 22 '18 at 0:15
LisaLisa
3741218
How can I create a 3D array with multiple data frames (or, I can convert them to arrays if that makes more sense) as the third dimension? So, I have multiple data frames that have rows and columns (are 2D), and I want them in one 3D array. The columns are the same across all data frames, but the number of rows is variable.
a <- c(1, 2)
b <- c(2, 1)
df <- data.frame(a, b)
c <- c(3, 4)
d <- c(4, 3)
df2 <- data.frame(c, d)
I need df and df2 to be the third dimension in an array
r
r
asked Nov 22 '18 at 0:15
LisaLisa
3741218
asked Nov 22 '18 at 0:15
LisaLisa
3741218
edited Nov 22 '18 at 0:57
Lisa
asked Nov 22 '18 at 0:15
LisaLisa
3741218
asked Nov 22 '18 at 0:15
LisaLisa
3741218
asked Nov 22 '18 at 0:15
LisaLisa
3741218
3741218
1
Do you just mean alist?list(df1, df2, df3)? If so, that was the exact output I suggested in my answer to your previous question.
– thelatemail
Nov 22 '18 at 0:34
1
Something like this - stackoverflow.com/a/36440267/496803 - in particularsimplify2array(list(x1, x2, x3))wherex1/2/3are matrices all of the same size.
– thelatemail
Nov 22 '18 at 0:53
1
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
1
As per the previous answer at the linked question -simplify2array(lapply(list(df,df2),as.matrix))works.
– thelatemail
Nov 22 '18 at 1:04
1
Using exactly what you have above in the question and your code to create and subsettest, I get1- the first column of the first row in the first strata. Maybe try with a fresh R session.
– thelatemail
Nov 22 '18 at 1:10
|
show 7 more comments
1
Do you just mean alist?list(df1, df2, df3)? If so, that was the exact output I suggested in my answer to your previous question.
– thelatemail
Nov 22 '18 at 0:34
1
Something like this - stackoverflow.com/a/36440267/496803 - in particularsimplify2array(list(x1, x2, x3))wherex1/2/3are matrices all of the same size.
– thelatemail
Nov 22 '18 at 0:53
1
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
1
As per the previous answer at the linked question -simplify2array(lapply(list(df,df2),as.matrix))works.
– thelatemail
Nov 22 '18 at 1:04
1
Using exactly what you have above in the question and your code to create and subsettest, I get1- the first column of the first row in the first strata. Maybe try with a fresh R session.
– thelatemail
Nov 22 '18 at 1:10
1
1
Do you just mean a
list? list(df1, df2, df3) ? If so, that was the exact output I suggested in my answer to your previous question.– thelatemail
Nov 22 '18 at 0:34
Do you just mean a
list? list(df1, df2, df3) ? If so, that was the exact output I suggested in my answer to your previous question.– thelatemail
Nov 22 '18 at 0:34
1
1
Something like this - stackoverflow.com/a/36440267/496803 - in particular
simplify2array(list(x1, x2, x3)) where x1/2/3 are matrices all of the same size.– thelatemail
Nov 22 '18 at 0:53
Something like this - stackoverflow.com/a/36440267/496803 - in particular
simplify2array(list(x1, x2, x3)) where x1/2/3 are matrices all of the same size.– thelatemail
Nov 22 '18 at 0:53
1
1
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
1
1
As per the previous answer at the linked question -
simplify2array(lapply(list(df,df2),as.matrix)) works.– thelatemail
Nov 22 '18 at 1:04
As per the previous answer at the linked question -
simplify2array(lapply(list(df,df2),as.matrix)) works.– thelatemail
Nov 22 '18 at 1:04
1
1
Using exactly what you have above in the question and your code to create and subset
test, I get 1 - the first column of the first row in the first strata. Maybe try with a fresh R session.– thelatemail
Nov 22 '18 at 1:10
Using exactly what you have above in the question and your code to create and subset
test, I get 1 - the first column of the first row in the first strata. Maybe try with a fresh R session.– thelatemail
Nov 22 '18 at 1:10
|
show 7 more comments
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1
Do you just mean a
list?list(df1, df2, df3)? If so, that was the exact output I suggested in my answer to your previous question.– thelatemail
Nov 22 '18 at 0:34
1
Something like this - stackoverflow.com/a/36440267/496803 - in particular
simplify2array(list(x1, x2, x3))wherex1/2/3are matrices all of the same size.– thelatemail
Nov 22 '18 at 0:53
1
stackoverflow.com/questions/4310727/…
– Chris
Nov 22 '18 at 0:56
1
As per the previous answer at the linked question -
simplify2array(lapply(list(df,df2),as.matrix))works.– thelatemail
Nov 22 '18 at 1:04
1
Using exactly what you have above in the question and your code to create and subset
test, I get1- the first column of the first row in the first strata. Maybe try with a fresh R session.– thelatemail
Nov 22 '18 at 1:10