Tukukkk

I am beginner in C++ (Data-structures and algorithms) and I need some help to write a better computation function in my int computemodes method. Is there way to write a better function that sorts the item count pair list in descending order by count. For example the item count pair list becomes,
{2,3},{4,3},{5,2}, {3,2}, {1,2}. Thanks for the help.

Right now it display as: 16 10 11 10 15 15 10 14 16 14 14 13 15 14 13 11 10 11 11 11 14 14 15 10 .

here is my code

    /*

the mode of a set of things is that thing that appears the greater number of times in the set

a set may have several modes

*/

int computemodes(int source, int size, int modes, int& msize)





{

    /*

    1. fill the modes array with zeroes

    */

    fill(modes, size, 0);



        /*

    2. store the number of times each source element appears in the modes array.

    if an element appears more than once in the source array then its counts appears

    more than once the modes array.

    source and modes form a parallel array structure

     */

    for(int i = 0; i < size; i++)

        modes[i] = count(source, size, source[i]);







     /*

    3. calculate the largest number in the modes array. this number is the number of

    times the mode or modes appears in the source array

    */

    int modevalue = findLargest(modes, size);



    /* 

    4. assign -1 to the mode array elements that are less than the mode value

    now only mode values in the modes array are not equal to -1.

    the corresponding elements in the source array are the modes.

    */

    for(int i = 0; i < size; i++)

        if(modes[i] != modevalue) modes[i] = -1;











    /*

    5. we use the modes array to identify the source elements that are modes:

    any element in the modes array that is not -1 corresponds to a mode in the

    source array. if the mode is 1 then every source element is a mode

    and no element in the modes array is -1; if the mode is greater than 1 then

    a. many modes array entries are -1

    b. the number of times a mode appears in the source equals its corresponding modes value

    c. the number of modes array entries that are not -1 are the number of times the modes

       appear in the source array



    the following nested for loop transforms the modes array into an array in which

    the first appearance of a mode in the source corresponds to a modes array entry 

    that is not -1 and subsequent appearances of this mode in the source correspond to

    modes array entries that are -1.

    */

    for(int i = 0; i < size; i++)

        if(modes[i] != -1)  //first appearance of the mode in the source

            for(int j = i + 1; j < size; j++)

                if(source[i] == source[j]) modes[j] = -1;

                        //subsequent appearances

    /*

    at this point the usage of the modes array changes. 

    heretofore, an entry that is not -1 in the modes array is the number of times

    a mode appears in the source array. now an entry in the modes array is a mode.

    the loop adds modes from the source array to the modes array. 

    msize serves 2 purposes:

    a. it is number of modes copied so far.

    b. it is the next free modes array position.

     */

    msize = 0;

    for (int i = 0; i < size; i++)

        if (modes[i] != -1) //first occurrence of a mode in the source

        {

            modes[msize] = source[i];

            msize++;

        }

    return modevalue;

}