cs50 vigenere - loops incorrectly
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Apologies if the answer to this is incredibly simple. I just can't work it out.
I've been working on the CS50 Vigenere problem and I think I'm almost there. However the program loops in a way that I don't expect and I'm not sure why. Once it has printed the first ciphered character of the plaintext, it loops back to move to the next character in the key but misses out the part where it needs to move to the next character of the plain text. At least I think that is what is happening.
Here is my code. Any help would be greatly appreciated.
#include <cs50.h>
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, string argv )
{
int a;
int ciphertext;
int k;
string plain;
int cipher;
// check user has input a valid number of arguments
if (argc < 2 || argc > 2)
{
printf("please input a valid number of argumentsn");
return 1;
}
// check user has input a valid key and prompt for plaintext
char * key = argv [1];
for (a = 0; a < strlen(key); a++)
if (!isalpha(key[a]))
{
printf("Please input a valid key. Key must be alphabetical");
return 1;
}
{
if (a == strlen(key))
{
plain = get_string("Plaintext: ");
}
{
printf("ciphertext: ");
}
}
//read plaintext and keep track
{
for (int i = 0, n = strlen(plain); i < n; i++)
{
//read key and keep track
if (isalpha(plain[i]))
{
for (int j = 0, p = strlen(key); j < p; j++)
//convert key to numerical
{
if (isupper(key[j]) > 'A')
{
k = (key[j] - 65);
//calculate ciphertext and print (upper case)
{
printf("%c", (plain[i] + (k % p) %26) +65);
}
}
else if (islower(key[j]) > 'a')
{
k = (key[j] - 97);
{
printf("%c", (plain[i] + (k % p) %26) +97);
}
}
else printf("%c", plain[i]);
}
}
}
{
printf("n");
}
}
}
cs50 vigenere
asked Nov 20 at 12:17
neumeaudio
1
add a comment |
up vote
0
down vote
favorite
Apologies if the answer to this is incredibly simple. I just can't work it out.
I've been working on the CS50 Vigenere problem and I think I'm almost there. However the program loops in a way that I don't expect and I'm not sure why. Once it has printed the first ciphered character of the plaintext, it loops back to move to the next character in the key but misses out the part where it needs to move to the next character of the plain text. At least I think that is what is happening.
Here is my code. Any help would be greatly appreciated.
#include <cs50.h>
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, string argv )
{
int a;
int ciphertext;
int k;
string plain;
int cipher;
// check user has input a valid number of arguments
if (argc < 2 || argc > 2)
{
printf("please input a valid number of argumentsn");
return 1;
}
// check user has input a valid key and prompt for plaintext
char * key = argv [1];
for (a = 0; a < strlen(key); a++)
if (!isalpha(key[a]))
{
printf("Please input a valid key. Key must be alphabetical");
return 1;
}
{
if (a == strlen(key))
{
plain = get_string("Plaintext: ");
}
{
printf("ciphertext: ");
}
}
//read plaintext and keep track
{
for (int i = 0, n = strlen(plain); i < n; i++)
{
//read key and keep track
if (isalpha(plain[i]))
{
for (int j = 0, p = strlen(key); j < p; j++)
//convert key to numerical
{
if (isupper(key[j]) > 'A')
{
k = (key[j] - 65);
//calculate ciphertext and print (upper case)
{
printf("%c", (plain[i] + (k % p) %26) +65);
}
}
else if (islower(key[j]) > 'a')
{
k = (key[j] - 97);
{
printf("%c", (plain[i] + (k % p) %26) +97);
}
}
else printf("%c", plain[i]);
}
}
}
{
printf("n");
}
}
}
cs50 vigenere
asked Nov 20 at 12:17
neumeaudio
1
1
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Apologies if the answer to this is incredibly simple. I just can't work it out.
I've been working on the CS50 Vigenere problem and I think I'm almost there. However the program loops in a way that I don't expect and I'm not sure why. Once it has printed the first ciphered character of the plaintext, it loops back to move to the next character in the key but misses out the part where it needs to move to the next character of the plain text. At least I think that is what is happening.
Here is my code. Any help would be greatly appreciated.
#include <cs50.h>
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, string argv )
{
int a;
int ciphertext;
int k;
string plain;
int cipher;
// check user has input a valid number of arguments
if (argc < 2 || argc > 2)
{
printf("please input a valid number of argumentsn");
return 1;
}
// check user has input a valid key and prompt for plaintext
char * key = argv [1];
for (a = 0; a < strlen(key); a++)
if (!isalpha(key[a]))
{
printf("Please input a valid key. Key must be alphabetical");
return 1;
}
{
if (a == strlen(key))
{
plain = get_string("Plaintext: ");
}
{
printf("ciphertext: ");
}
}
//read plaintext and keep track
{
for (int i = 0, n = strlen(plain); i < n; i++)
{
//read key and keep track
if (isalpha(plain[i]))
{
for (int j = 0, p = strlen(key); j < p; j++)
//convert key to numerical
{
if (isupper(key[j]) > 'A')
{
k = (key[j] - 65);
//calculate ciphertext and print (upper case)
{
printf("%c", (plain[i] + (k % p) %26) +65);
}
}
else if (islower(key[j]) > 'a')
{
k = (key[j] - 97);
{
printf("%c", (plain[i] + (k % p) %26) +97);
}
}
else printf("%c", plain[i]);
}
}
}
{
printf("n");
}
}
}
cs50 vigenere
asked Nov 20 at 12:17
neumeaudio
1
Apologies if the answer to this is incredibly simple. I just can't work it out.
I've been working on the CS50 Vigenere problem and I think I'm almost there. However the program loops in a way that I don't expect and I'm not sure why. Once it has printed the first ciphered character of the plaintext, it loops back to move to the next character in the key but misses out the part where it needs to move to the next character of the plain text. At least I think that is what is happening.
Here is my code. Any help would be greatly appreciated.
#include <cs50.h>
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, string argv )
{
int a;
int ciphertext;
int k;
string plain;
int cipher;
// check user has input a valid number of arguments
if (argc < 2 || argc > 2)
{
printf("please input a valid number of argumentsn");
return 1;
}
// check user has input a valid key and prompt for plaintext
char * key = argv [1];
for (a = 0; a < strlen(key); a++)
if (!isalpha(key[a]))
{
printf("Please input a valid key. Key must be alphabetical");
return 1;
}
{
if (a == strlen(key))
{
plain = get_string("Plaintext: ");
}
{
printf("ciphertext: ");
}
}
//read plaintext and keep track
{
for (int i = 0, n = strlen(plain); i < n; i++)
{
//read key and keep track
if (isalpha(plain[i]))
{
for (int j = 0, p = strlen(key); j < p; j++)
//convert key to numerical
{
if (isupper(key[j]) > 'A')
{
k = (key[j] - 65);
//calculate ciphertext and print (upper case)
{
printf("%c", (plain[i] + (k % p) %26) +65);
}
}
else if (islower(key[j]) > 'a')
{
k = (key[j] - 97);
{
printf("%c", (plain[i] + (k % p) %26) +97);
}
}
else printf("%c", plain[i]);
}
}
}
{
printf("n");
}
}
}
cs50 vigenere
cs50 vigenere
asked Nov 20 at 12:17
neumeaudio
1
asked Nov 20 at 12:17
neumeaudio
1
asked Nov 20 at 12:17
neumeaudio
1
asked Nov 20 at 12:17
neumeaudio
1
asked Nov 20 at 12:17
neumeaudio
1
1
1
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26
add a comment |
1
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26
1
1
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26
add a comment |
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1
Please format your code consistently. The misaligned and variable indentation makes unreadable.
– Andrew Henle
Nov 20 at 12:23
Sorry. I'm still grasping accepted conventions. I will do my best.
– neumeaudio
Nov 20 at 12:26