convert HttpServletResponse to FileInputStream











up vote
0
down vote

favorite












I have a Zip file downloaded from FTP server and the downloaded file is available in the HttpServletResponse object.



I have already written an utility program to decompress archived files using FileInputStream.



I now want to first convert the HttpServletResponse to FileInputStream so that I can decompress the downloaded file and upload it back to the FTP server location.



I am thinking of writing a program to create a temporary file to move the data from HttpServletResponse to FileInputStream but I am skeptical about it. Below is the sample program.



HttpServletResponse response
...
//Programming logic to download file from FTP to response object
...
FileInputStream fis = null;
FileChannel inputChannel = null;
FileChannel outputChannel = null;
Path archiveFilePath = Files.createTempFile(fileName, null);
OutputStream outStream = (OutputStream) response.getOutputStream();
if(outStream != null) {
FileOutputStream fos = (FileOutputStream) outStream;
outputChannel = fos.getChannel();
fis = new FileInputStream(archiveFilePath.toFile());
inputChannel = fis.getChannel();
outputChannel.transferTo(0, inputChannel.size(), inputChannel);
outputChannel.close();
fos.close();
}


Can anyone help me understand how do we convert from HttpServletResponse to FileInputStream? What needs to be done to make the above program work as required.



Any help on this topic is much appreciated.



Regards,



Alphonsa










share|improve this question




























    up vote
    0
    down vote

    favorite












    I have a Zip file downloaded from FTP server and the downloaded file is available in the HttpServletResponse object.



    I have already written an utility program to decompress archived files using FileInputStream.



    I now want to first convert the HttpServletResponse to FileInputStream so that I can decompress the downloaded file and upload it back to the FTP server location.



    I am thinking of writing a program to create a temporary file to move the data from HttpServletResponse to FileInputStream but I am skeptical about it. Below is the sample program.



    HttpServletResponse response
    ...
    //Programming logic to download file from FTP to response object
    ...
    FileInputStream fis = null;
    FileChannel inputChannel = null;
    FileChannel outputChannel = null;
    Path archiveFilePath = Files.createTempFile(fileName, null);
    OutputStream outStream = (OutputStream) response.getOutputStream();
    if(outStream != null) {
    FileOutputStream fos = (FileOutputStream) outStream;
    outputChannel = fos.getChannel();
    fis = new FileInputStream(archiveFilePath.toFile());
    inputChannel = fis.getChannel();
    outputChannel.transferTo(0, inputChannel.size(), inputChannel);
    outputChannel.close();
    fos.close();
    }


    Can anyone help me understand how do we convert from HttpServletResponse to FileInputStream? What needs to be done to make the above program work as required.



    Any help on this topic is much appreciated.



    Regards,



    Alphonsa










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a Zip file downloaded from FTP server and the downloaded file is available in the HttpServletResponse object.



      I have already written an utility program to decompress archived files using FileInputStream.



      I now want to first convert the HttpServletResponse to FileInputStream so that I can decompress the downloaded file and upload it back to the FTP server location.



      I am thinking of writing a program to create a temporary file to move the data from HttpServletResponse to FileInputStream but I am skeptical about it. Below is the sample program.



      HttpServletResponse response
      ...
      //Programming logic to download file from FTP to response object
      ...
      FileInputStream fis = null;
      FileChannel inputChannel = null;
      FileChannel outputChannel = null;
      Path archiveFilePath = Files.createTempFile(fileName, null);
      OutputStream outStream = (OutputStream) response.getOutputStream();
      if(outStream != null) {
      FileOutputStream fos = (FileOutputStream) outStream;
      outputChannel = fos.getChannel();
      fis = new FileInputStream(archiveFilePath.toFile());
      inputChannel = fis.getChannel();
      outputChannel.transferTo(0, inputChannel.size(), inputChannel);
      outputChannel.close();
      fos.close();
      }


      Can anyone help me understand how do we convert from HttpServletResponse to FileInputStream? What needs to be done to make the above program work as required.



      Any help on this topic is much appreciated.



      Regards,



      Alphonsa










      share|improve this question















      I have a Zip file downloaded from FTP server and the downloaded file is available in the HttpServletResponse object.



      I have already written an utility program to decompress archived files using FileInputStream.



      I now want to first convert the HttpServletResponse to FileInputStream so that I can decompress the downloaded file and upload it back to the FTP server location.



      I am thinking of writing a program to create a temporary file to move the data from HttpServletResponse to FileInputStream but I am skeptical about it. Below is the sample program.



      HttpServletResponse response
      ...
      //Programming logic to download file from FTP to response object
      ...
      FileInputStream fis = null;
      FileChannel inputChannel = null;
      FileChannel outputChannel = null;
      Path archiveFilePath = Files.createTempFile(fileName, null);
      OutputStream outStream = (OutputStream) response.getOutputStream();
      if(outStream != null) {
      FileOutputStream fos = (FileOutputStream) outStream;
      outputChannel = fos.getChannel();
      fis = new FileInputStream(archiveFilePath.toFile());
      inputChannel = fis.getChannel();
      outputChannel.transferTo(0, inputChannel.size(), inputChannel);
      outputChannel.close();
      fos.close();
      }


      Can anyone help me understand how do we convert from HttpServletResponse to FileInputStream? What needs to be done to make the above program work as required.



      Any help on this topic is much appreciated.



      Regards,



      Alphonsa







      servlets fileinputstream






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 at 15:53

























      asked Nov 20 at 12:16









      Alphonsa

      113




      113





























          active

          oldest

          votes











          Your Answer






          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "1"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53392808%2fconvert-httpservletresponse-to-fileinputstream%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.





          Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


          Please pay close attention to the following guidance:


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53392808%2fconvert-httpservletresponse-to-fileinputstream%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Feedback on college project

          Futebolista

          Albești (Vaslui)