R and Pandas: R equivalent of np.sum and np.reshape
up vote
-1
down vote
favorite
I have two line of code which I want to convert to R from Python:
Can anyone convert the below line of code from python to R:
np.sum([[0, 1], [0, 5]], axis=0)
&
np.reshape(li, [-1, N])
li is the list of elements and N is any variable.
python r pandas numpy reshape
asked Nov 19 at 13:10
apoorv parmar
346
add a comment |
up vote
-1
down vote
favorite
I have two line of code which I want to convert to R from Python:
Can anyone convert the below line of code from python to R:
np.sum([[0, 1], [0, 5]], axis=0)
&
np.reshape(li, [-1, N])
li is the list of elements and N is any variable.
python r pandas numpy reshape
asked Nov 19 at 13:10
apoorv parmar
346
You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I have two line of code which I want to convert to R from Python:
Can anyone convert the below line of code from python to R:
np.sum([[0, 1], [0, 5]], axis=0)
&
np.reshape(li, [-1, N])
li is the list of elements and N is any variable.
python r pandas numpy reshape
asked Nov 19 at 13:10
apoorv parmar
346
I have two line of code which I want to convert to R from Python:
Can anyone convert the below line of code from python to R:
np.sum([[0, 1], [0, 5]], axis=0)
&
np.reshape(li, [-1, N])
li is the list of elements and N is any variable.
python r pandas numpy reshape
python r pandas numpy reshape
asked Nov 19 at 13:10
apoorv parmar
346
asked Nov 19 at 13:10
apoorv parmar
346
asked Nov 19 at 13:10
apoorv parmar
346
asked Nov 19 at 13:10
apoorv parmar
346
asked Nov 19 at 13:10
apoorv parmar
346
346
You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21
add a comment |
You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21
You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21
add a comment |
1 Answer
1
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oldest
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up vote
1
down vote
Example data in R -
mat<-matrix(c(0,5,0,1), nrow=2, ncol=2)
This is what it will look like -
[,1] [,2]
[1,] 0 0
[2,] 5 1
1st part
rowSums(mat)
Output will look like this -
[1] 0 6
If this doesn't seem to work as per needs try colSums (equivalent to varying axis in numpy)
2nd Part
matrix(mat, 1, length(mat))
This will flatten the array similar to np.reshape()
[,1] [,2] [,3] [,4]
[1,] 0 5 0 1
This is the part where you want to flatten your matrix. reshape in numpy can be re-written in R by calling the matrix() function to re-cast the existing mat object
Note
This is a pure R implementation (standard libs). There are many other libraries like rehsape2 that will do it in different ways
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Example data in R -
mat<-matrix(c(0,5,0,1), nrow=2, ncol=2)
This is what it will look like -
[,1] [,2]
[1,] 0 0
[2,] 5 1
1st part
rowSums(mat)
Output will look like this -
[1] 0 6
If this doesn't seem to work as per needs try colSums (equivalent to varying axis in numpy)
2nd Part
matrix(mat, 1, length(mat))
This will flatten the array similar to np.reshape()
[,1] [,2] [,3] [,4]
[1,] 0 5 0 1
This is the part where you want to flatten your matrix. reshape in numpy can be re-written in R by calling the matrix() function to re-cast the existing mat object
Note
This is a pure R implementation (standard libs). There are many other libraries like rehsape2 that will do it in different ways
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
add a comment |
up vote
1
down vote
Example data in R -
mat<-matrix(c(0,5,0,1), nrow=2, ncol=2)
This is what it will look like -
[,1] [,2]
[1,] 0 0
[2,] 5 1
1st part
rowSums(mat)
Output will look like this -
[1] 0 6
If this doesn't seem to work as per needs try colSums (equivalent to varying axis in numpy)
2nd Part
matrix(mat, 1, length(mat))
This will flatten the array similar to np.reshape()
[,1] [,2] [,3] [,4]
[1,] 0 5 0 1
This is the part where you want to flatten your matrix. reshape in numpy can be re-written in R by calling the matrix() function to re-cast the existing mat object
Note
This is a pure R implementation (standard libs). There are many other libraries like rehsape2 that will do it in different ways
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
add a comment |
up vote
1
down vote
up vote
1
down vote
Example data in R -
mat<-matrix(c(0,5,0,1), nrow=2, ncol=2)
This is what it will look like -
[,1] [,2]
[1,] 0 0
[2,] 5 1
1st part
rowSums(mat)
Output will look like this -
[1] 0 6
If this doesn't seem to work as per needs try colSums (equivalent to varying axis in numpy)
2nd Part
matrix(mat, 1, length(mat))
This will flatten the array similar to np.reshape()
[,1] [,2] [,3] [,4]
[1,] 0 5 0 1
This is the part where you want to flatten your matrix. reshape in numpy can be re-written in R by calling the matrix() function to re-cast the existing mat object
Note
This is a pure R implementation (standard libs). There are many other libraries like rehsape2 that will do it in different ways
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
Example data in R -
mat<-matrix(c(0,5,0,1), nrow=2, ncol=2)
This is what it will look like -
[,1] [,2]
[1,] 0 0
[2,] 5 1
1st part
rowSums(mat)
Output will look like this -
[1] 0 6
If this doesn't seem to work as per needs try colSums (equivalent to varying axis in numpy)
2nd Part
matrix(mat, 1, length(mat))
This will flatten the array similar to np.reshape()
[,1] [,2] [,3] [,4]
[1,] 0 5 0 1
This is the part where you want to flatten your matrix. reshape in numpy can be re-written in R by calling the matrix() function to re-cast the existing mat object
Note
This is a pure R implementation (standard libs). There are many other libraries like rehsape2 that will do it in different ways
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
answered Nov 19 at 13:28
Vivek Kalyanarangan
4,0521725
4,0521725
add a comment |
add a comment |
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You can add also input/output data, because sometimes R coder cannot run this code...
– jezrael
Nov 19 at 13:11
np.sum([[0, 1], [0, 5]], axis=0) should result in array([0, 6]) For np.reshape(li, [-1, N]), I am not able to understand how this works and what is being done here. I am currently converting the python code to R and not able to understand this. li is ['1',2','3,], single dimensional array
– apoorv parmar
Nov 19 at 13:21