Does “V contains S” have two different meanings?











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Talking in terms of sets, I would take the above to mean $S in V$. But my course's notes says




Let $S$ be a subset of a vector space $V$, the span of $S$, denoted $Span(S)$ is the smallest subspace of $V$ that contains $S$.




Which confuses me, because $V$ contains vectors, whereas $S$ is a set, not a vector, so by my definition, $V$ cannot contains $S$.



So by "$V$ contains $S$" I assume it means $S subseteq V$, right? Is this considered correct also?










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    up vote
    3
    down vote

    favorite












    Talking in terms of sets, I would take the above to mean $S in V$. But my course's notes says




    Let $S$ be a subset of a vector space $V$, the span of $S$, denoted $Span(S)$ is the smallest subspace of $V$ that contains $S$.




    Which confuses me, because $V$ contains vectors, whereas $S$ is a set, not a vector, so by my definition, $V$ cannot contains $S$.



    So by "$V$ contains $S$" I assume it means $S subseteq V$, right? Is this considered correct also?










    share|cite|improve this question
























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      Talking in terms of sets, I would take the above to mean $S in V$. But my course's notes says




      Let $S$ be a subset of a vector space $V$, the span of $S$, denoted $Span(S)$ is the smallest subspace of $V$ that contains $S$.




      Which confuses me, because $V$ contains vectors, whereas $S$ is a set, not a vector, so by my definition, $V$ cannot contains $S$.



      So by "$V$ contains $S$" I assume it means $S subseteq V$, right? Is this considered correct also?










      share|cite|improve this question













      Talking in terms of sets, I would take the above to mean $S in V$. But my course's notes says




      Let $S$ be a subset of a vector space $V$, the span of $S$, denoted $Span(S)$ is the smallest subspace of $V$ that contains $S$.




      Which confuses me, because $V$ contains vectors, whereas $S$ is a set, not a vector, so by my definition, $V$ cannot contains $S$.



      So by "$V$ contains $S$" I assume it means $S subseteq V$, right? Is this considered correct also?







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          Yes. Unfortunately, "$x$ contains $y$" is ambiguous: it can mean either $yin x$ or $ysubseteq x$. Some writers make this distinction between "contains" and "includes": a set contains its elements and includes its subsets. Unfortunately, some do just the opposite, and say that a set includes its elements and contains its subsets. Sorry about that.






          share|cite|improve this answer





















          • In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
            – Barry Cipra
            4 hours ago












          • @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
            – bof
            3 hours ago










          • I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
            – Mong H. Ng
            2 hours ago


















          up vote
          1
          down vote













          $S$ is a set of vectors in $V$ which is not necessarily a subspace of $V$. So you can for example have $S= {v_1,v_2,...}$ However, when you take all linear combinations of vectors in $S$, you get the $span(S)={a_1v_1+a_2v_2+...|a_i in F,v_i in S}$, here $F$ is the underlying field of $v$, which is a subspace of $V$.



          I mean you could have $S subset V$. Take for example $V=mathbb{R}^3$ and $S={(1,0,0),(0,0,1)}$, $Span(S)=x-z plane$.






          share|cite|improve this answer





















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            2 Answers
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            up vote
            4
            down vote













            Yes. Unfortunately, "$x$ contains $y$" is ambiguous: it can mean either $yin x$ or $ysubseteq x$. Some writers make this distinction between "contains" and "includes": a set contains its elements and includes its subsets. Unfortunately, some do just the opposite, and say that a set includes its elements and contains its subsets. Sorry about that.






            share|cite|improve this answer





















            • In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
              – Barry Cipra
              4 hours ago












            • @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
              – bof
              3 hours ago










            • I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
              – Mong H. Ng
              2 hours ago















            up vote
            4
            down vote













            Yes. Unfortunately, "$x$ contains $y$" is ambiguous: it can mean either $yin x$ or $ysubseteq x$. Some writers make this distinction between "contains" and "includes": a set contains its elements and includes its subsets. Unfortunately, some do just the opposite, and say that a set includes its elements and contains its subsets. Sorry about that.






            share|cite|improve this answer





















            • In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
              – Barry Cipra
              4 hours ago












            • @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
              – bof
              3 hours ago










            • I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
              – Mong H. Ng
              2 hours ago













            up vote
            4
            down vote










            up vote
            4
            down vote









            Yes. Unfortunately, "$x$ contains $y$" is ambiguous: it can mean either $yin x$ or $ysubseteq x$. Some writers make this distinction between "contains" and "includes": a set contains its elements and includes its subsets. Unfortunately, some do just the opposite, and say that a set includes its elements and contains its subsets. Sorry about that.






            share|cite|improve this answer












            Yes. Unfortunately, "$x$ contains $y$" is ambiguous: it can mean either $yin x$ or $ysubseteq x$. Some writers make this distinction between "contains" and "includes": a set contains its elements and includes its subsets. Unfortunately, some do just the opposite, and say that a set includes its elements and contains its subsets. Sorry about that.







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered 4 hours ago









            bof

            48.6k451115




            48.6k451115












            • In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
              – Barry Cipra
              4 hours ago












            • @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
              – bof
              3 hours ago










            • I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
              – Mong H. Ng
              2 hours ago


















            • In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
              – Barry Cipra
              4 hours ago












            • @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
              – bof
              3 hours ago










            • I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
              – Mong H. Ng
              2 hours ago
















            In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
            – Barry Cipra
            4 hours ago






            In Naive Set Theory (1960), Paul Halmos has sets containing their elements and including their subsets. Do you know of any books that do the opposite? (I suspect some authors may use one word, or both, in both senses, but it'd be good to have an example or two of that as well.)
            – Barry Cipra
            4 hours ago














            @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
            – bof
            3 hours ago




            @BarryCipra I recall that C. St. J. A. Nash-Williams, in (at least) one of his series of papers on well-quasi-ordering, stated explicitly that sets include their elements and contain their subsets. I recall being surprised by this, as I was used to seeing it done the other way. Unfortunately I don't have an exact reference.
            – bof
            3 hours ago












            I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
            – Mong H. Ng
            2 hours ago




            I thought there isnt really an issue, as the context usually gives you a hint about whether it is referring to a set or a single element.
            – Mong H. Ng
            2 hours ago










            up vote
            1
            down vote













            $S$ is a set of vectors in $V$ which is not necessarily a subspace of $V$. So you can for example have $S= {v_1,v_2,...}$ However, when you take all linear combinations of vectors in $S$, you get the $span(S)={a_1v_1+a_2v_2+...|a_i in F,v_i in S}$, here $F$ is the underlying field of $v$, which is a subspace of $V$.



            I mean you could have $S subset V$. Take for example $V=mathbb{R}^3$ and $S={(1,0,0),(0,0,1)}$, $Span(S)=x-z plane$.






            share|cite|improve this answer

























              up vote
              1
              down vote













              $S$ is a set of vectors in $V$ which is not necessarily a subspace of $V$. So you can for example have $S= {v_1,v_2,...}$ However, when you take all linear combinations of vectors in $S$, you get the $span(S)={a_1v_1+a_2v_2+...|a_i in F,v_i in S}$, here $F$ is the underlying field of $v$, which is a subspace of $V$.



              I mean you could have $S subset V$. Take for example $V=mathbb{R}^3$ and $S={(1,0,0),(0,0,1)}$, $Span(S)=x-z plane$.






              share|cite|improve this answer























                up vote
                1
                down vote










                up vote
                1
                down vote









                $S$ is a set of vectors in $V$ which is not necessarily a subspace of $V$. So you can for example have $S= {v_1,v_2,...}$ However, when you take all linear combinations of vectors in $S$, you get the $span(S)={a_1v_1+a_2v_2+...|a_i in F,v_i in S}$, here $F$ is the underlying field of $v$, which is a subspace of $V$.



                I mean you could have $S subset V$. Take for example $V=mathbb{R}^3$ and $S={(1,0,0),(0,0,1)}$, $Span(S)=x-z plane$.






                share|cite|improve this answer












                $S$ is a set of vectors in $V$ which is not necessarily a subspace of $V$. So you can for example have $S= {v_1,v_2,...}$ However, when you take all linear combinations of vectors in $S$, you get the $span(S)={a_1v_1+a_2v_2+...|a_i in F,v_i in S}$, here $F$ is the underlying field of $v$, which is a subspace of $V$.



                I mean you could have $S subset V$. Take for example $V=mathbb{R}^3$ and $S={(1,0,0),(0,0,1)}$, $Span(S)=x-z plane$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 4 hours ago









                mathnoob

                82211




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