Implement State Monad transformer in Haskell from scratch











up vote
0
down vote

favorite












When I was studying Monad Transformer, I decided to create StateT s m a from scratch with instances for Functor, Applicative and Monad.



This is what I have:



newtype StateT s m a = StateT { runStateT :: (s -> m (a, s)) }

instance Functor m => Functor (StateT s m) where
-- fmap :: (a -> b) -> StateT s m a -> StateT s m b
-- which is (a -> b) -> (s -> m (a, s)) -> (s -> m (b, s))
f `fmap` (StateT x) = StateT $ s -> fmap run (x s)
where run (a, s) = (f a, s)

instance Monad m => Applicative (StateT s m) where
-- pure :: a -> StateT s m a
pure a = StateT $ s -> pure (a, s)
-- <*> :: f (a -> b) -> f a -> f b
-- which is StateT s m (a -> b) -> StateT s m a -> State s m b
k <*> x = StateT $ s -> do
(f, s1) <- runStateT k s -- :: m ((a -> b), s)
(a, s2) <- runStateT x s1
return (f a, s2)

instance (Monad m) => Monad (StateT s m) where
return a = StateT $ s -> return (a, s)
-- >>= :: StateT s m a -> (a -> StateT s m b) -> StateT s m b
(StateT x) >>= f = StateT $ s -> do
(v, s') <- x s
runStateT (f v) s'


My original intention is to implement Functor (StateT s m) with Functor m restriction, Applicative (StateT s m) with Applicative m restriction, and Monad (StateT s m) withMonad m) restriction. However I couldn't do the Applicative case and had to use Monad m restriction instead. Is there a way to do it with Applicative m?



Thank you in advance.










share|improve this question


























    up vote
    0
    down vote

    favorite












    When I was studying Monad Transformer, I decided to create StateT s m a from scratch with instances for Functor, Applicative and Monad.



    This is what I have:



    newtype StateT s m a = StateT { runStateT :: (s -> m (a, s)) }

    instance Functor m => Functor (StateT s m) where
    -- fmap :: (a -> b) -> StateT s m a -> StateT s m b
    -- which is (a -> b) -> (s -> m (a, s)) -> (s -> m (b, s))
    f `fmap` (StateT x) = StateT $ s -> fmap run (x s)
    where run (a, s) = (f a, s)

    instance Monad m => Applicative (StateT s m) where
    -- pure :: a -> StateT s m a
    pure a = StateT $ s -> pure (a, s)
    -- <*> :: f (a -> b) -> f a -> f b
    -- which is StateT s m (a -> b) -> StateT s m a -> State s m b
    k <*> x = StateT $ s -> do
    (f, s1) <- runStateT k s -- :: m ((a -> b), s)
    (a, s2) <- runStateT x s1
    return (f a, s2)

    instance (Monad m) => Monad (StateT s m) where
    return a = StateT $ s -> return (a, s)
    -- >>= :: StateT s m a -> (a -> StateT s m b) -> StateT s m b
    (StateT x) >>= f = StateT $ s -> do
    (v, s') <- x s
    runStateT (f v) s'


    My original intention is to implement Functor (StateT s m) with Functor m restriction, Applicative (StateT s m) with Applicative m restriction, and Monad (StateT s m) withMonad m) restriction. However I couldn't do the Applicative case and had to use Monad m restriction instead. Is there a way to do it with Applicative m?



    Thank you in advance.










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      When I was studying Monad Transformer, I decided to create StateT s m a from scratch with instances for Functor, Applicative and Monad.



      This is what I have:



      newtype StateT s m a = StateT { runStateT :: (s -> m (a, s)) }

      instance Functor m => Functor (StateT s m) where
      -- fmap :: (a -> b) -> StateT s m a -> StateT s m b
      -- which is (a -> b) -> (s -> m (a, s)) -> (s -> m (b, s))
      f `fmap` (StateT x) = StateT $ s -> fmap run (x s)
      where run (a, s) = (f a, s)

      instance Monad m => Applicative (StateT s m) where
      -- pure :: a -> StateT s m a
      pure a = StateT $ s -> pure (a, s)
      -- <*> :: f (a -> b) -> f a -> f b
      -- which is StateT s m (a -> b) -> StateT s m a -> State s m b
      k <*> x = StateT $ s -> do
      (f, s1) <- runStateT k s -- :: m ((a -> b), s)
      (a, s2) <- runStateT x s1
      return (f a, s2)

      instance (Monad m) => Monad (StateT s m) where
      return a = StateT $ s -> return (a, s)
      -- >>= :: StateT s m a -> (a -> StateT s m b) -> StateT s m b
      (StateT x) >>= f = StateT $ s -> do
      (v, s') <- x s
      runStateT (f v) s'


      My original intention is to implement Functor (StateT s m) with Functor m restriction, Applicative (StateT s m) with Applicative m restriction, and Monad (StateT s m) withMonad m) restriction. However I couldn't do the Applicative case and had to use Monad m restriction instead. Is there a way to do it with Applicative m?



      Thank you in advance.










      share|improve this question













      When I was studying Monad Transformer, I decided to create StateT s m a from scratch with instances for Functor, Applicative and Monad.



      This is what I have:



      newtype StateT s m a = StateT { runStateT :: (s -> m (a, s)) }

      instance Functor m => Functor (StateT s m) where
      -- fmap :: (a -> b) -> StateT s m a -> StateT s m b
      -- which is (a -> b) -> (s -> m (a, s)) -> (s -> m (b, s))
      f `fmap` (StateT x) = StateT $ s -> fmap run (x s)
      where run (a, s) = (f a, s)

      instance Monad m => Applicative (StateT s m) where
      -- pure :: a -> StateT s m a
      pure a = StateT $ s -> pure (a, s)
      -- <*> :: f (a -> b) -> f a -> f b
      -- which is StateT s m (a -> b) -> StateT s m a -> State s m b
      k <*> x = StateT $ s -> do
      (f, s1) <- runStateT k s -- :: m ((a -> b), s)
      (a, s2) <- runStateT x s1
      return (f a, s2)

      instance (Monad m) => Monad (StateT s m) where
      return a = StateT $ s -> return (a, s)
      -- >>= :: StateT s m a -> (a -> StateT s m b) -> StateT s m b
      (StateT x) >>= f = StateT $ s -> do
      (v, s') <- x s
      runStateT (f v) s'


      My original intention is to implement Functor (StateT s m) with Functor m restriction, Applicative (StateT s m) with Applicative m restriction, and Monad (StateT s m) withMonad m) restriction. However I couldn't do the Applicative case and had to use Monad m restriction instead. Is there a way to do it with Applicative m?



      Thank you in advance.







      haskell monads






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 27 mins ago









      dhu

      614




      614



























          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ifUsing("editor", function () {
          StackExchange.using("externalEditor", function () {
          StackExchange.using("snippets", function () {
          StackExchange.snippets.init();
          });
          });
          }, "code-snippets");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "196"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: false,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: null,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














           

          draft saved


          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208363%2fimplement-state-monad-transformer-in-haskell-from-scratch%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown






























          active

          oldest

          votes













          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















           

          draft saved


          draft discarded



















































           


          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f208363%2fimplement-state-monad-transformer-in-haskell-from-scratch%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          404 Error Contact Form 7 ajax form submitting

          How to know if a Active Directory user can login interactively

          Refactoring coordinates for Minecraft Pi buildings written in Python