Tukukkk

I have an old XmlNode-based code. but the simplest way to solve my current task is to use XElement and LINQ-to-XML. The only problem is that there is no direct or obvious method for converting a XmlNode to a XElement in .NET Framework.

So for starters, I want to implement a method that receives a XmlNode instance and converts it to a XElement instance.

How can I implement this conversion?

var xElem = XElement.Load( xmlElement.CreateNavigator().ReadSubtree() );

There are two problems with xmlElement.InnerXml used in other answer,

1- You will loose the root element (Of course, it can be handled easily)

XmlDocument doc = new XmlDocument();

doc.LoadXml("<root> <sub>aaa</sub> </root>");

var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());

var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml);

xElem2 will be <sub>aaa</sub>, without(root)

2- You will get exception if your xml contains text nodes

XmlDocument doc = new XmlDocument();

doc.LoadXml("<root> text <sub>aaa</sub> </root>");

var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());

var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml); //<-- XmlException

You can try using InnerXml property of XmlElement to get xml content of your element then parse it to XElement using XElement.Parse:

public static XElement ToXELement(this XmlElement source)

{

    return XElement.Parse(source.InnerXml);

}

just use it: XElement e = XElement.Load(node.CreateReader());

I hope that helps.

Example:

A real code example
The image code above

public static XNode GetNodeByFilter(XNode node,ref SortedList filter, int position = 1)
{

XNode result = null;

        if (filter.TryGetValue(position, out XMLSearchCriteria criteria))

        {

            while (node != null)

            {

                XElement e = XElement.Load(node.CreateReader());

                if (e.Name.LocalName.Equals(criteria.Node) && CheckIfAllAttributesMatch(e.Attributes(), criteria.Attributes))

                {

                    if (++position <= filter.Count)

                    {

                        result = GetNodeByFilter(e.FirstNode, ref filter, position);

                        break;

                    }

                    else

                    {

                        result = node;

                    }

                }



                node = node.NextNode;

            }

        }



        return result;

    }

There actually is a very straightforward way to convert an XNode to an XElement:

static XElement ToXElement( XNode node)

{

    return node as XElement; // returns null if node is not an XElement

}

If you are 100% certain the node is an XElement (or you are prepared to deal with the exception if it is not, then you can simply cast: (XElement)node.

As far as I know, you can do this:

XElement xdoc = new XElement(node.Name, node.InnerXml);