A simple function that removes empty or tags containing just ' '












0














I've written a function that should get rid of empty p, span, etc tags and those with just ' ' and am looking for ways to improve it. My original solution was very 'wet', but I've managed to come up with a drier solution.



The Original HTML:



<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id='test'>
<p>text</p>
<p>&nbsp;</p>
<p>text</p>
<p><span>text</span></p>
<p><span></span></p>
<p>text</p>
<p><strong>text</strong></p>
<p></p>
<p>&nbsp;</p>
<p>text</p>
<p><span><strong>&nbsp;</strong></span></p>
<p><span><strong>text</strong></span></p>
<p>&nbsp;</p>
<p><span>text</span></p>
<p></p>
<p><span></span></p>
<p><span>&nbsp;</span></p>
<p><span><strong></strong></span></p>
<p>text</p>
</div>


My Original Solution:



/*
How to make this drier?
ORIGINAL UNCLEAN SOLUTION
*/
var ps = document.getElementsByTagName('p'),
spans = document.getElementsByTagName('span'),
strongs = document.getElementsByTagName('strong');

for (let el of ps) {
if (el.innerHTML == '&nbsp;') { // can't also include if '' at this stage
el.parentNode.removeChild(el);
}
}
for (let el of spans) {
if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
el.parentNode.removeChild(el);
}
}
for (let el of strongs) {
if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
el.parentNode.removeChild(el);
}
}
for (let el of ps) {
if (el.innerHTML == '') {
el.parentNode.removeChild(el);
}
}


My 'drier' solution:



/*
MY CLEANER SOLUTION
*/
var ps = document.getElementsByTagName('p'),
spans = document.getElementsByTagName('span'),
strongs = document.getElementsByTagName('strong');

for (let el of ps) {
cleaner(el);
}
for (let el of spans) {
cleaner(el);
}
for (let el of strongs) {
cleaner(el);
}

function cleaner(el) {
if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
el.parentNode.removeChild(el);
}
}


Would someone mind quickly running over both solutions and verifying that my 2nd solution is best? Also, I wonder whether that could be improved, or whether anyone has any better ideas for a solution? Thanks for the help here - for brevity, I'm looking at writing concise but also clear code.










share|improve this question



























    0














    I've written a function that should get rid of empty p, span, etc tags and those with just ' ' and am looking for ways to improve it. My original solution was very 'wet', but I've managed to come up with a drier solution.



    The Original HTML:



    <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <div id='test'>
    <p>text</p>
    <p>&nbsp;</p>
    <p>text</p>
    <p><span>text</span></p>
    <p><span></span></p>
    <p>text</p>
    <p><strong>text</strong></p>
    <p></p>
    <p>&nbsp;</p>
    <p>text</p>
    <p><span><strong>&nbsp;</strong></span></p>
    <p><span><strong>text</strong></span></p>
    <p>&nbsp;</p>
    <p><span>text</span></p>
    <p></p>
    <p><span></span></p>
    <p><span>&nbsp;</span></p>
    <p><span><strong></strong></span></p>
    <p>text</p>
    </div>


    My Original Solution:



    /*
    How to make this drier?
    ORIGINAL UNCLEAN SOLUTION
    */
    var ps = document.getElementsByTagName('p'),
    spans = document.getElementsByTagName('span'),
    strongs = document.getElementsByTagName('strong');

    for (let el of ps) {
    if (el.innerHTML == '&nbsp;') { // can't also include if '' at this stage
    el.parentNode.removeChild(el);
    }
    }
    for (let el of spans) {
    if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
    el.parentNode.removeChild(el);
    }
    }
    for (let el of strongs) {
    if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
    el.parentNode.removeChild(el);
    }
    }
    for (let el of ps) {
    if (el.innerHTML == '') {
    el.parentNode.removeChild(el);
    }
    }


    My 'drier' solution:



    /*
    MY CLEANER SOLUTION
    */
    var ps = document.getElementsByTagName('p'),
    spans = document.getElementsByTagName('span'),
    strongs = document.getElementsByTagName('strong');

    for (let el of ps) {
    cleaner(el);
    }
    for (let el of spans) {
    cleaner(el);
    }
    for (let el of strongs) {
    cleaner(el);
    }

    function cleaner(el) {
    if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
    el.parentNode.removeChild(el);
    }
    }


    Would someone mind quickly running over both solutions and verifying that my 2nd solution is best? Also, I wonder whether that could be improved, or whether anyone has any better ideas for a solution? Thanks for the help here - for brevity, I'm looking at writing concise but also clear code.










    share|improve this question

























      0












      0








      0







      I've written a function that should get rid of empty p, span, etc tags and those with just ' ' and am looking for ways to improve it. My original solution was very 'wet', but I've managed to come up with a drier solution.



      The Original HTML:



      <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
      <div id='test'>
      <p>text</p>
      <p>&nbsp;</p>
      <p>text</p>
      <p><span>text</span></p>
      <p><span></span></p>
      <p>text</p>
      <p><strong>text</strong></p>
      <p></p>
      <p>&nbsp;</p>
      <p>text</p>
      <p><span><strong>&nbsp;</strong></span></p>
      <p><span><strong>text</strong></span></p>
      <p>&nbsp;</p>
      <p><span>text</span></p>
      <p></p>
      <p><span></span></p>
      <p><span>&nbsp;</span></p>
      <p><span><strong></strong></span></p>
      <p>text</p>
      </div>


      My Original Solution:



      /*
      How to make this drier?
      ORIGINAL UNCLEAN SOLUTION
      */
      var ps = document.getElementsByTagName('p'),
      spans = document.getElementsByTagName('span'),
      strongs = document.getElementsByTagName('strong');

      for (let el of ps) {
      if (el.innerHTML == '&nbsp;') { // can't also include if '' at this stage
      el.parentNode.removeChild(el);
      }
      }
      for (let el of spans) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }
      for (let el of strongs) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }
      for (let el of ps) {
      if (el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }


      My 'drier' solution:



      /*
      MY CLEANER SOLUTION
      */
      var ps = document.getElementsByTagName('p'),
      spans = document.getElementsByTagName('span'),
      strongs = document.getElementsByTagName('strong');

      for (let el of ps) {
      cleaner(el);
      }
      for (let el of spans) {
      cleaner(el);
      }
      for (let el of strongs) {
      cleaner(el);
      }

      function cleaner(el) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }


      Would someone mind quickly running over both solutions and verifying that my 2nd solution is best? Also, I wonder whether that could be improved, or whether anyone has any better ideas for a solution? Thanks for the help here - for brevity, I'm looking at writing concise but also clear code.










      share|improve this question













      I've written a function that should get rid of empty p, span, etc tags and those with just ' ' and am looking for ways to improve it. My original solution was very 'wet', but I've managed to come up with a drier solution.



      The Original HTML:



      <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
      <div id='test'>
      <p>text</p>
      <p>&nbsp;</p>
      <p>text</p>
      <p><span>text</span></p>
      <p><span></span></p>
      <p>text</p>
      <p><strong>text</strong></p>
      <p></p>
      <p>&nbsp;</p>
      <p>text</p>
      <p><span><strong>&nbsp;</strong></span></p>
      <p><span><strong>text</strong></span></p>
      <p>&nbsp;</p>
      <p><span>text</span></p>
      <p></p>
      <p><span></span></p>
      <p><span>&nbsp;</span></p>
      <p><span><strong></strong></span></p>
      <p>text</p>
      </div>


      My Original Solution:



      /*
      How to make this drier?
      ORIGINAL UNCLEAN SOLUTION
      */
      var ps = document.getElementsByTagName('p'),
      spans = document.getElementsByTagName('span'),
      strongs = document.getElementsByTagName('strong');

      for (let el of ps) {
      if (el.innerHTML == '&nbsp;') { // can't also include if '' at this stage
      el.parentNode.removeChild(el);
      }
      }
      for (let el of spans) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }
      for (let el of strongs) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }
      for (let el of ps) {
      if (el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }


      My 'drier' solution:



      /*
      MY CLEANER SOLUTION
      */
      var ps = document.getElementsByTagName('p'),
      spans = document.getElementsByTagName('span'),
      strongs = document.getElementsByTagName('strong');

      for (let el of ps) {
      cleaner(el);
      }
      for (let el of spans) {
      cleaner(el);
      }
      for (let el of strongs) {
      cleaner(el);
      }

      function cleaner(el) {
      if (el.innerHTML == '&nbsp;' || el.innerHTML == '') {
      el.parentNode.removeChild(el);
      }
      }


      Would someone mind quickly running over both solutions and verifying that my 2nd solution is best? Also, I wonder whether that could be improved, or whether anyone has any better ideas for a solution? Thanks for the help here - for brevity, I'm looking at writing concise but also clear code.







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      asked 31 mins ago









      user8758206

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      1763






















          1 Answer
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          0














          You can use querySelectorAll to simplify your code further:



          var elements = document.querySelectorAll('p, span, strong'),

          for (let el of elements) {
          cleaner(el);
          }





          share|improve this answer





















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            1 Answer
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            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            You can use querySelectorAll to simplify your code further:



            var elements = document.querySelectorAll('p, span, strong'),

            for (let el of elements) {
            cleaner(el);
            }





            share|improve this answer


























              0














              You can use querySelectorAll to simplify your code further:



              var elements = document.querySelectorAll('p, span, strong'),

              for (let el of elements) {
              cleaner(el);
              }





              share|improve this answer
























                0












                0








                0






                You can use querySelectorAll to simplify your code further:



                var elements = document.querySelectorAll('p, span, strong'),

                for (let el of elements) {
                cleaner(el);
                }





                share|improve this answer












                You can use querySelectorAll to simplify your code further:



                var elements = document.querySelectorAll('p, span, strong'),

                for (let el of elements) {
                cleaner(el);
                }






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 25 mins ago









                Carra

                1945




                1945






























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