how can i iterate through my object and display table rows in format

I have to use the .getJson method to download a file and display it on the page. I need help displaying rows in tables format, my code displays but its all over the page.

$(document).ready(function () {

    $.getJSON("data.json", function (data) {

        var topSpot = '';



        $.each(data, function (key, value) {



            $("table").append("<tr>");

            $("table").append("<td>" + value.name + "</td>");

            $("table").append("<td>" + value.description + "</td>");

            $("table").append("<td>" + value.link + "</td>");



            var link = 'https://www.google.com/maps?q=' + value.location[0] + ',' +

                value.location[1];



            topSpot += '<td>' + '<a class="btn" href="' + link + '">Google Maps 

            location</a > ' + '</td > '; 



            topSpot += '</tr>';

        });

        $('#table').append(topSpot);

    });

});

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

1

You need to think of the DOM as a tree, not as a sequence of HTML elements.

– Robby Cornelissen
Nov 22 '18 at 3:23

add a comment |

I have to use the .getJson method to download a file and display it on the page. I need help displaying rows in tables format, my code displays but its all over the page.

$(document).ready(function () {

    $.getJSON("data.json", function (data) {

        var topSpot = '';



        $.each(data, function (key, value) {



            $("table").append("<tr>");

            $("table").append("<td>" + value.name + "</td>");

            $("table").append("<td>" + value.description + "</td>");

            $("table").append("<td>" + value.link + "</td>");



            var link = 'https://www.google.com/maps?q=' + value.location[0] + ',' +

                value.location[1];



            topSpot += '<td>' + '<a class="btn" href="' + link + '">Google Maps 

            location</a > ' + '</td > '; 



            topSpot += '</tr>';

        });

        $('#table').append(topSpot);

    });

});

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

1

You need to think of the DOM as a tree, not as a sequence of HTML elements.

– Robby Cornelissen
Nov 22 '18 at 3:23

add a comment |

I have to use the .getJson method to download a file and display it on the page. I need help displaying rows in tables format, my code displays but its all over the page.

$(document).ready(function () {

    $.getJSON("data.json", function (data) {

        var topSpot = '';



        $.each(data, function (key, value) {



            $("table").append("<tr>");

            $("table").append("<td>" + value.name + "</td>");

            $("table").append("<td>" + value.description + "</td>");

            $("table").append("<td>" + value.link + "</td>");



            var link = 'https://www.google.com/maps?q=' + value.location[0] + ',' +

                value.location[1];



            topSpot += '<td>' + '<a class="btn" href="' + link + '">Google Maps 

            location</a > ' + '</td > '; 



            topSpot += '</tr>';

        });

        $('#table').append(topSpot);

    });

});

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

I have to use the .getJson method to download a file and display it on the page. I need help displaying rows in tables format, my code displays but its all over the page.

$(document).ready(function () {

    $.getJSON("data.json", function (data) {

        var topSpot = '';



        $.each(data, function (key, value) {



            $("table").append("<tr>");

            $("table").append("<td>" + value.name + "</td>");

            $("table").append("<td>" + value.description + "</td>");

            $("table").append("<td>" + value.link + "</td>");



            var link = 'https://www.google.com/maps?q=' + value.location[0] + ',' +

                value.location[1];



            topSpot += '<td>' + '<a class="btn" href="' + link + '">Google Maps 

            location</a > ' + '</td > '; 



            topSpot += '</tr>';

        });

        $('#table').append(topSpot);

    });

});

javascript

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

edited Nov 22 '18 at 3:46

dhilt

7,77241941

edited Nov 22 '18 at 3:46

dhilt

7,77241941

edited Nov 22 '18 at 3:46

dhilt

7,77241941

asked Nov 22 '18 at 3:21

junior

203

asked Nov 22 '18 at 3:21

junior

203

asked Nov 22 '18 at 3:21

junior

203

1

You need to think of the DOM as a tree, not as a sequence of HTML elements.

– Robby Cornelissen
Nov 22 '18 at 3:23

add a comment |

1

You need to think of the DOM as a tree, not as a sequence of HTML elements.

– Robby Cornelissen
Nov 22 '18 at 3:23

You need to think of the DOM as a tree, not as a sequence of HTML elements.

– Robby Cornelissen
Nov 22 '18 at 3:23

add a comment |

2 Answers
2

active

oldest

votes

I think major reason its all over the page is lack of correct css classes getting applied on the html table that you are generating. To Fix Create the div container with right type of properties and place the table inside it using $('#table').append(topSpot) and also apply css on table elements. There are multiple plugins which provides controlled table output with multiple features like sorting, searching, editing and so on e.g. http://tabulator.info/ or simple plugin like jsontotable which you can explore,

<div id="jsontotable" class="jsontotable"></div>



var data = [{'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}, {'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}];

$.jsontotable(data, { id: '#jsontotable', header: false });

answered Nov 22 '18 at 5:30

Mukund

16816

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

add a comment |

In these cases you can use Template literals, you can achieve results I think a little easier to read. Please consider the following example.

Edit: In order to use $.getJSON in the implementation, I edited the answer, I am getting data from https://jsonplaceholder.typicode.com/ for simplicity. The logic is almost the same. The difference here is to execute the render logic inside a $.getJSON callback.

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

<div id="jsontotable" class="jsontotable"></div>



var data = [{'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}, {'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}];

$.jsontotable(data, { id: '#jsontotable', header: false });

answered Nov 22 '18 at 5:30

Mukund

16816

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

add a comment |

<div id="jsontotable" class="jsontotable"></div>



var data = [{'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}, {'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}];

$.jsontotable(data, { id: '#jsontotable', header: false });

answered Nov 22 '18 at 5:30

Mukund

16816

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

add a comment |

<div id="jsontotable" class="jsontotable"></div>



var data = [{'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}, {'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}];

$.jsontotable(data, { id: '#jsontotable', header: false });

answered Nov 22 '18 at 5:30

Mukund

16816

<div id="jsontotable" class="jsontotable"></div>



var data = [{'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}, {'Title1': 'Hello', 'Title2': 'Fine', 'Title3': 'Thank you'}];

$.jsontotable(data, { id: '#jsontotable', header: false });

answered Nov 22 '18 at 5:30

Mukund

16816

answered Nov 22 '18 at 5:30

Mukund

16816

answered Nov 22 '18 at 5:30

Mukund

16816

answered Nov 22 '18 at 5:30

Mukund

16816

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

add a comment |

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

I tried your advice but couldn't get it to work. maybe I'm doing it wrong!

– junior
Nov 25 '18 at 2:57

See my code displays but i cant seem to get it to display in the correct format! My code is al over the page

– junior
Nov 25 '18 at 2:59

add a comment |

In these cases you can use Template literals, you can achieve results I think a little easier to read. Please consider the following example.

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

add a comment |

In these cases you can use Template literals, you can achieve results I think a little easier to read. Please consider the following example.

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

add a comment |

In these cases you can use Template literals, you can achieve results I think a little easier to read. Please consider the following example.

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

In these cases you can use Template literals, you can achieve results I think a little easier to read. Please consider the following example.

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

function render() {

    $.getJSON('https://jsonplaceholder.typicode.com/posts', function(data) {

      const output = document.querySelector('#output');

      const rows = data.map(toTableRows).join('');



      output.innerHTML = `<table>

        <tbody>${rows}</tbody>

      </table>`;

    });

}



function toTableRows(data) {

  return `

      <tr>

          <td>${data.title}</td>

          <td>${data.body}</td>

      </tr>`;

}



render();

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>

<!DOCTYPE html>

<html lang="en">

<head>

    <meta charset="UTF-8">

    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <meta http-equiv="X-UA-Compatible" content="ie=edge">

    <title>Document</title>

</head>

<body>

    <div id="output"></div>

</body>

</html>

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

edited Nov 25 '18 at 17:25

answered Nov 22 '18 at 3:45

user615274

1,4061219

answered Nov 22 '18 at 3:45

user615274

1,4061219

answered Nov 22 '18 at 3:45

user615274

1,4061219

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

add a comment |

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

very Good example, but I need to use the .getjson to download a file, then populate the data stored in it, my outcome should be in table row format

– junior
Nov 25 '18 at 2:24

I just edited the answer.

– user615274
Nov 25 '18 at 17:26

add a comment |

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