Hi All, I want to search this word “(Error: 87)” in my text file using Java code
0
I was trying to search this complete word "(Error: 87)" in my text file.
I used below java code.
String path = "C:\Temp\Error_Hunter";
String fileName = "\nvr-service.txt";
String testWord = "(Error: 87)";
int tLen = testWord.length();
int wordCntr = 0;
String file1 = path + fileName;
boolean check;
try{
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
//Read File Line By Line
while((strLine = br.readLine()) != null){
//check to see whether testWord occurs at least once in the line of text
check = strLine.toLowerCase().contains(testWord.toLowerCase());
if(check){
//get the line, and parse its words into a String array
String lineWords = strLine.split("\s+");
for(String w : lineWords)
{
if(w.length() >= tLen){
String word = w.substring(0,tLen).trim();
if(word.equalsIgnoreCase(testWord))
{
wordCntr++;
}
}
}
}
}
System.out.println("total is: " + wordCntr);
//Close the input stream
br.close();
} catch(Exception e){
e.printStackTrace();
}
In my text file, the word has 104 hits. but this is not finding the word. because it contain space in between. Kindly suggest something or edit in the code itself.
java text-files keyword-search wordsearch
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
add a comment |
0
I was trying to search this complete word "(Error: 87)" in my text file.
I used below java code.
String path = "C:\Temp\Error_Hunter";
String fileName = "\nvr-service.txt";
String testWord = "(Error: 87)";
int tLen = testWord.length();
int wordCntr = 0;
String file1 = path + fileName;
boolean check;
try{
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
//Read File Line By Line
while((strLine = br.readLine()) != null){
//check to see whether testWord occurs at least once in the line of text
check = strLine.toLowerCase().contains(testWord.toLowerCase());
if(check){
//get the line, and parse its words into a String array
String lineWords = strLine.split("\s+");
for(String w : lineWords)
{
if(w.length() >= tLen){
String word = w.substring(0,tLen).trim();
if(word.equalsIgnoreCase(testWord))
{
wordCntr++;
}
}
}
}
}
System.out.println("total is: " + wordCntr);
//Close the input stream
br.close();
} catch(Exception e){
e.printStackTrace();
}
In my text file, the word has 104 hits. but this is not finding the word. because it contain space in between. Kindly suggest something or edit in the code itself.
java text-files keyword-search wordsearch
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
Not even sure why you are doing it, why not just print the sentence that has"(Error: 87)"in it
– Scary Wombat
Nov 22 '18 at 5:02
UseIndexOffunction of string.
– NASSER
Nov 22 '18 at 5:16
add a comment |
0
0
0
I was trying to search this complete word "(Error: 87)" in my text file.
I used below java code.
String path = "C:\Temp\Error_Hunter";
String fileName = "\nvr-service.txt";
String testWord = "(Error: 87)";
int tLen = testWord.length();
int wordCntr = 0;
String file1 = path + fileName;
boolean check;
try{
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
//Read File Line By Line
while((strLine = br.readLine()) != null){
//check to see whether testWord occurs at least once in the line of text
check = strLine.toLowerCase().contains(testWord.toLowerCase());
if(check){
//get the line, and parse its words into a String array
String lineWords = strLine.split("\s+");
for(String w : lineWords)
{
if(w.length() >= tLen){
String word = w.substring(0,tLen).trim();
if(word.equalsIgnoreCase(testWord))
{
wordCntr++;
}
}
}
}
}
System.out.println("total is: " + wordCntr);
//Close the input stream
br.close();
} catch(Exception e){
e.printStackTrace();
}
In my text file, the word has 104 hits. but this is not finding the word. because it contain space in between. Kindly suggest something or edit in the code itself.
java text-files keyword-search wordsearch
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
I was trying to search this complete word "(Error: 87)" in my text file.
I used below java code.
String path = "C:\Temp\Error_Hunter";
String fileName = "\nvr-service.txt";
String testWord = "(Error: 87)";
int tLen = testWord.length();
int wordCntr = 0;
String file1 = path + fileName;
boolean check;
try{
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
//Read File Line By Line
while((strLine = br.readLine()) != null){
//check to see whether testWord occurs at least once in the line of text
check = strLine.toLowerCase().contains(testWord.toLowerCase());
if(check){
//get the line, and parse its words into a String array
String lineWords = strLine.split("\s+");
for(String w : lineWords)
{
if(w.length() >= tLen){
String word = w.substring(0,tLen).trim();
if(word.equalsIgnoreCase(testWord))
{
wordCntr++;
}
}
}
}
}
System.out.println("total is: " + wordCntr);
//Close the input stream
br.close();
} catch(Exception e){
e.printStackTrace();
}
In my text file, the word has 104 hits. but this is not finding the word. because it contain space in between. Kindly suggest something or edit in the code itself.
java text-files keyword-search wordsearch
java text-files keyword-search wordsearch
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
asked Nov 22 '18 at 4:56
kirubhaharankirubhaharan
31
31
You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
Not even sure why you are doing it, why not just print the sentence that has"(Error: 87)"in it
– Scary Wombat
Nov 22 '18 at 5:02
UseIndexOffunction of string.
– NASSER
Nov 22 '18 at 5:16
add a comment |
You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
Not even sure why you are doing it, why not just print the sentence that has"(Error: 87)"in it
– Scary Wombat
Nov 22 '18 at 5:02
UseIndexOffunction of string.
– NASSER
Nov 22 '18 at 5:16
You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
Not even sure why you are doing it, why not just print the sentence that has
"(Error: 87)" in it– Scary Wombat
Nov 22 '18 at 5:02
Not even sure why you are doing it, why not just print the sentence that has
"(Error: 87)" in it– Scary Wombat
Nov 22 '18 at 5:02
Use
IndexOf function of string.– NASSER
Nov 22 '18 at 5:16
Use
IndexOf function of string.– NASSER
Nov 22 '18 at 5:16
add a comment |
1 Answer
1
active
oldest
votes
1
Instead of
String lineWords = strLine.split("\s+");
do
String tokens = strLine.split("(Error: 87)");
And then the number of occurrences of (Error: 87) in that line would be tokens.length - 1.
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
add a comment |
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1 Answer
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active
oldest
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oldest
votes
active
oldest
votes
1
Instead of
String lineWords = strLine.split("\s+");
do
String tokens = strLine.split("(Error: 87)");
And then the number of occurrences of (Error: 87) in that line would be tokens.length - 1.
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
add a comment |
1
Instead of
String lineWords = strLine.split("\s+");
do
String tokens = strLine.split("(Error: 87)");
And then the number of occurrences of (Error: 87) in that line would be tokens.length - 1.
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
add a comment |
1
1
1
Instead of
String lineWords = strLine.split("\s+");
do
String tokens = strLine.split("(Error: 87)");
And then the number of occurrences of (Error: 87) in that line would be tokens.length - 1.
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
Instead of
String lineWords = strLine.split("\s+");
do
String tokens = strLine.split("(Error: 87)");
And then the number of occurrences of (Error: 87) in that line would be tokens.length - 1.
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
answered Nov 22 '18 at 5:05
KartikKartik
2,63031332
2,63031332
add a comment |
add a comment |
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You are splitting the line based upon spaces, so the word will never match another word that has a blank in it.
– Scary Wombat
Nov 22 '18 at 5:01
Not even sure why you are doing it, why not just print the sentence that has
"(Error: 87)"in it– Scary Wombat
Nov 22 '18 at 5:02
Use
IndexOffunction of string.– NASSER
Nov 22 '18 at 5:16