where does the array elements get stored when we use shift in javascript

-1

I tried array.shift() and array.unshift().
As a beginner in javascript I am not able to understand if use shift(), first array element will get removed but when we use unshift after shift from where does the removed element get added?

var temp = ['Five','Four','Three']

// temp.shift()

temp.unshift()

console.log(`we have ${temp}`)

This is a sample snippet

asked Nov 25 '18 at 13:50

Jitendra Koyande

Um...you probably left temp.shift() commented out.

– Zohir Salak
Nov 25 '18 at 14:28

add a comment |

-1

var temp = ['Five','Four','Three']

// temp.shift()

temp.unshift()

console.log(`we have ${temp}`)

This is a sample snippet

asked Nov 25 '18 at 13:50

Jitendra Koyande

Um...you probably left temp.shift() commented out.

– Zohir Salak
Nov 25 '18 at 14:28

add a comment |

-1

var temp = ['Five','Four','Three']

// temp.shift()

temp.unshift()

console.log(`we have ${temp}`)

This is a sample snippet

asked Nov 25 '18 at 13:50

Jitendra Koyande

var temp = ['Five','Four','Three']

// temp.shift()

temp.unshift()

console.log(`we have ${temp}`)

This is a sample snippet

javascript node.js

asked Nov 25 '18 at 13:50

Jitendra Koyande

asked Nov 25 '18 at 13:50

Jitendra Koyande

asked Nov 25 '18 at 13:50

Jitendra Koyande

asked Nov 25 '18 at 13:50

Jitendra Koyande

asked Nov 25 '18 at 13:50

Jitendra Koyande

Um...you probably left temp.shift() commented out.

– Zohir Salak
Nov 25 '18 at 14:28

add a comment |

Um...you probably left temp.shift() commented out.

– Zohir Salak
Nov 25 '18 at 14:28

Um...you probably left temp.shift() commented out.

– Zohir Salak
Nov 25 '18 at 14:28

add a comment |

1 Answer
1

active

oldest

votes

Array.unshift adds the element to first position in the array. Pls see below example.

Always better to read doc as well

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

Also, Array.shift removes first element from the array

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

UPDATE - Doing shift and unshift parallelly to show unshift() without passing any value does nothing.

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

1

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

|
show 1 more comment

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Array.unshift adds the element to first position in the array. Pls see below example.

Always better to read doc as well

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

Also, Array.shift removes first element from the array

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

UPDATE - Doing shift and unshift parallelly to show unshift() without passing any value does nothing.

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

1

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

|
show 1 more comment

Array.unshift adds the element to first position in the array. Pls see below example.

Always better to read doc as well

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

Also, Array.shift removes first element from the array

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

UPDATE - Doing shift and unshift parallelly to show unshift() without passing any value does nothing.

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

1

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

|
show 1 more comment

Array.unshift adds the element to first position in the array. Pls see below example.

Always better to read doc as well

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

Also, Array.shift removes first element from the array

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

UPDATE - Doing shift and unshift parallelly to show unshift() without passing any value does nothing.

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

Array.unshift adds the element to first position in the array. Pls see below example.

Always better to read doc as well

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

Also, Array.shift removes first element from the array

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

UPDATE - Doing shift and unshift parallelly to show unshift() without passing any value does nothing.

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

let arr = ['Five','Four','Three']



arr.unshift('add1')



console.log(arr)

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

let arr1 = ['Five','Four','Three']



arr1.shift()



console.log(arr1)

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

let arr1 = ['Five','Four','Three']



arr1.shift()



arr1.unshift()



console.log(arr1)

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

edited Nov 25 '18 at 14:20

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

answered Nov 25 '18 at 13:52

Nitish Narang

2,9601815

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

1

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

|
show 1 more comment

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

1

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

If i use shift first on array consisting 5 element it will remove first element. But after shift() If I call unshift() without any parameter it retrieves the removed element. My question is from where does it retrieve the deleted values?

– Jitendra Koyande
Nov 25 '18 at 14:15

It never happens. If you do unshift without passing any value.. it's sort of doing nothing.

– Nitish Narang
Nov 25 '18 at 14:18

So, when you say you do shift() and then unshift() your value comes back.. it doesn't happen.. I will update answer for you

– Nitish Narang
Nov 25 '18 at 14:18

@JitendraKoyande Updated

– Nitish Narang
Nov 25 '18 at 14:20

Got it. Thanks for the quick reply. @NishantNarang

– Jitendra Koyande
Nov 25 '18 at 14:27

|
show 1 more comment

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