Flattening a nested structure
Looks for wisdom on fixing this borrow-checker/lifetime issue in Rust. I'm trying to flatten a generic nested structure (into an impl Iterator or Vec). It's perhaps a few &s and `s away from working:
fn iter_els(prev_result: Vec<&El>) -> Vec<&El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child.clone());
}
result.extend(iter_els(&el.children));
}
result
}
You'll note that the immediate exception this raises is that iter_els expects a Vec of refs, not a ref itself. When addressing this directly, other issues rear their mischievous heads, as in a game of oxidized, but safe wack-a-mole.
Playground
rust
add a comment |
Looks for wisdom on fixing this borrow-checker/lifetime issue in Rust. I'm trying to flatten a generic nested structure (into an impl Iterator or Vec). It's perhaps a few &s and `s away from working:
fn iter_els(prev_result: Vec<&El>) -> Vec<&El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child.clone());
}
result.extend(iter_els(&el.children));
}
result
}
You'll note that the immediate exception this raises is that iter_els expects a Vec of refs, not a ref itself. When addressing this directly, other issues rear their mischievous heads, as in a game of oxidized, but safe wack-a-mole.
Playground
rust
add a comment |
Looks for wisdom on fixing this borrow-checker/lifetime issue in Rust. I'm trying to flatten a generic nested structure (into an impl Iterator or Vec). It's perhaps a few &s and `s away from working:
fn iter_els(prev_result: Vec<&El>) -> Vec<&El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child.clone());
}
result.extend(iter_els(&el.children));
}
result
}
You'll note that the immediate exception this raises is that iter_els expects a Vec of refs, not a ref itself. When addressing this directly, other issues rear their mischievous heads, as in a game of oxidized, but safe wack-a-mole.
Playground
rust
Looks for wisdom on fixing this borrow-checker/lifetime issue in Rust. I'm trying to flatten a generic nested structure (into an impl Iterator or Vec). It's perhaps a few &s and `s away from working:
fn iter_els(prev_result: Vec<&El>) -> Vec<&El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child.clone());
}
result.extend(iter_els(&el.children));
}
result
}
You'll note that the immediate exception this raises is that iter_els expects a Vec of refs, not a ref itself. When addressing this directly, other issues rear their mischievous heads, as in a game of oxidized, but safe wack-a-mole.
Playground
rust
rust
asked Nov 25 '18 at 13:20
Turtles Are CuteTurtles Are Cute
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1,06851829
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1 Answer
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There are various solutions to this task. One would be to pass the result as an out-parameter to the function:
fn iter_els<'el>(el_top: &'el El, result: &mut Vec<&'el El>) {
result.push(el_top);
for el in &el_top.children {
iter_els(el, result);
}
}
fn main() {
// build top_el as you did
let mut result = Vec::new();
iter_els(&top_el, &mut result);
println!("{:?}", result);
}
Adapting your original approach imho results in a more complex implementation:
fn iter_els<'el>(prev_result: &Vec<&'el El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child);
}
result.extend(iter_els(&el.children.iter().collect()));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![&top_el]));
}
Alternatively:
fn iter_els<'el>(prev_result: &'el Vec<El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result : Vec<_> = prev_result.iter().collect();
for el in prev_result {
for child in &el.children {
result.push(child);
}
result.extend(iter_els(&el.children));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![top_el]));
}
As you can see, the first approach only operates on an immutable El
, and one single result Vec
, while the other implementations do not get around clone
and collect
.
Ideally, you would write a custom Iterator
for your tree, but I think this could get quite cumbersome, because this iterator would have to keep track of the current state somehow (maybe can prove me wrong and show that it's actually easy to do).
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
There are various solutions to this task. One would be to pass the result as an out-parameter to the function:
fn iter_els<'el>(el_top: &'el El, result: &mut Vec<&'el El>) {
result.push(el_top);
for el in &el_top.children {
iter_els(el, result);
}
}
fn main() {
// build top_el as you did
let mut result = Vec::new();
iter_els(&top_el, &mut result);
println!("{:?}", result);
}
Adapting your original approach imho results in a more complex implementation:
fn iter_els<'el>(prev_result: &Vec<&'el El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child);
}
result.extend(iter_els(&el.children.iter().collect()));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![&top_el]));
}
Alternatively:
fn iter_els<'el>(prev_result: &'el Vec<El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result : Vec<_> = prev_result.iter().collect();
for el in prev_result {
for child in &el.children {
result.push(child);
}
result.extend(iter_els(&el.children));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![top_el]));
}
As you can see, the first approach only operates on an immutable El
, and one single result Vec
, while the other implementations do not get around clone
and collect
.
Ideally, you would write a custom Iterator
for your tree, but I think this could get quite cumbersome, because this iterator would have to keep track of the current state somehow (maybe can prove me wrong and show that it's actually easy to do).
add a comment |
There are various solutions to this task. One would be to pass the result as an out-parameter to the function:
fn iter_els<'el>(el_top: &'el El, result: &mut Vec<&'el El>) {
result.push(el_top);
for el in &el_top.children {
iter_els(el, result);
}
}
fn main() {
// build top_el as you did
let mut result = Vec::new();
iter_els(&top_el, &mut result);
println!("{:?}", result);
}
Adapting your original approach imho results in a more complex implementation:
fn iter_els<'el>(prev_result: &Vec<&'el El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child);
}
result.extend(iter_els(&el.children.iter().collect()));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![&top_el]));
}
Alternatively:
fn iter_els<'el>(prev_result: &'el Vec<El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result : Vec<_> = prev_result.iter().collect();
for el in prev_result {
for child in &el.children {
result.push(child);
}
result.extend(iter_els(&el.children));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![top_el]));
}
As you can see, the first approach only operates on an immutable El
, and one single result Vec
, while the other implementations do not get around clone
and collect
.
Ideally, you would write a custom Iterator
for your tree, but I think this could get quite cumbersome, because this iterator would have to keep track of the current state somehow (maybe can prove me wrong and show that it's actually easy to do).
add a comment |
There are various solutions to this task. One would be to pass the result as an out-parameter to the function:
fn iter_els<'el>(el_top: &'el El, result: &mut Vec<&'el El>) {
result.push(el_top);
for el in &el_top.children {
iter_els(el, result);
}
}
fn main() {
// build top_el as you did
let mut result = Vec::new();
iter_els(&top_el, &mut result);
println!("{:?}", result);
}
Adapting your original approach imho results in a more complex implementation:
fn iter_els<'el>(prev_result: &Vec<&'el El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child);
}
result.extend(iter_els(&el.children.iter().collect()));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![&top_el]));
}
Alternatively:
fn iter_els<'el>(prev_result: &'el Vec<El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result : Vec<_> = prev_result.iter().collect();
for el in prev_result {
for child in &el.children {
result.push(child);
}
result.extend(iter_els(&el.children));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![top_el]));
}
As you can see, the first approach only operates on an immutable El
, and one single result Vec
, while the other implementations do not get around clone
and collect
.
Ideally, you would write a custom Iterator
for your tree, but I think this could get quite cumbersome, because this iterator would have to keep track of the current state somehow (maybe can prove me wrong and show that it's actually easy to do).
There are various solutions to this task. One would be to pass the result as an out-parameter to the function:
fn iter_els<'el>(el_top: &'el El, result: &mut Vec<&'el El>) {
result.push(el_top);
for el in &el_top.children {
iter_els(el, result);
}
}
fn main() {
// build top_el as you did
let mut result = Vec::new();
iter_els(&top_el, &mut result);
println!("{:?}", result);
}
Adapting your original approach imho results in a more complex implementation:
fn iter_els<'el>(prev_result: &Vec<&'el El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result = prev_result.clone();
for el in prev_result {
for child in &el.children {
result.push(&child);
}
result.extend(iter_els(&el.children.iter().collect()));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![&top_el]));
}
Alternatively:
fn iter_els<'el>(prev_result: &'el Vec<El>) -> Vec<&'el El> {
// Iterate over all elements from a tree, starting at the top-level element.
let mut result : Vec<_> = prev_result.iter().collect();
for el in prev_result {
for child in &el.children {
result.push(child);
}
result.extend(iter_els(&el.children));
}
result
}
fn main() {
// build top_el as you did
println!("{:?}", iter_els(&vec![top_el]));
}
As you can see, the first approach only operates on an immutable El
, and one single result Vec
, while the other implementations do not get around clone
and collect
.
Ideally, you would write a custom Iterator
for your tree, but I think this could get quite cumbersome, because this iterator would have to keep track of the current state somehow (maybe can prove me wrong and show that it's actually easy to do).
edited Nov 25 '18 at 13:57
answered Nov 25 '18 at 13:39
phimuemuephimuemue
20.6k66298
20.6k66298
add a comment |
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