What is right way to design an component class with private properties in react native












0















Is there any recommended way to have private properties/Variables for the component and update the values in Constructor and use those properties throughout the components



Example:






export default class Workarea extends React.Component {

constructor(props) {
super(props);
MenuProps = this.props.navigation.getParam('MenuProps', {})
}

MenuProps= {};

getCurrentForm = () => {
if(MenuProps.Type == "Type1") {
this.RenderType1();
}
if(MenuProps.Type == "type2") {
this.RenderType2();
}
}

render() {
return (
<View>
{
this.getCurrentForm()
}
</View>
)
}
}





Is this the right way of doing class and property based approach.
Or i should always set the value and props to state please recommend.










share|improve this question





























    0















    Is there any recommended way to have private properties/Variables for the component and update the values in Constructor and use those properties throughout the components



    Example:






    export default class Workarea extends React.Component {

    constructor(props) {
    super(props);
    MenuProps = this.props.navigation.getParam('MenuProps', {})
    }

    MenuProps= {};

    getCurrentForm = () => {
    if(MenuProps.Type == "Type1") {
    this.RenderType1();
    }
    if(MenuProps.Type == "type2") {
    this.RenderType2();
    }
    }

    render() {
    return (
    <View>
    {
    this.getCurrentForm()
    }
    </View>
    )
    }
    }





    Is this the right way of doing class and property based approach.
    Or i should always set the value and props to state please recommend.










    share|improve this question



























      0












      0








      0








      Is there any recommended way to have private properties/Variables for the component and update the values in Constructor and use those properties throughout the components



      Example:






      export default class Workarea extends React.Component {

      constructor(props) {
      super(props);
      MenuProps = this.props.navigation.getParam('MenuProps', {})
      }

      MenuProps= {};

      getCurrentForm = () => {
      if(MenuProps.Type == "Type1") {
      this.RenderType1();
      }
      if(MenuProps.Type == "type2") {
      this.RenderType2();
      }
      }

      render() {
      return (
      <View>
      {
      this.getCurrentForm()
      }
      </View>
      )
      }
      }





      Is this the right way of doing class and property based approach.
      Or i should always set the value and props to state please recommend.










      share|improve this question
















      Is there any recommended way to have private properties/Variables for the component and update the values in Constructor and use those properties throughout the components



      Example:






      export default class Workarea extends React.Component {

      constructor(props) {
      super(props);
      MenuProps = this.props.navigation.getParam('MenuProps', {})
      }

      MenuProps= {};

      getCurrentForm = () => {
      if(MenuProps.Type == "Type1") {
      this.RenderType1();
      }
      if(MenuProps.Type == "type2") {
      this.RenderType2();
      }
      }

      render() {
      return (
      <View>
      {
      this.getCurrentForm()
      }
      </View>
      )
      }
      }





      Is this the right way of doing class and property based approach.
      Or i should always set the value and props to state please recommend.






      export default class Workarea extends React.Component {

      constructor(props) {
      super(props);
      MenuProps = this.props.navigation.getParam('MenuProps', {})
      }

      MenuProps= {};

      getCurrentForm = () => {
      if(MenuProps.Type == "Type1") {
      this.RenderType1();
      }
      if(MenuProps.Type == "type2") {
      this.RenderType2();
      }
      }

      render() {
      return (
      <View>
      {
      this.getCurrentForm()
      }
      </View>
      )
      }
      }





      export default class Workarea extends React.Component {

      constructor(props) {
      super(props);
      MenuProps = this.props.navigation.getParam('MenuProps', {})
      }

      MenuProps= {};

      getCurrentForm = () => {
      if(MenuProps.Type == "Type1") {
      this.RenderType1();
      }
      if(MenuProps.Type == "type2") {
      this.RenderType2();
      }
      }

      render() {
      return (
      <View>
      {
      this.getCurrentForm()
      }
      </View>
      )
      }
      }






      reactjs react-native






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 23 '18 at 9:35









      kivul

      487114




      487114










      asked Nov 23 '18 at 9:17









      GowthamanGowthaman

      231415




      231415
























          1 Answer
          1






          active

          oldest

          votes


















          0














          I ain't familiar with ReactNative, but es6 classes do not support private properties. The way to achieve them though, is to just declare the variable outside the class, but in the same file, like this:



              let _somePrivateProperty='hey';


          export default class Workarea extends React.Component {

          constructor(props) {
          super(props);
          MenuProps = this.props.navigation.getParam('MenuProps', {})
          }

          MenuProps= {};

          getCurrentForm = () => {
          if(MenuProps.Type == "Type1") {
          this.RenderType1();
          }
          if(MenuProps.Type == "type2") {
          this.RenderType2();
          }
          }

          render() {
          return (
          <div>
          <p>{_somePrivateProperty}</p>
          <View>
          {
          this.getCurrentForm()
          }
          </View>
          </div

          )
          }
          }


          Hope that this is what you meant.






          share|improve this answer
























          • if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

            – Gowthaman
            Nov 23 '18 at 10:51











          • I think so..Just try, and let me know :D. After all, this is just JS, React or not

            – sheff2k1
            Nov 23 '18 at 12:17











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          1 Answer
          1






          active

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          I ain't familiar with ReactNative, but es6 classes do not support private properties. The way to achieve them though, is to just declare the variable outside the class, but in the same file, like this:



              let _somePrivateProperty='hey';


          export default class Workarea extends React.Component {

          constructor(props) {
          super(props);
          MenuProps = this.props.navigation.getParam('MenuProps', {})
          }

          MenuProps= {};

          getCurrentForm = () => {
          if(MenuProps.Type == "Type1") {
          this.RenderType1();
          }
          if(MenuProps.Type == "type2") {
          this.RenderType2();
          }
          }

          render() {
          return (
          <div>
          <p>{_somePrivateProperty}</p>
          <View>
          {
          this.getCurrentForm()
          }
          </View>
          </div

          )
          }
          }


          Hope that this is what you meant.






          share|improve this answer
























          • if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

            – Gowthaman
            Nov 23 '18 at 10:51











          • I think so..Just try, and let me know :D. After all, this is just JS, React or not

            – sheff2k1
            Nov 23 '18 at 12:17
















          0














          I ain't familiar with ReactNative, but es6 classes do not support private properties. The way to achieve them though, is to just declare the variable outside the class, but in the same file, like this:



              let _somePrivateProperty='hey';


          export default class Workarea extends React.Component {

          constructor(props) {
          super(props);
          MenuProps = this.props.navigation.getParam('MenuProps', {})
          }

          MenuProps= {};

          getCurrentForm = () => {
          if(MenuProps.Type == "Type1") {
          this.RenderType1();
          }
          if(MenuProps.Type == "type2") {
          this.RenderType2();
          }
          }

          render() {
          return (
          <div>
          <p>{_somePrivateProperty}</p>
          <View>
          {
          this.getCurrentForm()
          }
          </View>
          </div

          )
          }
          }


          Hope that this is what you meant.






          share|improve this answer
























          • if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

            – Gowthaman
            Nov 23 '18 at 10:51











          • I think so..Just try, and let me know :D. After all, this is just JS, React or not

            – sheff2k1
            Nov 23 '18 at 12:17














          0












          0








          0







          I ain't familiar with ReactNative, but es6 classes do not support private properties. The way to achieve them though, is to just declare the variable outside the class, but in the same file, like this:



              let _somePrivateProperty='hey';


          export default class Workarea extends React.Component {

          constructor(props) {
          super(props);
          MenuProps = this.props.navigation.getParam('MenuProps', {})
          }

          MenuProps= {};

          getCurrentForm = () => {
          if(MenuProps.Type == "Type1") {
          this.RenderType1();
          }
          if(MenuProps.Type == "type2") {
          this.RenderType2();
          }
          }

          render() {
          return (
          <div>
          <p>{_somePrivateProperty}</p>
          <View>
          {
          this.getCurrentForm()
          }
          </View>
          </div

          )
          }
          }


          Hope that this is what you meant.






          share|improve this answer













          I ain't familiar with ReactNative, but es6 classes do not support private properties. The way to achieve them though, is to just declare the variable outside the class, but in the same file, like this:



              let _somePrivateProperty='hey';


          export default class Workarea extends React.Component {

          constructor(props) {
          super(props);
          MenuProps = this.props.navigation.getParam('MenuProps', {})
          }

          MenuProps= {};

          getCurrentForm = () => {
          if(MenuProps.Type == "Type1") {
          this.RenderType1();
          }
          if(MenuProps.Type == "type2") {
          this.RenderType2();
          }
          }

          render() {
          return (
          <div>
          <p>{_somePrivateProperty}</p>
          <View>
          {
          this.getCurrentForm()
          }
          </View>
          </div

          )
          }
          }


          Hope that this is what you meant.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 '18 at 9:59









          sheff2k1sheff2k1

          395212




          395212













          • if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

            – Gowthaman
            Nov 23 '18 at 10:51











          • I think so..Just try, and let me know :D. After all, this is just JS, React or not

            – sheff2k1
            Nov 23 '18 at 12:17



















          • if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

            – Gowthaman
            Nov 23 '18 at 10:51











          • I think so..Just try, and let me know :D. After all, this is just JS, React or not

            – sheff2k1
            Nov 23 '18 at 12:17

















          if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

          – Gowthaman
          Nov 23 '18 at 10:51





          if i declare the private properties outside the calls, Is it possible to set the value in the constructor.?

          – Gowthaman
          Nov 23 '18 at 10:51













          I think so..Just try, and let me know :D. After all, this is just JS, React or not

          – sheff2k1
          Nov 23 '18 at 12:17





          I think so..Just try, and let me know :D. After all, this is just JS, React or not

          – sheff2k1
          Nov 23 '18 at 12:17


















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