C++ constructor specialization using SFINAE












0















I have a templated struct whose member type depends on the specialization:



template<typename T>
struct Base
{
typedef T VT[4];
}

template<>
struct Base<float>
{
typedef ___m128 VT;
} // And other similar specializations for int, uint etc...

template<typename T>
struct A
{
typename A<T>::VT data;
}


I would like to specialize the copy constructor for pointer and non-pointer types:



// Non-pointer
A::A(const A & a) : data(a.data) { }

// Pointer
A::A(const A & a) { memcpy(data, a.data, sizeof(data)); }


I tried using a combination of std::enable_if and std::is_pointer but I cannot seem to make it work. Can someone show me how it's done?










share|improve this question























  • Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

    – Matthieu Brucher
    Nov 23 '18 at 9:09











  • @Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

    – Sneppy
    Nov 23 '18 at 9:11











  • Then perhaps share your trials so that we can figure out the issue with your constructor.

    – Matthieu Brucher
    Nov 23 '18 at 9:12











  • Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

    – Sneppy
    Nov 23 '18 at 9:17
















0















I have a templated struct whose member type depends on the specialization:



template<typename T>
struct Base
{
typedef T VT[4];
}

template<>
struct Base<float>
{
typedef ___m128 VT;
} // And other similar specializations for int, uint etc...

template<typename T>
struct A
{
typename A<T>::VT data;
}


I would like to specialize the copy constructor for pointer and non-pointer types:



// Non-pointer
A::A(const A & a) : data(a.data) { }

// Pointer
A::A(const A & a) { memcpy(data, a.data, sizeof(data)); }


I tried using a combination of std::enable_if and std::is_pointer but I cannot seem to make it work. Can someone show me how it's done?










share|improve this question























  • Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

    – Matthieu Brucher
    Nov 23 '18 at 9:09











  • @Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

    – Sneppy
    Nov 23 '18 at 9:11











  • Then perhaps share your trials so that we can figure out the issue with your constructor.

    – Matthieu Brucher
    Nov 23 '18 at 9:12











  • Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

    – Sneppy
    Nov 23 '18 at 9:17














0












0








0








I have a templated struct whose member type depends on the specialization:



template<typename T>
struct Base
{
typedef T VT[4];
}

template<>
struct Base<float>
{
typedef ___m128 VT;
} // And other similar specializations for int, uint etc...

template<typename T>
struct A
{
typename A<T>::VT data;
}


I would like to specialize the copy constructor for pointer and non-pointer types:



// Non-pointer
A::A(const A & a) : data(a.data) { }

// Pointer
A::A(const A & a) { memcpy(data, a.data, sizeof(data)); }


I tried using a combination of std::enable_if and std::is_pointer but I cannot seem to make it work. Can someone show me how it's done?










share|improve this question














I have a templated struct whose member type depends on the specialization:



template<typename T>
struct Base
{
typedef T VT[4];
}

template<>
struct Base<float>
{
typedef ___m128 VT;
} // And other similar specializations for int, uint etc...

template<typename T>
struct A
{
typename A<T>::VT data;
}


I would like to specialize the copy constructor for pointer and non-pointer types:



// Non-pointer
A::A(const A & a) : data(a.data) { }

// Pointer
A::A(const A & a) { memcpy(data, a.data, sizeof(data)); }


I tried using a combination of std::enable_if and std::is_pointer but I cannot seem to make it work. Can someone show me how it's done?







c++ templates constructor sfinae template-specialization






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 9:07









SneppySneppy

92211




92211













  • Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

    – Matthieu Brucher
    Nov 23 '18 at 9:09











  • @Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

    – Sneppy
    Nov 23 '18 at 9:11











  • Then perhaps share your trials so that we can figure out the issue with your constructor.

    – Matthieu Brucher
    Nov 23 '18 at 9:12











  • Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

    – Sneppy
    Nov 23 '18 at 9:17



















  • Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

    – Matthieu Brucher
    Nov 23 '18 at 9:09











  • @Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

    – Sneppy
    Nov 23 '18 at 9:11











  • Then perhaps share your trials so that we can figure out the issue with your constructor.

    – Matthieu Brucher
    Nov 23 '18 at 9:12











  • Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

    – Sneppy
    Nov 23 '18 at 9:17

















Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

– Matthieu Brucher
Nov 23 '18 at 9:09





Have a look at stackoverflow.com/questions/29430090/…, may be a duplicate.

– Matthieu Brucher
Nov 23 '18 at 9:09













@Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

– Sneppy
Nov 23 '18 at 9:11





@Matthieu I think I did (in the sense that I'm not sure whether I did that correctly or not) but the compiler gave me a redefined error on the constructor

– Sneppy
Nov 23 '18 at 9:11













Then perhaps share your trials so that we can figure out the issue with your constructor.

– Matthieu Brucher
Nov 23 '18 at 9:12





Then perhaps share your trials so that we can figure out the issue with your constructor.

– Matthieu Brucher
Nov 23 '18 at 9:12













Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

– Sneppy
Nov 23 '18 at 9:17





Ok sorry, I'll edit my question as soon as I get my hands on the computer. That link you posted talks about conditionally disabling the copy constructor, which is not what I want, but I'll give it a look to see if it applies to my case too

– Sneppy
Nov 23 '18 at 9:17












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