Sum the count of 3 nested for-each in XSLT












1















I have the following XSLT:



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.3ds.com/xsd/XPDMXML">
<xsl:output method="text" doctype-public="XSLT-compat" encoding="ISO-8859-1"/>
<xsl:template match="/">
<xsl:for-each select="/foo/bar/AAA[Owned/text()='1']">
<xsl:variable name="vOP">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/BBB[Owned[text()=$vOP]]">
<xsl:variable name="vTO">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/CCC[Owned[text()=$vTO]]">
<xsl:variable name="vIE">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:text>"COUNT": </xsl:text><xsl:value-of select="count(/foo/buzz/DDD[Owned[text()=$vIE]])"/><xsl:text>,</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>


This is a sample input



<?xml version='1.0' encoding='utf-8'?>
<foo>
<bar>
<AAA>
<Owned>1</Owned>
<Instancing>2</Instancing>
</AAA>
<BBB>
<Owned>2</Owned>
<Instancing>3</Instancing>
</BBB>
<CCC>
<Owned>3</Owned>
<Instancing>4</Instancing>
</CCC>
<CCC>
<Owned>3</Owned>
<Instancing>5</Instancing>
</CCC>
<CCC><Owned>4</Owned></CCC>
</bar>
<buzz>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>5</Owned></DDD>
<DDD><Owned>3</Owned></DDD>
<CCC><Owned>4</Owned></CCC>
</buzz>
</foo>


Is there a way to get the total value (SUM) of the latest value-of call? And possibly remove all the foreach ?



The output with that should be 3 (2 + 1).










share|improve this question




















  • 1





    Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

    – Martin Honnen
    Nov 23 '18 at 12:52











  • @MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

    – Thomas Ruiz
    Nov 23 '18 at 13:40











  • It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

    – Michael Kay
    Nov 23 '18 at 17:51
















1















I have the following XSLT:



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.3ds.com/xsd/XPDMXML">
<xsl:output method="text" doctype-public="XSLT-compat" encoding="ISO-8859-1"/>
<xsl:template match="/">
<xsl:for-each select="/foo/bar/AAA[Owned/text()='1']">
<xsl:variable name="vOP">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/BBB[Owned[text()=$vOP]]">
<xsl:variable name="vTO">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/CCC[Owned[text()=$vTO]]">
<xsl:variable name="vIE">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:text>"COUNT": </xsl:text><xsl:value-of select="count(/foo/buzz/DDD[Owned[text()=$vIE]])"/><xsl:text>,</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>


This is a sample input



<?xml version='1.0' encoding='utf-8'?>
<foo>
<bar>
<AAA>
<Owned>1</Owned>
<Instancing>2</Instancing>
</AAA>
<BBB>
<Owned>2</Owned>
<Instancing>3</Instancing>
</BBB>
<CCC>
<Owned>3</Owned>
<Instancing>4</Instancing>
</CCC>
<CCC>
<Owned>3</Owned>
<Instancing>5</Instancing>
</CCC>
<CCC><Owned>4</Owned></CCC>
</bar>
<buzz>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>5</Owned></DDD>
<DDD><Owned>3</Owned></DDD>
<CCC><Owned>4</Owned></CCC>
</buzz>
</foo>


Is there a way to get the total value (SUM) of the latest value-of call? And possibly remove all the foreach ?



The output with that should be 3 (2 + 1).










share|improve this question




















  • 1





    Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

    – Martin Honnen
    Nov 23 '18 at 12:52











  • @MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

    – Thomas Ruiz
    Nov 23 '18 at 13:40











  • It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

    – Michael Kay
    Nov 23 '18 at 17:51














1












1








1








I have the following XSLT:



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.3ds.com/xsd/XPDMXML">
<xsl:output method="text" doctype-public="XSLT-compat" encoding="ISO-8859-1"/>
<xsl:template match="/">
<xsl:for-each select="/foo/bar/AAA[Owned/text()='1']">
<xsl:variable name="vOP">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/BBB[Owned[text()=$vOP]]">
<xsl:variable name="vTO">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/CCC[Owned[text()=$vTO]]">
<xsl:variable name="vIE">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:text>"COUNT": </xsl:text><xsl:value-of select="count(/foo/buzz/DDD[Owned[text()=$vIE]])"/><xsl:text>,</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>


This is a sample input



<?xml version='1.0' encoding='utf-8'?>
<foo>
<bar>
<AAA>
<Owned>1</Owned>
<Instancing>2</Instancing>
</AAA>
<BBB>
<Owned>2</Owned>
<Instancing>3</Instancing>
</BBB>
<CCC>
<Owned>3</Owned>
<Instancing>4</Instancing>
</CCC>
<CCC>
<Owned>3</Owned>
<Instancing>5</Instancing>
</CCC>
<CCC><Owned>4</Owned></CCC>
</bar>
<buzz>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>5</Owned></DDD>
<DDD><Owned>3</Owned></DDD>
<CCC><Owned>4</Owned></CCC>
</buzz>
</foo>


Is there a way to get the total value (SUM) of the latest value-of call? And possibly remove all the foreach ?



The output with that should be 3 (2 + 1).










share|improve this question
















I have the following XSLT:



<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.3ds.com/xsd/XPDMXML">
<xsl:output method="text" doctype-public="XSLT-compat" encoding="ISO-8859-1"/>
<xsl:template match="/">
<xsl:for-each select="/foo/bar/AAA[Owned/text()='1']">
<xsl:variable name="vOP">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/BBB[Owned[text()=$vOP]]">
<xsl:variable name="vTO">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/CCC[Owned[text()=$vTO]]">
<xsl:variable name="vIE">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:text>"COUNT": </xsl:text><xsl:value-of select="count(/foo/buzz/DDD[Owned[text()=$vIE]])"/><xsl:text>,</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>


This is a sample input



<?xml version='1.0' encoding='utf-8'?>
<foo>
<bar>
<AAA>
<Owned>1</Owned>
<Instancing>2</Instancing>
</AAA>
<BBB>
<Owned>2</Owned>
<Instancing>3</Instancing>
</BBB>
<CCC>
<Owned>3</Owned>
<Instancing>4</Instancing>
</CCC>
<CCC>
<Owned>3</Owned>
<Instancing>5</Instancing>
</CCC>
<CCC><Owned>4</Owned></CCC>
</bar>
<buzz>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>5</Owned></DDD>
<DDD><Owned>3</Owned></DDD>
<CCC><Owned>4</Owned></CCC>
</buzz>
</foo>


Is there a way to get the total value (SUM) of the latest value-of call? And possibly remove all the foreach ?



The output with that should be 3 (2 + 1).







xslt xslt-1.0 xslt-2.0 xslt-grouping






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 13:38







Thomas Ruiz

















asked Nov 23 '18 at 11:46









Thomas RuizThomas Ruiz

3,13121428




3,13121428








  • 1





    Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

    – Martin Honnen
    Nov 23 '18 at 12:52











  • @MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

    – Thomas Ruiz
    Nov 23 '18 at 13:40











  • It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

    – Michael Kay
    Nov 23 '18 at 17:51














  • 1





    Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

    – Martin Honnen
    Nov 23 '18 at 12:52











  • @MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

    – Thomas Ruiz
    Nov 23 '18 at 13:40











  • It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

    – Michael Kay
    Nov 23 '18 at 17:51








1




1





Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

– Martin Honnen
Nov 23 '18 at 12:52





Can you show us a relevant minimal input sample and the corresponding result you get now plus the one you want? It seems you want to group items by Owned but don't use xsl:for-each-group. Not sure why. But in any case, if you want to accumulate values you can use sum on an adequately constructed sequence, so I guess you want to store the result of your grouping in a variable, probably with an XML structure, and then you can use sum on the relevant values you have in the variable.

– Martin Honnen
Nov 23 '18 at 12:52













@MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

– Thomas Ruiz
Nov 23 '18 at 13:40





@MartinHonnen I added some input to work with, and an expected output. I know the very basics of XSL, I'll look into for-each-group.

– Thomas Ruiz
Nov 23 '18 at 13:40













It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

– Michael Kay
Nov 23 '18 at 17:51





It's not the cause of your problem, but writing <xsl:variable name="vTO"><xsl:value-of select="./Instancing"/></xsl:variable> is verbose and inefficient when you could write <xsl:variable name="vTO" select="Instancing"/>

– Michael Kay
Nov 23 '18 at 17:51












1 Answer
1






active

oldest

votes


















2














You can store the result of the first computation in a variable and then sum up values from the variable (and output them:



<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>


As for doing it with more compact code, you can use keys to follow cross-references:



<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>

<xsl:key name="ref" match="bar/*" use="Owned"/>

<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

</xsl:stylesheet>


https://xsltfiddle.liberty-development.net/nc4NzRs/4



I don't know how variable your input data is, perhaps you will need different keys for the different child elements of bar, for your sample data the single key suffices.






share|improve this answer


























  • These solutions work flawlessly! Thank you so much!

    – Thomas Ruiz
    Nov 23 '18 at 14:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














You can store the result of the first computation in a variable and then sum up values from the variable (and output them:



<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>


As for doing it with more compact code, you can use keys to follow cross-references:



<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>

<xsl:key name="ref" match="bar/*" use="Owned"/>

<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

</xsl:stylesheet>


https://xsltfiddle.liberty-development.net/nc4NzRs/4



I don't know how variable your input data is, perhaps you will need different keys for the different child elements of bar, for your sample data the single key suffices.






share|improve this answer


























  • These solutions work flawlessly! Thank you so much!

    – Thomas Ruiz
    Nov 23 '18 at 14:53
















2














You can store the result of the first computation in a variable and then sum up values from the variable (and output them:



<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>


As for doing it with more compact code, you can use keys to follow cross-references:



<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>

<xsl:key name="ref" match="bar/*" use="Owned"/>

<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

</xsl:stylesheet>


https://xsltfiddle.liberty-development.net/nc4NzRs/4



I don't know how variable your input data is, perhaps you will need different keys for the different child elements of bar, for your sample data the single key suffices.






share|improve this answer


























  • These solutions work flawlessly! Thank you so much!

    – Thomas Ruiz
    Nov 23 '18 at 14:53














2












2








2







You can store the result of the first computation in a variable and then sum up values from the variable (and output them:



<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>


As for doing it with more compact code, you can use keys to follow cross-references:



<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>

<xsl:key name="ref" match="bar/*" use="Owned"/>

<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

</xsl:stylesheet>


https://xsltfiddle.liberty-development.net/nc4NzRs/4



I don't know how variable your input data is, perhaps you will need different keys for the different child elements of bar, for your sample data the single key suffices.






share|improve this answer















You can store the result of the first computation in a variable and then sum up values from the variable (and output them:



<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>


As for doing it with more compact code, you can use keys to follow cross-references:



<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>

<xsl:key name="ref" match="bar/*" use="Owned"/>

<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

</xsl:stylesheet>


https://xsltfiddle.liberty-development.net/nc4NzRs/4



I don't know how variable your input data is, perhaps you will need different keys for the different child elements of bar, for your sample data the single key suffices.







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edited Nov 23 '18 at 14:41

























answered Nov 23 '18 at 14:15









Martin HonnenMartin Honnen

111k65976




111k65976













  • These solutions work flawlessly! Thank you so much!

    – Thomas Ruiz
    Nov 23 '18 at 14:53



















  • These solutions work flawlessly! Thank you so much!

    – Thomas Ruiz
    Nov 23 '18 at 14:53

















These solutions work flawlessly! Thank you so much!

– Thomas Ruiz
Nov 23 '18 at 14:53





These solutions work flawlessly! Thank you so much!

– Thomas Ruiz
Nov 23 '18 at 14:53


















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