If the user enter “q”, program quits
I have this C++ code and I am trying to do the following:
Prompt the user to enter "p" to play or "q" to quit, if the user enters anything "p" the program will continue, if the user enters "q" program would just terminate and if they entered an invalid input, it would also terminate. How do I do that?.
Thank you,
Here is the code:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int Umain = 0;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
void displayOverview ();
void playOrQuit();
void promptNumber();
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
cout << "n";
for (Utemp = Umain; Utemp > 0; Utemp--)
{
cout << "Please enter a number: ";
cin >> Atemp;
Working = (Working + Atemp);
}
}while (Answer == 'y');
}
c++
asked Nov 20 at 22:30
Epic Dehaan
335
add a comment |
I have this C++ code and I am trying to do the following:
Prompt the user to enter "p" to play or "q" to quit, if the user enters anything "p" the program will continue, if the user enters "q" program would just terminate and if they entered an invalid input, it would also terminate. How do I do that?.
Thank you,
Here is the code:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int Umain = 0;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
void displayOverview ();
void playOrQuit();
void promptNumber();
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
cout << "n";
for (Utemp = Umain; Utemp > 0; Utemp--)
{
cout << "Please enter a number: ";
cin >> Atemp;
Working = (Working + Atemp);
}
}while (Answer == 'y');
}
c++
asked Nov 20 at 22:30
Epic Dehaan
335
3
And your question is?
– NathanOliver
Nov 20 at 22:30
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
ifvoid playOrQuit();wasbool playOrQuit();you couldif (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.
– user4581301
Nov 20 at 22:54
add a comment |
I have this C++ code and I am trying to do the following:
Prompt the user to enter "p" to play or "q" to quit, if the user enters anything "p" the program will continue, if the user enters "q" program would just terminate and if they entered an invalid input, it would also terminate. How do I do that?.
Thank you,
Here is the code:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int Umain = 0;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
void displayOverview ();
void playOrQuit();
void promptNumber();
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
cout << "n";
for (Utemp = Umain; Utemp > 0; Utemp--)
{
cout << "Please enter a number: ";
cin >> Atemp;
Working = (Working + Atemp);
}
}while (Answer == 'y');
}
c++
asked Nov 20 at 22:30
Epic Dehaan
335
I have this C++ code and I am trying to do the following:
Prompt the user to enter "p" to play or "q" to quit, if the user enters anything "p" the program will continue, if the user enters "q" program would just terminate and if they entered an invalid input, it would also terminate. How do I do that?.
Thank you,
Here is the code:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
int Umain = 0;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
void displayOverview ();
void playOrQuit();
void promptNumber();
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
cout << "n";
for (Utemp = Umain; Utemp > 0; Utemp--)
{
cout << "Please enter a number: ";
cin >> Atemp;
Working = (Working + Atemp);
}
}while (Answer == 'y');
}
c++
c++
asked Nov 20 at 22:30
Epic Dehaan
335
asked Nov 20 at 22:30
Epic Dehaan
335
edited Nov 20 at 22:32
asked Nov 20 at 22:30
Epic Dehaan
335
asked Nov 20 at 22:30
Epic Dehaan
335
asked Nov 20 at 22:30
Epic Dehaan
335
335
3
And your question is?
– NathanOliver
Nov 20 at 22:30
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
ifvoid playOrQuit();wasbool playOrQuit();you couldif (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.
– user4581301
Nov 20 at 22:54
add a comment |
3
And your question is?
– NathanOliver
Nov 20 at 22:30
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
ifvoid playOrQuit();wasbool playOrQuit();you couldif (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.
– user4581301
Nov 20 at 22:54
3
3
And your question is?
– NathanOliver
Nov 20 at 22:30
And your question is?
– NathanOliver
Nov 20 at 22:30
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
if
void playOrQuit(); was bool playOrQuit(); you could if (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.– user4581301
Nov 20 at 22:54
if
void playOrQuit(); was bool playOrQuit(); you could if (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.– user4581301
Nov 20 at 22:54
add a comment |
4 Answers
4
active
oldest
votes
Just add a call to exit after you detect 'q' was pressed:
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0); // <=== Add this here
Exiting with a 0 traditionally means the program exited in an expected fashion and without any errors.
answered Nov 20 at 22:37
xaxxon
14.3k43059
add a comment |
The usual way to do this kind of thing is to have PlayOrQuit return a bool with true meaning "keep on playing" and false meaning "quit". Use that function to control a loop:
while (PlayOrQuit()) {
// game logic goes here
}
That way you can put any appropriate cleanup code after the game loop instead of having a brute-force exit from down inside the function.
answered Nov 20 at 22:56
Pete Becker
56.9k440116
add a comment |
There are a couple of ways you can achieve this.
But I suggest you include the stdlib.h library and use system("exit") right inside your else statements that is meant to exit the program.
answered Nov 20 at 22:42
Beth
191
1
system("exit")is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.
– user4581301
Nov 20 at 22:52
add a comment |
Add end(), return 0 or exit(0).
Use u brain like, if you need this then i will remember nearest possible thing you spot from past.
So you never made these kind of mistake.
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}
answered Nov 20 at 23:58
Dusan Dusann
14
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just add a call to exit after you detect 'q' was pressed:
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0); // <=== Add this here
Exiting with a 0 traditionally means the program exited in an expected fashion and without any errors.
answered Nov 20 at 22:37
xaxxon
14.3k43059
add a comment |
Just add a call to exit after you detect 'q' was pressed:
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0); // <=== Add this here
Exiting with a 0 traditionally means the program exited in an expected fashion and without any errors.
answered Nov 20 at 22:37
xaxxon
14.3k43059
add a comment |
Just add a call to exit after you detect 'q' was pressed:
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0); // <=== Add this here
Exiting with a 0 traditionally means the program exited in an expected fashion and without any errors.
answered Nov 20 at 22:37
xaxxon
14.3k43059
Just add a call to exit after you detect 'q' was pressed:
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0); // <=== Add this here
Exiting with a 0 traditionally means the program exited in an expected fashion and without any errors.
answered Nov 20 at 22:37
xaxxon
14.3k43059
answered Nov 20 at 22:37
xaxxon
14.3k43059
answered Nov 20 at 22:37
xaxxon
14.3k43059
answered Nov 20 at 22:37
xaxxon
14.3k43059
14.3k43059
add a comment |
add a comment |
The usual way to do this kind of thing is to have PlayOrQuit return a bool with true meaning "keep on playing" and false meaning "quit". Use that function to control a loop:
while (PlayOrQuit()) {
// game logic goes here
}
That way you can put any appropriate cleanup code after the game loop instead of having a brute-force exit from down inside the function.
answered Nov 20 at 22:56
Pete Becker
56.9k440116
add a comment |
The usual way to do this kind of thing is to have PlayOrQuit return a bool with true meaning "keep on playing" and false meaning "quit". Use that function to control a loop:
while (PlayOrQuit()) {
// game logic goes here
}
That way you can put any appropriate cleanup code after the game loop instead of having a brute-force exit from down inside the function.
answered Nov 20 at 22:56
Pete Becker
56.9k440116
add a comment |
The usual way to do this kind of thing is to have PlayOrQuit return a bool with true meaning "keep on playing" and false meaning "quit". Use that function to control a loop:
while (PlayOrQuit()) {
// game logic goes here
}
That way you can put any appropriate cleanup code after the game loop instead of having a brute-force exit from down inside the function.
answered Nov 20 at 22:56
Pete Becker
56.9k440116
The usual way to do this kind of thing is to have PlayOrQuit return a bool with true meaning "keep on playing" and false meaning "quit". Use that function to control a loop:
while (PlayOrQuit()) {
// game logic goes here
}
That way you can put any appropriate cleanup code after the game loop instead of having a brute-force exit from down inside the function.
answered Nov 20 at 22:56
Pete Becker
56.9k440116
answered Nov 20 at 22:56
Pete Becker
56.9k440116
answered Nov 20 at 22:56
Pete Becker
56.9k440116
answered Nov 20 at 22:56
Pete Becker
56.9k440116
56.9k440116
add a comment |
add a comment |
There are a couple of ways you can achieve this.
But I suggest you include the stdlib.h library and use system("exit") right inside your else statements that is meant to exit the program.
answered Nov 20 at 22:42
Beth
191
1
system("exit")is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.
– user4581301
Nov 20 at 22:52
add a comment |
There are a couple of ways you can achieve this.
But I suggest you include the stdlib.h library and use system("exit") right inside your else statements that is meant to exit the program.
answered Nov 20 at 22:42
Beth
191
1
system("exit")is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.
– user4581301
Nov 20 at 22:52
add a comment |
There are a couple of ways you can achieve this.
But I suggest you include the stdlib.h library and use system("exit") right inside your else statements that is meant to exit the program.
answered Nov 20 at 22:42
Beth
191
There are a couple of ways you can achieve this.
But I suggest you include the stdlib.h library and use system("exit") right inside your else statements that is meant to exit the program.
answered Nov 20 at 22:42
Beth
191
answered Nov 20 at 22:42
Beth
191
answered Nov 20 at 22:42
Beth
191
answered Nov 20 at 22:42
Beth
191
191
1
system("exit")is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.
– user4581301
Nov 20 at 22:52
add a comment |
1
system("exit")is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.
– user4581301
Nov 20 at 22:52
1
1
system("exit") is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.– user4581301
Nov 20 at 22:52
system("exit") is quite a bit heavier in weight than you want or need and lacks portability. It is starting another process to call the exit ms-dos command which will end the program with all the subtlety if a headsman's axe.– user4581301
Nov 20 at 22:52
add a comment |
Add end(), return 0 or exit(0).
Use u brain like, if you need this then i will remember nearest possible thing you spot from past.
So you never made these kind of mistake.
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}
answered Nov 20 at 23:58
Dusan Dusann
14
add a comment |
Add end(), return 0 or exit(0).
Use u brain like, if you need this then i will remember nearest possible thing you spot from past.
So you never made these kind of mistake.
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}
answered Nov 20 at 23:58
Dusan Dusann
14
add a comment |
Add end(), return 0 or exit(0).
Use u brain like, if you need this then i will remember nearest possible thing you spot from past.
So you never made these kind of mistake.
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}
answered Nov 20 at 23:58
Dusan Dusann
14
Add end(), return 0 or exit(0).
Use u brain like, if you need this then i will remember nearest possible thing you spot from past.
So you never made these kind of mistake.
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}
answered Nov 20 at 23:58
Dusan Dusann
14
answered Nov 20 at 23:58
Dusan Dusann
14
answered Nov 20 at 23:58
Dusan Dusann
14
answered Nov 20 at 23:58
Dusan Dusann
14
14
add a comment |
add a comment |
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3
And your question is?
– NathanOliver
Nov 20 at 22:30
Please don't tag your questions in the title - that's what the actual tags are for
– xaxxon
Nov 20 at 22:31
@NathanOliver How do I do it?
– Epic Dehaan
Nov 20 at 22:33
if
void playOrQuit();wasbool playOrQuit();you couldif (!playOrQuit()) { return 0; }. You're going to want t loop in main or the whole idea is moot.– user4581301
Nov 20 at 22:54