Powershell Dynamic Menu Based on Mailbox Permission Entries
I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.
Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}
$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}
The next function uses the output of the previous to build the menu.
Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}
The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.
powershell
edited Nov 22 '18 at 14:05
Robert
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
add a comment |
I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.
Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}
$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}
The next function uses the output of the previous to build the menu.
Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}
The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.
powershell
edited Nov 22 '18 at 14:05
Robert
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
Try$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
– Theo
Nov 22 '18 at 14:11
add a comment |
I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.
Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}
$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}
The next function uses the output of the previous to build the menu.
Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}
The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.
powershell
edited Nov 22 '18 at 14:05
Robert
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
I'm having trouble with creating a dynamic menu from mailbox permission entries in PowerShell. The below function gets a list of permission entries for the selected mailbox and outputs a table.
Function AuditSingleMailboxPermission($mbox) {
If ($mbox -like $null){
Write-Host "Please select the mailbox from the list below"
$mbox = SelectMailbox
}
$mboxPermissions = Get-MailboxPermission $mbox | where {$_.User -like "*@*"}
Return $mboxPermissions
}
The next function uses the output of the previous to build the menu.
Function SelectMailboxPermission($mbox) {
$rights = (AuditSingleMailboxPermission -mbox $mbox).User
Write-Host $rights
$menu = @{}
for ($i=1;$i -le $rights.count; $i++) {
Write-Host "$i. $($rights[$i-1])"
$menu.Add($i,($rights[$i-1]))
}
[int]$ans = Read-Host "Enter selection"
$selection = $menu.Item($ans)
Return $selection
}
The Write-Host $rights line shows the full username. However, the menu only returns the first letter of the username. This is a problem because the output of this function is used to remove user permissions on a mailbox. I can't figure this out for the life of me.
powershell
powershell
edited Nov 22 '18 at 14:05
Robert
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
edited Nov 22 '18 at 14:05
Robert
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
edited Nov 22 '18 at 14:05
Robert
4,0571252106
edited Nov 22 '18 at 14:05
Robert
4,0571252106
edited Nov 22 '18 at 14:05
Robert
4,0571252106
4,0571252106
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
asked Nov 22 '18 at 13:59
OhSnapWordOhSnapWord
102
102
Try$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
– Theo
Nov 22 '18 at 14:11
add a comment |
Try$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there
– Theo
Nov 22 '18 at 14:11
Try
$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there– Theo
Nov 22 '18 at 14:11
Try
$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there– Theo
Nov 22 '18 at 14:11
add a comment |
1 Answer
1
active
oldest
votes
If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.
Casting to Array should fix the issue:
$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User
Generic example:
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of@(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 '18 at 20:20
add a comment |
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If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.
Casting to Array should fix the issue:
$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User
Generic example:
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of@(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 '18 at 20:20
add a comment |
If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.
Casting to Array should fix the issue:
$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User
Generic example:
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of@(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 '18 at 20:20
add a comment |
If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.
Casting to Array should fix the issue:
$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User
Generic example:
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
If (AuditSingleMailboxPermission -mbox $mbox).User returns only one item, it will return a single object, not an array with length of one. Then, when you refer to $rights[0] it won't return the first object of an array, but the first character of the String representation of the object.
Casting to Array should fix the issue:
$rights = [Array](AuditSingleMailboxPermission -mbox $mbox).User
Generic example:
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 1)[0]
F
PS C:> ("FOO", "BAR", "BAZ" | Select-Object -First 2)[0]
FOO
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
edited Nov 22 '18 at 14:36
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
answered Nov 22 '18 at 14:31
Janne TuukkanenJanne Tuukkanen
1,125210
1,125210
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of@(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 '18 at 20:20
add a comment |
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of@(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.
– mklement0
Nov 22 '18 at 20:20
1
1
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use
@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.– mklement0
Nov 22 '18 at 20:20
+1 for the explanation and an effective solution, but the PowerShell-idiomatic solution would be to use
@(AuditSingleMailboxPermission -mbox $mbox).User, i.e., use of @(...), the array-subexpression operator, which guarantees that a command's output is treated as an array, if it isn't already one.– mklement0
Nov 22 '18 at 20:20
add a comment |
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Try
$menu.Add($i,$($rights[$i-1])). I think you forgot the dollar sign there– Theo
Nov 22 '18 at 14:11