typescript how to rewrite property type of interface












1















type Old = Other & {rewrite:number};
type New = Old & {rewrite:string};


Exected behavior:

type of New: Other & {rewrite:string}



Actual behavior:

type of New: Other & {rewrite:string & number}










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    1















    type Old = Other & {rewrite:number};
    type New = Old & {rewrite:string};


    Exected behavior:

    type of New: Other & {rewrite:string}



    Actual behavior:

    type of New: Other & {rewrite:string & number}










    share|improve this question

























      1












      1








      1








      type Old = Other & {rewrite:number};
      type New = Old & {rewrite:string};


      Exected behavior:

      type of New: Other & {rewrite:string}



      Actual behavior:

      type of New: Other & {rewrite:string & number}










      share|improve this question














      type Old = Other & {rewrite:number};
      type New = Old & {rewrite:string};


      Exected behavior:

      type of New: Other & {rewrite:string}



      Actual behavior:

      type of New: Other & {rewrite:string & number}







      typescript






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 22 '18 at 14:02









      s97712s97712

      256




      256
























          1 Answer
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          3














          This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.



          To replace a property, we can first exclude it from the original type using Pick and Exclude:



          type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

          type Other = { a: number };
          type Old = Other & {rewrite:number};
          type New = Omit<Old, 'rewrite'> & {rewrite:string};
          let n: New;
          n.rewrite // string
          n.a // number


          We can ecen create a generic type to do the replacement if this is a common scenario:



          type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

          type Other = { a: number };
          type Old = Other & {rewrite:number, rewrite2:number};
          type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
          type New = Replace<Old, 'rewrite', string> // replace one
          type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more





          share|improve this answer























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            1 Answer
            1






            active

            oldest

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            active

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            active

            oldest

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            3














            This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.



            To replace a property, we can first exclude it from the original type using Pick and Exclude:



            type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

            type Other = { a: number };
            type Old = Other & {rewrite:number};
            type New = Omit<Old, 'rewrite'> & {rewrite:string};
            let n: New;
            n.rewrite // string
            n.a // number


            We can ecen create a generic type to do the replacement if this is a common scenario:



            type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

            type Other = { a: number };
            type Old = Other & {rewrite:number, rewrite2:number};
            type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
            type New = Replace<Old, 'rewrite', string> // replace one
            type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more





            share|improve this answer




























              3














              This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.



              To replace a property, we can first exclude it from the original type using Pick and Exclude:



              type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

              type Other = { a: number };
              type Old = Other & {rewrite:number};
              type New = Omit<Old, 'rewrite'> & {rewrite:string};
              let n: New;
              n.rewrite // string
              n.a // number


              We can ecen create a generic type to do the replacement if this is a common scenario:



              type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

              type Other = { a: number };
              type Old = Other & {rewrite:number, rewrite2:number};
              type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
              type New = Replace<Old, 'rewrite', string> // replace one
              type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more





              share|improve this answer


























                3












                3








                3







                This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.



                To replace a property, we can first exclude it from the original type using Pick and Exclude:



                type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

                type Other = { a: number };
                type Old = Other & {rewrite:number};
                type New = Omit<Old, 'rewrite'> & {rewrite:string};
                let n: New;
                n.rewrite // string
                n.a // number


                We can ecen create a generic type to do the replacement if this is a common scenario:



                type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

                type Other = { a: number };
                type Old = Other & {rewrite:number, rewrite2:number};
                type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
                type New = Replace<Old, 'rewrite', string> // replace one
                type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more





                share|improve this answer













                This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.



                To replace a property, we can first exclude it from the original type using Pick and Exclude:



                type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

                type Other = { a: number };
                type Old = Other & {rewrite:number};
                type New = Omit<Old, 'rewrite'> & {rewrite:string};
                let n: New;
                n.rewrite // string
                n.a // number


                We can ecen create a generic type to do the replacement if this is a common scenario:



                type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>

                type Other = { a: number };
                type Old = Other & {rewrite:number, rewrite2:number};
                type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
                type New = Replace<Old, 'rewrite', string> // replace one
                type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more






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                share|improve this answer










                answered Nov 22 '18 at 14:09









                Titian Cernicova-DragomirTitian Cernicova-Dragomir

                60k33553




                60k33553






























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