typescript how to rewrite property type of interface
type Old = Other & {rewrite:number};
type New = Old & {rewrite:string};
Exected behavior:
type of New
: Other & {rewrite:string}
Actual behavior:
type of New
: Other & {rewrite:string & number}
typescript
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type Old = Other & {rewrite:number};
type New = Old & {rewrite:string};
Exected behavior:
type of New
: Other & {rewrite:string}
Actual behavior:
type of New
: Other & {rewrite:string & number}
typescript
add a comment |
type Old = Other & {rewrite:number};
type New = Old & {rewrite:string};
Exected behavior:
type of New
: Other & {rewrite:string}
Actual behavior:
type of New
: Other & {rewrite:string & number}
typescript
type Old = Other & {rewrite:number};
type New = Old & {rewrite:string};
Exected behavior:
type of New
: Other & {rewrite:string}
Actual behavior:
type of New
: Other & {rewrite:string & number}
typescript
typescript
asked Nov 22 '18 at 14:02
s97712s97712
256
256
add a comment |
add a comment |
1 Answer
1
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votes
This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.
To replace a property, we can first exclude it from the original type using Pick
and Exclude
:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number};
type New = Omit<Old, 'rewrite'> & {rewrite:string};
let n: New;
n.rewrite // string
n.a // number
We can ecen create a generic type to do the replacement if this is a common scenario:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number, rewrite2:number};
type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
type New = Replace<Old, 'rewrite', string> // replace one
type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.
To replace a property, we can first exclude it from the original type using Pick
and Exclude
:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number};
type New = Omit<Old, 'rewrite'> & {rewrite:string};
let n: New;
n.rewrite // string
n.a // number
We can ecen create a generic type to do the replacement if this is a common scenario:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number, rewrite2:number};
type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
type New = Replace<Old, 'rewrite', string> // replace one
type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more
add a comment |
This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.
To replace a property, we can first exclude it from the original type using Pick
and Exclude
:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number};
type New = Omit<Old, 'rewrite'> & {rewrite:string};
let n: New;
n.rewrite // string
n.a // number
We can ecen create a generic type to do the replacement if this is a common scenario:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number, rewrite2:number};
type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
type New = Replace<Old, 'rewrite', string> // replace one
type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more
add a comment |
This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.
To replace a property, we can first exclude it from the original type using Pick
and Exclude
:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number};
type New = Omit<Old, 'rewrite'> & {rewrite:string};
let n: New;
n.rewrite // string
n.a // number
We can ecen create a generic type to do the replacement if this is a common scenario:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number, rewrite2:number};
type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
type New = Replace<Old, 'rewrite', string> // replace one
type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more
This is the by design behavior of intersection types. If the property exists on both members of the intersection the resulting property type will be an intersection of the original types.
To replace a property, we can first exclude it from the original type using Pick
and Exclude
:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number};
type New = Omit<Old, 'rewrite'> & {rewrite:string};
let n: New;
n.rewrite // string
n.a // number
We can ecen create a generic type to do the replacement if this is a common scenario:
type Omit<T, TKey extends keyof T> = Pick<T, Exclude<keyof T, TKey>>
type Other = { a: number };
type Old = Other & {rewrite:number, rewrite2:number};
type Replace<T, TKey extends keyof T, TKeyType> = Omit<T, TKey> & Record<TKey, TKeyType>
type New = Replace<Old, 'rewrite', string> // replace one
type New2 = Replace<Old, 'rewrite' | 'rewrite2', string> // replace more
answered Nov 22 '18 at 14:09
Titian Cernicova-DragomirTitian Cernicova-Dragomir
60k33553
60k33553
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