Intersect in JpaRepository












0














I have SQL query like below. I'd like to take the common product_id,authorization_ids for certain merchantIds.
In this example merchant 20000 has product1,authorization1 and product2, authorization1 whereas the other merchants only have product1, authorization1.



SELECT product_id,authorization_id  FROM ACQ_MERCHANT_PRODUCT_AUTH  WHERE merchant_Id = 20000
Intersect
SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20001
Intersect
SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20002


The query above gives the right result which is product1, authorization1.
I am trying to implement that in jpa:



@Repository
public interface MerchantProductAuthorizationRepository extends
JpaRepository<MerchantProductAuthorizationEntity, Long> {

@Query("SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY m.product.id, m.authorization.id")
List<ProductAuthMap> findIntersactionOfProductAndAuthorizations(@Param("merchants") Set<Long> merchants);

}


But this gives me more lines than the intersect. ( product1, authorization1 and product2, authorization2)



How do I get the same result?










share|improve this question





























    0














    I have SQL query like below. I'd like to take the common product_id,authorization_ids for certain merchantIds.
    In this example merchant 20000 has product1,authorization1 and product2, authorization1 whereas the other merchants only have product1, authorization1.



    SELECT product_id,authorization_id  FROM ACQ_MERCHANT_PRODUCT_AUTH  WHERE merchant_Id = 20000
    Intersect
    SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20001
    Intersect
    SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20002


    The query above gives the right result which is product1, authorization1.
    I am trying to implement that in jpa:



    @Repository
    public interface MerchantProductAuthorizationRepository extends
    JpaRepository<MerchantProductAuthorizationEntity, Long> {

    @Query("SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY m.product.id, m.authorization.id")
    List<ProductAuthMap> findIntersactionOfProductAndAuthorizations(@Param("merchants") Set<Long> merchants);

    }


    But this gives me more lines than the intersect. ( product1, authorization1 and product2, authorization2)



    How do I get the same result?










    share|improve this question



























      0












      0








      0







      I have SQL query like below. I'd like to take the common product_id,authorization_ids for certain merchantIds.
      In this example merchant 20000 has product1,authorization1 and product2, authorization1 whereas the other merchants only have product1, authorization1.



      SELECT product_id,authorization_id  FROM ACQ_MERCHANT_PRODUCT_AUTH  WHERE merchant_Id = 20000
      Intersect
      SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20001
      Intersect
      SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20002


      The query above gives the right result which is product1, authorization1.
      I am trying to implement that in jpa:



      @Repository
      public interface MerchantProductAuthorizationRepository extends
      JpaRepository<MerchantProductAuthorizationEntity, Long> {

      @Query("SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY m.product.id, m.authorization.id")
      List<ProductAuthMap> findIntersactionOfProductAndAuthorizations(@Param("merchants") Set<Long> merchants);

      }


      But this gives me more lines than the intersect. ( product1, authorization1 and product2, authorization2)



      How do I get the same result?










      share|improve this question















      I have SQL query like below. I'd like to take the common product_id,authorization_ids for certain merchantIds.
      In this example merchant 20000 has product1,authorization1 and product2, authorization1 whereas the other merchants only have product1, authorization1.



      SELECT product_id,authorization_id  FROM ACQ_MERCHANT_PRODUCT_AUTH  WHERE merchant_Id = 20000
      Intersect
      SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20001
      Intersect
      SELECT product_id,authorization_id FROM ACQ_MERCHANT_PRODUCT_AUTH WHERE merchant_Id = 20002


      The query above gives the right result which is product1, authorization1.
      I am trying to implement that in jpa:



      @Repository
      public interface MerchantProductAuthorizationRepository extends
      JpaRepository<MerchantProductAuthorizationEntity, Long> {

      @Query("SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY m.product.id, m.authorization.id")
      List<ProductAuthMap> findIntersactionOfProductAndAuthorizations(@Param("merchants") Set<Long> merchants);

      }


      But this gives me more lines than the intersect. ( product1, authorization1 and product2, authorization2)



      How do I get the same result?







      spring spring-data-jpa jpql






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 '18 at 7:52









      Billy Frost

      1,74598




      1,74598










      asked Nov 21 '18 at 20:38









      EgeEge

      4161928




      4161928
























          1 Answer
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          0














          Your HQL not had intersect logic by merchantIds. In this, I count merchant_id groupped by (m.product.id, m.authorization.id) and if the count is equal the merchants count, then this pair(m.product.id, m.authorization.id) is in all merchant's Set.



          SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY  m.product.id, m.authorization.id having count(distinct m.merchantId) =:merchantsCount





          share|improve this answer





















          • This worked thanks :)
            – Ege
            Nov 22 '18 at 6:44











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Your HQL not had intersect logic by merchantIds. In this, I count merchant_id groupped by (m.product.id, m.authorization.id) and if the count is equal the merchants count, then this pair(m.product.id, m.authorization.id) is in all merchant's Set.



          SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY  m.product.id, m.authorization.id having count(distinct m.merchantId) =:merchantsCount





          share|improve this answer





















          • This worked thanks :)
            – Ege
            Nov 22 '18 at 6:44
















          0














          Your HQL not had intersect logic by merchantIds. In this, I count merchant_id groupped by (m.product.id, m.authorization.id) and if the count is equal the merchants count, then this pair(m.product.id, m.authorization.id) is in all merchant's Set.



          SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY  m.product.id, m.authorization.id having count(distinct m.merchantId) =:merchantsCount





          share|improve this answer





















          • This worked thanks :)
            – Ege
            Nov 22 '18 at 6:44














          0












          0








          0






          Your HQL not had intersect logic by merchantIds. In this, I count merchant_id groupped by (m.product.id, m.authorization.id) and if the count is equal the merchants count, then this pair(m.product.id, m.authorization.id) is in all merchant's Set.



          SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY  m.product.id, m.authorization.id having count(distinct m.merchantId) =:merchantsCount





          share|improve this answer












          Your HQL not had intersect logic by merchantIds. In this, I count merchant_id groupped by (m.product.id, m.authorization.id) and if the count is equal the merchants count, then this pair(m.product.id, m.authorization.id) is in all merchant's Set.



          SELECT new com.ykb.acq.application.sweep.util.ProductAuthMap(m.product.id, m.authorization.id) FROM MerchantProductAuthorizationEntity m WHERE m.merchantId IN (:merchants) GROUP BY  m.product.id, m.authorization.id having count(distinct m.merchantId) =:merchantsCount






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 21 '18 at 21:22









          László TóthLászló Tóth

          765




          765












          • This worked thanks :)
            – Ege
            Nov 22 '18 at 6:44


















          • This worked thanks :)
            – Ege
            Nov 22 '18 at 6:44
















          This worked thanks :)
          – Ege
          Nov 22 '18 at 6:44




          This worked thanks :)
          – Ege
          Nov 22 '18 at 6:44


















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