Django middleware process view after done with return render template continue to regular page
I created a custom django middleware,
class CustomMiddleware(object):
def process_view(self, request, view_func, *view_args, **view_kwargs):
...
...
return render(request, 'accounts/xyz_form.html', {})
Now in xyz_form.html
there is a form which on submit action goes to url which call the view and view save the form data. Now after the form data is saved how can that form disappear after the view complete its execution and continue with its normal execution.
So what url should I pass in urls.py to call that view and on calling view the middleware gets exit.
django django-views django-urls django-middleware
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I created a custom django middleware,
class CustomMiddleware(object):
def process_view(self, request, view_func, *view_args, **view_kwargs):
...
...
return render(request, 'accounts/xyz_form.html', {})
Now in xyz_form.html
there is a form which on submit action goes to url which call the view and view save the form data. Now after the form data is saved how can that form disappear after the view complete its execution and continue with its normal execution.
So what url should I pass in urls.py to call that view and on calling view the middleware gets exit.
django django-views django-urls django-middleware
add a comment |
I created a custom django middleware,
class CustomMiddleware(object):
def process_view(self, request, view_func, *view_args, **view_kwargs):
...
...
return render(request, 'accounts/xyz_form.html', {})
Now in xyz_form.html
there is a form which on submit action goes to url which call the view and view save the form data. Now after the form data is saved how can that form disappear after the view complete its execution and continue with its normal execution.
So what url should I pass in urls.py to call that view and on calling view the middleware gets exit.
django django-views django-urls django-middleware
I created a custom django middleware,
class CustomMiddleware(object):
def process_view(self, request, view_func, *view_args, **view_kwargs):
...
...
return render(request, 'accounts/xyz_form.html', {})
Now in xyz_form.html
there is a form which on submit action goes to url which call the view and view save the form data. Now after the form data is saved how can that form disappear after the view complete its execution and continue with its normal execution.
So what url should I pass in urls.py to call that view and on calling view the middleware gets exit.
django django-views django-urls django-middleware
django django-views django-urls django-middleware
edited Nov 22 '18 at 9:43
ruddra
12.7k32648
12.7k32648
asked Nov 22 '18 at 9:31
aakash singhaakash singh
437
437
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1 Answer
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If you want to disappear the form, you can use javascript to hide it or you can redirect page to another page where you want to continue with other code stuff. You can also go back to the home page with the following URL.
url(r'^$', views.index, name='index')
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want to disappear the form, you can use javascript to hide it or you can redirect page to another page where you want to continue with other code stuff. You can also go back to the home page with the following URL.
url(r'^$', views.index, name='index')
add a comment |
If you want to disappear the form, you can use javascript to hide it or you can redirect page to another page where you want to continue with other code stuff. You can also go back to the home page with the following URL.
url(r'^$', views.index, name='index')
add a comment |
If you want to disappear the form, you can use javascript to hide it or you can redirect page to another page where you want to continue with other code stuff. You can also go back to the home page with the following URL.
url(r'^$', views.index, name='index')
If you want to disappear the form, you can use javascript to hide it or you can redirect page to another page where you want to continue with other code stuff. You can also go back to the home page with the following URL.
url(r'^$', views.index, name='index')
answered Nov 22 '18 at 9:56
Naveen KumarNaveen Kumar
11
11
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