Array of Linked Lists into one list in C
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I am trying to get all integer in an array of linked lists to form into one linked list. I am getting run time error and I think its from this function stitchBuckets. Am I suppose to use double pointer or triple for buckets??
void stitchBuckets(Node *buckets, Node **head)
{
for(int i = 9; i > -1; --i)
{
Node *currentNode = (buckets[i]);
Node *nextNode;
while(currentNode != NULL)
{
nextNode = currentNode->next;
insertNode(head,currentNode->num);
free(currentNode);//freeing linked list in bucket
currentNode = nextNode;
}
}
}
c++ c linked-list
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up vote
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I am trying to get all integer in an array of linked lists to form into one linked list. I am getting run time error and I think its from this function stitchBuckets. Am I suppose to use double pointer or triple for buckets??
void stitchBuckets(Node *buckets, Node **head)
{
for(int i = 9; i > -1; --i)
{
Node *currentNode = (buckets[i]);
Node *nextNode;
while(currentNode != NULL)
{
nextNode = currentNode->next;
insertNode(head,currentNode->num);
free(currentNode);//freeing linked list in bucket
currentNode = nextNode;
}
}
}
c++ c linked-list
New contributor
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am trying to get all integer in an array of linked lists to form into one linked list. I am getting run time error and I think its from this function stitchBuckets. Am I suppose to use double pointer or triple for buckets??
void stitchBuckets(Node *buckets, Node **head)
{
for(int i = 9; i > -1; --i)
{
Node *currentNode = (buckets[i]);
Node *nextNode;
while(currentNode != NULL)
{
nextNode = currentNode->next;
insertNode(head,currentNode->num);
free(currentNode);//freeing linked list in bucket
currentNode = nextNode;
}
}
}
c++ c linked-list
New contributor
I am trying to get all integer in an array of linked lists to form into one linked list. I am getting run time error and I think its from this function stitchBuckets. Am I suppose to use double pointer or triple for buckets??
void stitchBuckets(Node *buckets, Node **head)
{
for(int i = 9; i > -1; --i)
{
Node *currentNode = (buckets[i]);
Node *nextNode;
while(currentNode != NULL)
{
nextNode = currentNode->next;
insertNode(head,currentNode->num);
free(currentNode);//freeing linked list in bucket
currentNode = nextNode;
}
}
}
c++ c linked-list
c++ c linked-list
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