What makes game 5 of the World Championship a draw?











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I was watching recently the excellent ChessNetwork commentary of the 5th game of the WCC 2018 between Magnus Carlsen and Fabiano Caruana. The end position is the following:





[FEN "8/5R2/5bp1/3rpk1p/8/4B2P/5PP1/5K2 w - - 0 1"]


There is not much to grip onto on either side for sure, but it doesn't strike me as a draw either. The line I get with Stockfish is not straight forward.



{ [Stockfish 280218 64 POPCNT] 68:+0.00} 1...Ke6 2.Ra7 Rd6 3.Ke2 
hxg4 4.hxg4 Rc6 5.f3 Bd8 6.Rg7 Kf6 7.Rg8 Bb6 8.Bh6 Rd6 9.Rf8+ Ke6 10.
Re8+ Kd5 11.Be3 Bd8 12.f4 exf4 13.Bxf4 Re6+ 14.Rxe6 Kxe6 15.Kd3 Kd5
16.Ke3 Be7 17.Kd3 Bb4 18.Ke3 Bc5+ 19.Kf3 Be7 20.Be3 Bd8 21.Bf4 Be7


Is there any simple explanation why this position appears as an obvious draw other than a lack of goals to pursue on both sides?










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    I was watching recently the excellent ChessNetwork commentary of the 5th game of the WCC 2018 between Magnus Carlsen and Fabiano Caruana. The end position is the following:





    [FEN "8/5R2/5bp1/3rpk1p/8/4B2P/5PP1/5K2 w - - 0 1"]


    There is not much to grip onto on either side for sure, but it doesn't strike me as a draw either. The line I get with Stockfish is not straight forward.



    { [Stockfish 280218 64 POPCNT] 68:+0.00} 1...Ke6 2.Ra7 Rd6 3.Ke2 
    hxg4 4.hxg4 Rc6 5.f3 Bd8 6.Rg7 Kf6 7.Rg8 Bb6 8.Bh6 Rd6 9.Rf8+ Ke6 10.
    Re8+ Kd5 11.Be3 Bd8 12.f4 exf4 13.Bxf4 Re6+ 14.Rxe6 Kxe6 15.Kd3 Kd5
    16.Ke3 Be7 17.Kd3 Bb4 18.Ke3 Bc5+ 19.Kf3 Be7 20.Be3 Bd8 21.Bf4 Be7


    Is there any simple explanation why this position appears as an obvious draw other than a lack of goals to pursue on both sides?










    share|improve this question
























      up vote
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      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I was watching recently the excellent ChessNetwork commentary of the 5th game of the WCC 2018 between Magnus Carlsen and Fabiano Caruana. The end position is the following:





      [FEN "8/5R2/5bp1/3rpk1p/8/4B2P/5PP1/5K2 w - - 0 1"]


      There is not much to grip onto on either side for sure, but it doesn't strike me as a draw either. The line I get with Stockfish is not straight forward.



      { [Stockfish 280218 64 POPCNT] 68:+0.00} 1...Ke6 2.Ra7 Rd6 3.Ke2 
      hxg4 4.hxg4 Rc6 5.f3 Bd8 6.Rg7 Kf6 7.Rg8 Bb6 8.Bh6 Rd6 9.Rf8+ Ke6 10.
      Re8+ Kd5 11.Be3 Bd8 12.f4 exf4 13.Bxf4 Re6+ 14.Rxe6 Kxe6 15.Kd3 Kd5
      16.Ke3 Be7 17.Kd3 Bb4 18.Ke3 Bc5+ 19.Kf3 Be7 20.Be3 Bd8 21.Bf4 Be7


      Is there any simple explanation why this position appears as an obvious draw other than a lack of goals to pursue on both sides?










      share|improve this question













      I was watching recently the excellent ChessNetwork commentary of the 5th game of the WCC 2018 between Magnus Carlsen and Fabiano Caruana. The end position is the following:





      [FEN "8/5R2/5bp1/3rpk1p/8/4B2P/5PP1/5K2 w - - 0 1"]


      There is not much to grip onto on either side for sure, but it doesn't strike me as a draw either. The line I get with Stockfish is not straight forward.



      { [Stockfish 280218 64 POPCNT] 68:+0.00} 1...Ke6 2.Ra7 Rd6 3.Ke2 
      hxg4 4.hxg4 Rc6 5.f3 Bd8 6.Rg7 Kf6 7.Rg8 Bb6 8.Bh6 Rd6 9.Rf8+ Ke6 10.
      Re8+ Kd5 11.Be3 Bd8 12.f4 exf4 13.Bxf4 Re6+ 14.Rxe6 Kxe6 15.Kd3 Kd5
      16.Ke3 Be7 17.Kd3 Bb4 18.Ke3 Bc5+ 19.Kf3 Be7 20.Be3 Bd8 21.Bf4 Be7


      Is there any simple explanation why this position appears as an obvious draw other than a lack of goals to pursue on both sides?







      draw world-championship






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      asked 9 hours ago









      Jacques Gaudin

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      20829






















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          Computer engines are of little use in positions like this. Still it is a pretty obvious draw, because of:




          • equal (and very limited) material

          • pawns on the same side of the board

          • no weaknesses for either player

          • active and safe kings


          In order to win this, one would have to win material or promote a pawn, neither of which can be forced.






          share|improve this answer




























            up vote
            3
            down vote













            Some points to consider:




            • No passed pawn

            • All rook endgames with equal number of pawns in its own half are drawn (I do not know if this is a theorem, but it is almost a theorem).

            • One of the players can probably force exchange of bishops and get it to rook endgame with equal number of pawns.

            • Both players are 2800+ and it is a classical game, so enough time to think and make the right moves.


            EDIT: You can look at the game discussed here, where one side has Rook along with 'a' and 'c' pawns, while the other side just has a rook and the game is still a draw.






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              2 Answers
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              up vote
              3
              down vote













              Computer engines are of little use in positions like this. Still it is a pretty obvious draw, because of:




              • equal (and very limited) material

              • pawns on the same side of the board

              • no weaknesses for either player

              • active and safe kings


              In order to win this, one would have to win material or promote a pawn, neither of which can be forced.






              share|improve this answer

























                up vote
                3
                down vote













                Computer engines are of little use in positions like this. Still it is a pretty obvious draw, because of:




                • equal (and very limited) material

                • pawns on the same side of the board

                • no weaknesses for either player

                • active and safe kings


                In order to win this, one would have to win material or promote a pawn, neither of which can be forced.






                share|improve this answer























                  up vote
                  3
                  down vote










                  up vote
                  3
                  down vote









                  Computer engines are of little use in positions like this. Still it is a pretty obvious draw, because of:




                  • equal (and very limited) material

                  • pawns on the same side of the board

                  • no weaknesses for either player

                  • active and safe kings


                  In order to win this, one would have to win material or promote a pawn, neither of which can be forced.






                  share|improve this answer












                  Computer engines are of little use in positions like this. Still it is a pretty obvious draw, because of:




                  • equal (and very limited) material

                  • pawns on the same side of the board

                  • no weaknesses for either player

                  • active and safe kings


                  In order to win this, one would have to win material or promote a pawn, neither of which can be forced.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 9 hours ago









                  user1583209

                  11.4k11452




                  11.4k11452






















                      up vote
                      3
                      down vote













                      Some points to consider:




                      • No passed pawn

                      • All rook endgames with equal number of pawns in its own half are drawn (I do not know if this is a theorem, but it is almost a theorem).

                      • One of the players can probably force exchange of bishops and get it to rook endgame with equal number of pawns.

                      • Both players are 2800+ and it is a classical game, so enough time to think and make the right moves.


                      EDIT: You can look at the game discussed here, where one side has Rook along with 'a' and 'c' pawns, while the other side just has a rook and the game is still a draw.






                      share|improve this answer



























                        up vote
                        3
                        down vote













                        Some points to consider:




                        • No passed pawn

                        • All rook endgames with equal number of pawns in its own half are drawn (I do not know if this is a theorem, but it is almost a theorem).

                        • One of the players can probably force exchange of bishops and get it to rook endgame with equal number of pawns.

                        • Both players are 2800+ and it is a classical game, so enough time to think and make the right moves.


                        EDIT: You can look at the game discussed here, where one side has Rook along with 'a' and 'c' pawns, while the other side just has a rook and the game is still a draw.






                        share|improve this answer

























                          up vote
                          3
                          down vote










                          up vote
                          3
                          down vote









                          Some points to consider:




                          • No passed pawn

                          • All rook endgames with equal number of pawns in its own half are drawn (I do not know if this is a theorem, but it is almost a theorem).

                          • One of the players can probably force exchange of bishops and get it to rook endgame with equal number of pawns.

                          • Both players are 2800+ and it is a classical game, so enough time to think and make the right moves.


                          EDIT: You can look at the game discussed here, where one side has Rook along with 'a' and 'c' pawns, while the other side just has a rook and the game is still a draw.






                          share|improve this answer














                          Some points to consider:




                          • No passed pawn

                          • All rook endgames with equal number of pawns in its own half are drawn (I do not know if this is a theorem, but it is almost a theorem).

                          • One of the players can probably force exchange of bishops and get it to rook endgame with equal number of pawns.

                          • Both players are 2800+ and it is a classical game, so enough time to think and make the right moves.


                          EDIT: You can look at the game discussed here, where one side has Rook along with 'a' and 'c' pawns, while the other side just has a rook and the game is still a draw.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 2 hours ago

























                          answered 2 hours ago









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