iterate through a list of numbers and break when one of the numbers is not consecutive
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0
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m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
asked 27 mins ago
Big girl
1
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Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
0
down vote
favorite
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
asked 27 mins ago
Big girl
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
asked 27 mins ago
Big girl
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
python-3.x
asked 27 mins ago
Big girl
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 27 mins ago
Big girl
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 27 mins ago
Big girl
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 27 mins ago
Big girl
1
asked 27 mins ago
Big girl
1
1
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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Big girl is a new contributor. Be nice, and check out our Code of Conduct.
Big girl is a new contributor. Be nice, and check out our Code of Conduct.
Big girl is a new contributor. Be nice, and check out our Code of Conduct.
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