PostgreSQL using variables












0














If I have a query like this:



SELECT COUNT(1) FILTER (WHERE type = 0) as first_sum,
COUNT(1) FILTER (WHERE type = 0) as second_sum,
first_sum + second_sum as final_sum
FROM ...


Is it possible to use some kind of variables to make this work?










share|improve this question
























  • How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
    – Hambone
    Nov 21 '18 at 19:28


















0














If I have a query like this:



SELECT COUNT(1) FILTER (WHERE type = 0) as first_sum,
COUNT(1) FILTER (WHERE type = 0) as second_sum,
first_sum + second_sum as final_sum
FROM ...


Is it possible to use some kind of variables to make this work?










share|improve this question
























  • How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
    – Hambone
    Nov 21 '18 at 19:28
















0












0








0







If I have a query like this:



SELECT COUNT(1) FILTER (WHERE type = 0) as first_sum,
COUNT(1) FILTER (WHERE type = 0) as second_sum,
first_sum + second_sum as final_sum
FROM ...


Is it possible to use some kind of variables to make this work?










share|improve this question















If I have a query like this:



SELECT COUNT(1) FILTER (WHERE type = 0) as first_sum,
COUNT(1) FILTER (WHERE type = 0) as second_sum,
first_sum + second_sum as final_sum
FROM ...


Is it possible to use some kind of variables to make this work?







sql postgresql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 19:29









Laurenz Albe

44.4k102746




44.4k102746










asked Nov 21 '18 at 18:45









sudoman281sudoman281

18212




18212












  • How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
    – Hambone
    Nov 21 '18 at 19:28




















  • How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
    – Hambone
    Nov 21 '18 at 19:28


















How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
– Hambone
Nov 21 '18 at 19:28






How about COUNT(1) FILTER (WHERE type = 0) + COUNT(1) FILTER (WHERE type = 0)? Of course this will result in a null if either argument is null. Your example has them both with the same criteria, but presumably that's not what you meant
– Hambone
Nov 21 '18 at 19:28














1 Answer
1






active

oldest

votes


















1














Yes, that is perfectly possible, the technique is called “subquery”:



SELECT first_sum,
second_sum,
first_sum + second_sum AS final_sum
FROM (SELECT count(*) FILTER (WHERE type = 0) AS first_sum,
count(*) FILTER (WHERE type = 0) AS second_sum
FROM ...
) AS subq;





share|improve this answer





















  • Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
    – sudoman281
    Nov 21 '18 at 19:37











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418689%2fpostgresql-using-variables%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Yes, that is perfectly possible, the technique is called “subquery”:



SELECT first_sum,
second_sum,
first_sum + second_sum AS final_sum
FROM (SELECT count(*) FILTER (WHERE type = 0) AS first_sum,
count(*) FILTER (WHERE type = 0) AS second_sum
FROM ...
) AS subq;





share|improve this answer





















  • Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
    – sudoman281
    Nov 21 '18 at 19:37
















1














Yes, that is perfectly possible, the technique is called “subquery”:



SELECT first_sum,
second_sum,
first_sum + second_sum AS final_sum
FROM (SELECT count(*) FILTER (WHERE type = 0) AS first_sum,
count(*) FILTER (WHERE type = 0) AS second_sum
FROM ...
) AS subq;





share|improve this answer





















  • Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
    – sudoman281
    Nov 21 '18 at 19:37














1












1








1






Yes, that is perfectly possible, the technique is called “subquery”:



SELECT first_sum,
second_sum,
first_sum + second_sum AS final_sum
FROM (SELECT count(*) FILTER (WHERE type = 0) AS first_sum,
count(*) FILTER (WHERE type = 0) AS second_sum
FROM ...
) AS subq;





share|improve this answer












Yes, that is perfectly possible, the technique is called “subquery”:



SELECT first_sum,
second_sum,
first_sum + second_sum AS final_sum
FROM (SELECT count(*) FILTER (WHERE type = 0) AS first_sum,
count(*) FILTER (WHERE type = 0) AS second_sum
FROM ...
) AS subq;






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 21 '18 at 19:28









Laurenz AlbeLaurenz Albe

44.4k102746




44.4k102746












  • Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
    – sudoman281
    Nov 21 '18 at 19:37


















  • Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
    – sudoman281
    Nov 21 '18 at 19:37
















Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
– sudoman281
Nov 21 '18 at 19:37




Ok thanks! That's what I thought. :) I was just wondering if there is any other (better) way.
– sudoman281
Nov 21 '18 at 19:37


















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53418689%2fpostgresql-using-variables%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

404 Error Contact Form 7 ajax form submitting

How to know if a Active Directory user can login interactively

TypeError: fit_transform() missing 1 required positional argument: 'X'