See if a specific resource exists in a kubernetes namespace
$begingroup$
So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).
from kubernetes import client, config
config.load_kube_config()
client = client.AppsV1Api()
try:
client.read_namespaced_deployment("deployment_name", "default")
return True
except ApiException as e:
if e.status == 404:
return False
Is there a way to achieve the same without relying on the ApiException explicitly?
python exception
asked 6 mins ago
user3079474user3079474
1335
$endgroup$
add a comment |
$begingroup$
So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).
from kubernetes import client, config
config.load_kube_config()
client = client.AppsV1Api()
try:
client.read_namespaced_deployment("deployment_name", "default")
return True
except ApiException as e:
if e.status == 404:
return False
Is there a way to achieve the same without relying on the ApiException explicitly?
python exception
asked 6 mins ago
user3079474user3079474
1335
$endgroup$
add a comment |
$begingroup$
So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).
from kubernetes import client, config
config.load_kube_config()
client = client.AppsV1Api()
try:
client.read_namespaced_deployment("deployment_name", "default")
return True
except ApiException as e:
if e.status == 404:
return False
Is there a way to achieve the same without relying on the ApiException explicitly?
python exception
asked 6 mins ago
user3079474user3079474
1335
$endgroup$
So I want to have a function that checks to see if a certain resource (deployment, job, cronjob etc) exist in a namespace. Using the kubernetes python client, I can create a boolean function (using deployments as a concrete example).
from kubernetes import client, config
config.load_kube_config()
client = client.AppsV1Api()
try:
client.read_namespaced_deployment("deployment_name", "default")
return True
except ApiException as e:
if e.status == 404:
return False
Is there a way to achieve the same without relying on the ApiException explicitly?
python exception
python exception
asked 6 mins ago
user3079474user3079474
1335
asked 6 mins ago
user3079474user3079474
1335
asked 6 mins ago
user3079474user3079474
1335
asked 6 mins ago
user3079474user3079474
1335
asked 6 mins ago
user3079474user3079474
1335
1335
add a comment |
add a comment |
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