Is using mixin with no parameter is more efficient than using extend












0















I have gone through many articles online and totally got confused.
Could someone clarify on below



Is using mixin with no parameter is more efficient than using extend










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  • Are you using SASS?

    – Mav
    Nov 24 '18 at 3:45











  • yes.We are using SAAS.

    – user3190467
    Nov 24 '18 at 4:15
















0















I have gone through many articles online and totally got confused.
Could someone clarify on below



Is using mixin with no parameter is more efficient than using extend










share|improve this question























  • Are you using SASS?

    – Mav
    Nov 24 '18 at 3:45











  • yes.We are using SAAS.

    – user3190467
    Nov 24 '18 at 4:15














0












0








0








I have gone through many articles online and totally got confused.
Could someone clarify on below



Is using mixin with no parameter is more efficient than using extend










share|improve this question














I have gone through many articles online and totally got confused.
Could someone clarify on below



Is using mixin with no parameter is more efficient than using extend







html5 css3






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 3:23









user3190467user3190467

43




43













  • Are you using SASS?

    – Mav
    Nov 24 '18 at 3:45











  • yes.We are using SAAS.

    – user3190467
    Nov 24 '18 at 4:15



















  • Are you using SASS?

    – Mav
    Nov 24 '18 at 3:45











  • yes.We are using SAAS.

    – user3190467
    Nov 24 '18 at 4:15

















Are you using SASS?

– Mav
Nov 24 '18 at 3:45





Are you using SASS?

– Mav
Nov 24 '18 at 3:45













yes.We are using SAAS.

– user3190467
Nov 24 '18 at 4:15





yes.We are using SAAS.

– user3190467
Nov 24 '18 at 4:15












1 Answer
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oldest

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0














Extending a class will add the styles just once, and add all the selectors that the style needs to be applied to alongside where it's defined. A mixin on the other hand, will copy the styles individually to each selector where you've included it.



Here's what I mean.



Mixin



@mixin mixin(){
color: blue;
}

.selector-1{
@include mixin();
}

.selector-2{
@include mixin();
}


Compiles to



.selector-1 {
color: blue;
}
.selector-2 {
color: blue;
}




Extending a class



.extend{
color: blue;
}

.selector-1{
@extend .extend;
}

.selector-2{
@extend .extend;
}


Compiles to



.extend, .selector-1, .selector-2 {
color: blue;
}


So in terms of efficiency, extending a class will result in a smaller compiled file size, which is why Sass offers the extend feature in the first place.






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    Extending a class will add the styles just once, and add all the selectors that the style needs to be applied to alongside where it's defined. A mixin on the other hand, will copy the styles individually to each selector where you've included it.



    Here's what I mean.



    Mixin



    @mixin mixin(){
    color: blue;
    }

    .selector-1{
    @include mixin();
    }

    .selector-2{
    @include mixin();
    }


    Compiles to



    .selector-1 {
    color: blue;
    }
    .selector-2 {
    color: blue;
    }




    Extending a class



    .extend{
    color: blue;
    }

    .selector-1{
    @extend .extend;
    }

    .selector-2{
    @extend .extend;
    }


    Compiles to



    .extend, .selector-1, .selector-2 {
    color: blue;
    }


    So in terms of efficiency, extending a class will result in a smaller compiled file size, which is why Sass offers the extend feature in the first place.






    share|improve this answer




























      0














      Extending a class will add the styles just once, and add all the selectors that the style needs to be applied to alongside where it's defined. A mixin on the other hand, will copy the styles individually to each selector where you've included it.



      Here's what I mean.



      Mixin



      @mixin mixin(){
      color: blue;
      }

      .selector-1{
      @include mixin();
      }

      .selector-2{
      @include mixin();
      }


      Compiles to



      .selector-1 {
      color: blue;
      }
      .selector-2 {
      color: blue;
      }




      Extending a class



      .extend{
      color: blue;
      }

      .selector-1{
      @extend .extend;
      }

      .selector-2{
      @extend .extend;
      }


      Compiles to



      .extend, .selector-1, .selector-2 {
      color: blue;
      }


      So in terms of efficiency, extending a class will result in a smaller compiled file size, which is why Sass offers the extend feature in the first place.






      share|improve this answer


























        0












        0








        0







        Extending a class will add the styles just once, and add all the selectors that the style needs to be applied to alongside where it's defined. A mixin on the other hand, will copy the styles individually to each selector where you've included it.



        Here's what I mean.



        Mixin



        @mixin mixin(){
        color: blue;
        }

        .selector-1{
        @include mixin();
        }

        .selector-2{
        @include mixin();
        }


        Compiles to



        .selector-1 {
        color: blue;
        }
        .selector-2 {
        color: blue;
        }




        Extending a class



        .extend{
        color: blue;
        }

        .selector-1{
        @extend .extend;
        }

        .selector-2{
        @extend .extend;
        }


        Compiles to



        .extend, .selector-1, .selector-2 {
        color: blue;
        }


        So in terms of efficiency, extending a class will result in a smaller compiled file size, which is why Sass offers the extend feature in the first place.






        share|improve this answer













        Extending a class will add the styles just once, and add all the selectors that the style needs to be applied to alongside where it's defined. A mixin on the other hand, will copy the styles individually to each selector where you've included it.



        Here's what I mean.



        Mixin



        @mixin mixin(){
        color: blue;
        }

        .selector-1{
        @include mixin();
        }

        .selector-2{
        @include mixin();
        }


        Compiles to



        .selector-1 {
        color: blue;
        }
        .selector-2 {
        color: blue;
        }




        Extending a class



        .extend{
        color: blue;
        }

        .selector-1{
        @extend .extend;
        }

        .selector-2{
        @extend .extend;
        }


        Compiles to



        .extend, .selector-1, .selector-2 {
        color: blue;
        }


        So in terms of efficiency, extending a class will result in a smaller compiled file size, which is why Sass offers the extend feature in the first place.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 24 '18 at 5:05









        MavMav

        554520




        554520
































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